Theo đề ta có:

\(5.3^{3x+2}-27^{x+1}=486\)

\(\Rightarrow5.27^x.9-27^x.27=486\)

\(\Rightarrow27^x\left(45-27\right)=486\)

\(\Rightarrow27^x.18=486\)

\(\Rightarrow27^x=\frac{486}{18}\)

\(\Rightarrow27^x=27\)

\(\Rightarrow27^x=27^1\)

\(\Rightarrow x=1\)

vậy \(x=1\)

Bài 1 :

a) 7^2x-1 = 343

=> 7^2x-1 = 7³

=> 2x - 1 = 3 => 2x = 4 => x = 2

b) (7x - 11)³ = 2⁵.3² + 200

=> (7x - 11)³ = 32.9 + 200

=> (7x - 11)³ = 488

xem kĩ lại đề này :vvv

c) 174 - (2x - 1)² = 5³

=> (2x - 1)² = 174 - 5³

=> (2x - 1)² = 174 - 125 = 49

=> (2x - 1)² = (\(\pm\)7)²

=> \(\orbr{\begin{cases}2x-1=7\\2x-1=-7\end{cases}}\Rightarrow\orbr{\begin{cases}x=4\\x=-3\end{cases}}\)

Mà x \(\in\)N nên x = 4( thỏa mãn điều kiện)

Bài 2 :

a) x⁵ = 32 => x⁵ = 2⁵ => x = 2

b) (x + 2)³ = 27

=> (x + 2)³ = 3³

=> x + 2 = 3 => x = 3 - 2 = 1

c) (x - 1)⁴ = 16

=> (x - 1)⁴ = 2⁴

=> x - 1 = 2 => x = 3 ( vì đề bài cho x thuộc N nên thỏa mãn)

d) (x - 1)⁸ = (x - 1)⁶

=> (x - 1)⁸ - (x - 1)⁶ = 0

=> (x - 1)⁶ [(x - 1)² - 1] = 0

=> \(\orbr{\begin{cases}\left(x-1\right)^6=0\\\left(x-1\right)^2-1=0\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\\left(x-1\right)^2=1\end{cases}}\Rightarrow\orbr{\begin{cases}x=1\\\left(x-1\right)^2=\left(\pm1\right)^2\end{cases}}\)

+) x - 1 = 1 => x = 2 ( tm)

+) x - 1 = -1 => x = 0 ( tm)

Vậy x = 1,x = 2,x = 0

\(a,\Rightarrow\left|x\right|=4+1,16=5,16\Rightarrow\left[{}\begin{matrix}x=5,16\\x=-5,16\end{matrix}\right.\\ b,\Rightarrow\left(3x-2\right)^3=\left(-\dfrac{5}{2}\right)^3\\ \Rightarrow3x-2=-\dfrac{5}{2}\\ \Rightarrow3x=-\dfrac{5}{2}+2=-\dfrac{1}{2}\\ \Rightarrow x=-\dfrac{1}{2}:3=-\dfrac{1}{6}\)

a)lxl - 1,16=4

lxl=4+1,16

lxl=5,16

=>x thuộc ( 5,16 ; -5,16)

a) \(\Rightarrow\left|x\right|=5,16\\ \Rightarrow\left[{}\begin{matrix}x=-5,16\\x=5,16\end{matrix}\right.\)

b) \(\Rightarrow\left(3x-2\right)^3=\left(\dfrac{-5}{2}\right)^3\\ \Rightarrow3x-2=-\dfrac{5}{2}\\ \Rightarrow3x=-\dfrac{1}{2}\\ \Rightarrow x=-\dfrac{1}{6}\)

M.n ơi mk cần m.n giải gấp lắm nên cảm ơn m.n nhìu😊😊😊😊

a) 25 - 3x = 13

            3x = 25 - 13

            3x = 12

              x = 12 : 3

              x = 4

b) 13 + 3(130 - 3x) = 313

            3(130 - 3x) = 313 - 13

            3(130 - 3x) = 300

               130 - 3x = 300 : 3

               130 - 3x = 100

                         3x = 130 - 100

                         3x = 30

                           x = 30 : 3

                           x = 10

25-3x=13

3x=25-13

3x=12

x=12:3

x=4

b, 13+3.(130-3x) =313

3.(130-3x)=313-13

3.(130-3x)=300

130-3x=300:3

130-3x=100

3x=130-100

3x=30

x=30:3

x=10

c, (17-x).125=1500

17-x=1500:125

17-x=12

x=17-12

x=5

\(\left(2600-6400\right)-3x=1200\\ -3800-3x=1200\\ 3x=-3800-1200\\ 3x=-5000\\ x=-5000:3\\ x=\dfrac{-5000}{3}\)

\(\left(3x-1\right)^3=125\\ \left(3x-1\right)^3=5^3\\ 3x-1=5\\ 3x=6\\ x=6:3\\ x=2\)

\(3^{x-1}+5.3^{x-1}=486\)

\(\Rightarrow3^{x-1}.\left(5+1\right)=486\)

\(3^{x-1}.6=486\)

\(3^{x-1}=81\)

\(3^{x-1}=3^4\)

\(\Rightarrow x-1=4\)

\(\Rightarrow x=5\)

<=> 3^x-1 +5.3^x-1 =486

<=> 3^x-1 . (1+5) = 486

<=> 3^x-1 . 6 =486

<=> 3^x-1 = 486 :6

<=> 3^x-1 = 81

<=> 3^x-1 = 3⁴

<=> X-1=4

<=> X = 4+1

<=> X=5

\(3^{x-1}+5.3^{x-1}=486\)

=> \(3^{x-1}.1+5.3^{x-1}=486\)

=> \(\left(3^{x-1}\right).1+5=486\)

=> \(\left(3^{x-1}\right).6=486\)

=> \(\left(3^{x-1}\right)=486:6\)

=> \(3^{x-1}=81\)

=> \(3^{x-1}=3^4\)

=> x - 1 = 4

           x = 4 - 1

           x = 3

Vậy x = 3

#Ori_deeptry

a)17-(12+13)

=17-25

=-8

b)2347-450-347-550

=(2347-347)-(450+550)

=2000-1000

=1000

c)(-71).(-175)-75.71

=71.(175-75)

=71.100

=7100

d)93.(27-100)+(-3)^3.93

=93.(27-100)+(-27).93

=93.((-27)+(-73))

=93.(-100)

=-9300

bài 2 :

a)x-15=-20

        x=-20+15

        x=-5 

b)3x+27=6

 3x=6-27

 3x=-21

    x=-21:3

    x=-7

c)3.(x-1)+27=102

  3.(x-1)=102-27

 3.(x-1)=75

   x-1=75:3

   x-1=25

     x=25+1

    x=26

d)|x-6|.7-(-2)^2=-8+39 

sory ,câu này mk ko làm đc