(-136)x23+(-136)x17+40x36
Bài 1:Giải các bất phương trình sau:
a)(x+3)(1-x)>0
b)(2x-1)(x+3)<0
c)(x2+1)(x-2)(x+2) ≥ 0
d)(3-2x)(x+5)(x-3) ≤ 0
f)(x2-4x-5)(x+2) ≥ 0
Giúp mk vs!!
Lát nx nộp r:>
Tính nhanh: a) 136 x 2 + 136 x 7 + 136 ............................................................... ................................................................ ................................................................ ............................................................... b) 3465 x 9 x (72 - 8 x 9) ................................................................ ................................................................ ........................................................
a) = 136 x 2 + 136 x 7 + 136 x 1
= 136 x ( 2 + 7 + 1 )
= 136 x 10
= 1360
b) = 3465 x 9 x 0
= 0
a) = 136 x 2 + 136 x 7 + 136 x 1
= 136 x ( 2 + 7 + 1 )
= 136 x 10
= 1360
b) = 3465 x 9 x 0
= 0
136*34+36*136+30*136 hãy tính
136*34+36*136+30*136
=136*(34+36+30)
=136*100
=13600
794 + [ 136 - ( 136 + 794 ) ]
136 . 23 + 136 . 17 – 40 . 36
= 136 . ( 23 + 17 ) - 40 .36
= 136 . 40 - 40 . 36
= 40. ( 136 - 36 )
= 40. 100 = 4000
136 . 23 + 136 . 17 – 40 . 36
= 3128 + 2312 - 1440
= 4000
(-136)-(136-13)bằng bao nhiêu
\(\sqrt{19+\sqrt{136}}-\sqrt{19-\sqrt{136}}\)
\(\sqrt{19+\sqrt{136}}-\sqrt{19-\sqrt{136}}=\sqrt{17+2\sqrt{17.2}+2}-\sqrt{17-2\sqrt{17.2}+2}\)
\(=\sqrt{\left(\sqrt{17}+\sqrt{2}\right)^2}-\sqrt{\left(\sqrt{17}-\sqrt{2}\right)^2}=\sqrt{17}+\sqrt{2}-\sqrt{17}+\sqrt{2}\)
\(=2\sqrt{2}\)
Tính hợp lí:
-136 . (64-95) - 64 . (-95-136)
\(-136\cdot(64-95)-64\cdot(-95-136)\\=-136\cdot64+(-136)\cdot(-95)+(-64)\cdot(-95)+(-64)\cdot(-136)\\=-136\cdot64+136\cdot95+64\cdot95+64\cdot136\\=(-136\cdot64+64\cdot136)+(136\cdot95+64\cdot95)\\=0+95\cdot(136+64)\\=95\cdot200\\=19000\)
136*25+75*136-6^2*10^2
Tính hợp lí 136 mũ 2 -92×136+46 mũ 2
1362 − 92.136 + 462
= 1362 − 2.46.136 + 462
=(136−46)2
=902
=8100