(7x-11)^3=(-3)^2x15+208
Tim x biet
(7x-11)^3=(-3)^2x15+208
(7x-11)3=(-3)3.15+208
(7x-11)3=(-3)3.15+208
(7x-11)3=-27.15+208
(7x-11)3=-405+208
(7x-11)3=-197
Vô lí vì -197 ko chuyển sang mũ 3 đc.
Vậy \(x\in\varnothing\)
(7x-11)3=(-3)2x15+208=?
( 7x - 11 )^3 = ( -3 ) ^2 x 15 + 208
( 7x - 11 )^3 = 9 x 15 + 208
( 7x - 11 )^3 = 135 + 208
( 7x - 11 )^3 = 343
( 7x - 11)^3 = 7^3
7x - 11 = 7
7x = 18
x = 18/7
(7x-11)3=(-3)2x15+208
(7x-11)3=9x15+208
(7x-11)3=135+208
(7x-11)3=343
(7x-11)3=73
7x-11=7
7x=7+11
7x=18
x=18 : 7
x=18/7
(7x-11)^3=9x15+208=135+208=343=7^3
7x-11=7
x=11+7:7
x=18/7
Tìm x biết
(7x-11)^3 = (-3).15 + 208
Tìm x biết ( 7x-11)3 = (-3)2.15+208
mình sửa lại nha, nãy mình nhìn nhầm dấu:
343x3 - 1617x2 + 2541x - 1674 = 0
x = 18/7 là nghiệm duy nhất của phương trình đã cho
Tìm x , biết:
a) (2x-15)5 = (2x-15)3
b) (7x-11)3 = (-3)2 . 15 + 208
Giúp mình nhanh nhé
a)
\(\left(2x-15\right)^5=\left(2x-15\right)^3\\ \Leftrightarrow\left(2x-15\right)^5-\left(2x-15\right)^3=0\\ \Leftrightarrow\left(2x-15\right)^3.\left[\left(2x-15\right)^2-1\right]=0\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15\right)^2-1=0\end{matrix}\right.\\ \Leftrightarrow\left[{}\begin{matrix}2x-15=0\\\left(2x-15-1\right).\left(2d-15+1\right)=0\end{matrix}\right.\\\Leftrightarrow\left[{}\begin{matrix}2x-15=0\\2x-16=0\\2x-14=0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x=\dfrac{15}{2}\\x=8\\x=7\end{matrix}\right. \)
b) \(\left(7x-11\right)^3=\left(-3\right)^2.15+208\\ \Leftrightarrow\left(7x-11\right)^3=343=7^3\\ \Leftrightarrow7x-11=7\\ \Leftrightarrow x=\dfrac{18}{7}\)
Tìm số nguyên x biết :
\(\left(7x-11\right)^3=\left(-3\right)^2\cdot15+208\)
( 7x - 11 ) 3 = ( -3 )2 .15 + 208
( 7x - 11 ) 3 = 9 .15 + 208
( 7x - 11 ) 3 = 135 + 208
( 7x - 11 ) 3 = 343
( 7x - 11 ) 3 = 73
=> 7x - 11 = 7
=> 7x = 7 + 11 = 18
=> x = 18/7
\(\left(7x-11\right)^3=\left(-3\right)^2.15+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=9.15+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=135+208\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=343\)
\(\Leftrightarrow\)\(\left(7x-11\right)^3=7^3\)
\(\Leftrightarrow\)\(7x-11=7\)
\(\Leftrightarrow\)\(7x=18\)
\(\Leftrightarrow\)\(x=\frac{18}{7}\)
Vậy \(x=\frac{18}{7}\)
Chúc bạn học tốt ~
Tính hợp lí :
B = 5 / 2 x1 + 4 / 1x 11 + 3 / 11 x 2 + 1 /2x15 + 13 / 15 x 4
trả lời:
B = 7x( 5/2x7 + 4/7x11 + 3/11x14 + 1/14x15 + 13/15x28 )
B = 7x(1/2 - 1/7 + 1/7 - 1/11 +....+ 1/15 - 1/28)
B = 7x(1/2 - 1/28)
B = 7x13/28
B = 13/4
Bàì làm:
\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(B=7.\left(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\right)\)
\(B=7.\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\right)\)
\(B=7.\left(\frac{1}{2}-\frac{1}{28}\right)\)
\(B=7.\frac{13}{28}\)
\(B=\frac{13}{4}\)
Bài làm:
\(B=\frac{5}{2.1}+\frac{4}{1.11}+\frac{3}{11.2}+\frac{1}{2.15}+\frac{13}{15.4}\)
\(B=7\left(\frac{5}{2.7}+\frac{4}{7.11}+\frac{3}{11.14}+\frac{1}{14.15}+\frac{13}{15.28}\right)\)
\(B=7\left(\frac{1}{2}-\frac{1}{7}+\frac{1}{7}-\frac{1}{11}+\frac{1}{11}-\frac{1}{14}+\frac{1}{14}-\frac{1}{15}+\frac{1}{15}-\frac{1}{28}\right)\)
\(B=7\left(\frac{1}{2}-\frac{1}{28}\right)=7.\frac{13}{28}=\frac{13}{4}\)
Tìm x
x + 1/ 2 = 8/ -3
(-5/3)3 < x < -24/35 * -5/6
(7x-11)3 = (-3)2 *15 +208
1) \(x=\frac{8}{-3}-\frac{1}{2}=\frac{-19}{6}\)
2) \(\left(\frac{-5}{3}\right)^3=\frac{-125}{27}\)
\(\frac{-24}{35}.\frac{-5}{6}=\frac{4}{7}\)
Mà \(\frac{-125}{27}<0<\frac{4}{7}\)
=> \(x=0\)
3) \(\left(7.x-11\right)^3=343\)
=> \(\left(7.x-11\right)^3=7^3\)
=> \(7.x-11=7\)
=> \(x=\frac{7+11}{7}=\frac{18}{7}\)