Ta có : 

\(\frac{x-1}{27}+\frac{x-2}{26}+\frac{x-3}{25}+\frac{x-4}{24}=4\)

\(\Leftrightarrow\)\(\left(\frac{x-1}{27}-1\right)+\left(\frac{x-2}{26}-1\right)+\left(\frac{x-3}{25}-1\right)+\left(\frac{x-4}{24}-1\right)=4-4\) ( trừ 2 vế cho 4 ) 

\(\Leftrightarrow\)\(\frac{x-28}{27}+\frac{x-28}{26}+\frac{x-28}{25}+\frac{x-28}{24}=0\)

\(\Leftrightarrow\)\(\left(x-28\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}\right)=0\)

Vì \(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}\ne0\)

Nên \(x-28=0\)

\(\Rightarrow\)\(x=28\)

Vậy \(x=28\)

Chúc bạn học tốt ~ 

\(x-\frac{1}{27}+x-\frac{2}{26}+x-\frac{3}{25}+x-\frac{4}{24}=4\)

\(\left(x+x+x+x\right)-\left(\frac{1}{27}+\frac{2}{26}+\frac{3}{25}+\frac{4}{24}\right)=4\)

\(4x-\frac{7031}{17550}=4\)

\(4x=4+\frac{7031}{17550}\)

\(x=\frac{4+\frac{7031}{17550}}{4}=1+\frac{\frac{7031}{17550}}{4}\)

\(x=1+\frac{7031}{70200}\)

.........................................................................................

CÁI ĐỀ CỦA BẠN DỄ GÂY HIỂU NHẦM QUÁ !!!

 ( 12 x 13 + 14 x 15 + ... + 24 x 25 + 26 x 27 ) x ( 14 + 6 - 10 + 5 - 3 x 5 )

=  ( 12 x 13 + 14 x 15 + ... + 24 x 25 + 26 x 27 ) x 0

= 0

\(1,=-\left(y^2+12y+36\right)=-y^2-12y-36\)

\(2,=-\left(16-8y+y^2\right)=-16+8y-y^2\)

\(3,=-\left(\dfrac{4}{9}+\dfrac{4}{3}x+x^2\right)=-\dfrac{4}{9}-\dfrac{4}{3}x-x^2\)

\(4,=-\left(x^2-3x+\dfrac{9}{4}\right)=-x^2+3x-\dfrac{9}{4}\)

\(5,-\left(2+3y\right)^2=-\left(4+12y+9y^2\right)=-4-12y-9y^2\)

.... mấy ý còn lại bn tự lm nhé, tương tự thhooi

1) \(-\left(y+6\right)^2=-y^2-12y-36\)

2) \(-\left(4-y\right)^2=-y^2+8y-16\)

3) \(-\left(x+\dfrac{2}{3}\right)^2=-x^2-\dfrac{4}{3}x-\dfrac{4}{9}\)

4) \(-\left(x-\dfrac{3}{2}\right)^2=-x^2+3x-\dfrac{9}{4}\)

5) \(-\left(3y+2\right)^2=-9y^2-12y-4\)

6) \(-\left(2y-3\right)^2=-4y^2+12y-9\)

7) \(-\left(5x+2y\right)^2=-25x^2-20xy-4y^2\)

8) \(-\left(2x-\dfrac{3}{2}\right)^2=-4x^2+6x-\dfrac{9}{4}\)

a) (x - 1/2)² = 4

<=> (x - 1/2)² = 2²

<=> x - 1/2 = -2; 2

<=> x - 1/2 = 2 hoặc x - 1/2 = -2

       x = 2 + 1/2         x = -2 + 1/2

       x = 5/2               x = -3/2

=> x = 5/2 hoặc x = -3/2

b) 10/1/2 - (x + 1/3)² = 1/1/2

<=> -(x + 1/3)² = 1/1/2 - 10/1/2

<=> -(x + 1/3)² = 1/2 - 5

<=> -(x + 1/3)² = -5.2 + 1/2

<=> -(x + 1/3)² = -9/2

<=> (x + 1/3)² = 9/2

<=> x + 1/3 = \(\sqrt{\frac{9}{2}}\)  hoặc x + 1/3 = \(-\sqrt{\frac{9}{2}}\)

       x = \(\frac{3\sqrt{2}}{2}\) - 1/3         x = \(-\frac{3\sqrt{2}}{2}\) -1/3

=> x = \(\frac{3\sqrt{2}}{2}\) - 1/3 hoặc x = \(-\frac{3\sqrt{2}}{2}\) -1/3

c) (x - 1/5)² + 17/25 = 26/25

<=> (x - 1/5)² = 26/25 - 17/25

<=> (x - 1/5)² = (3/5)²

<=> x - 1/5 = -3/5; 3/5

<=> x - 1/5 = 3/5 hoặc x - 1/5 = -3/5

       x = 3/5 + 1/5         x = -3/5 + 1/5

       x = 4/5                  x = -2/5

=> x = 4/5 hoặc x = -2/5

=9x2^25-2^2x2^26/2^24x5^2-2^27x3

=9x2^25-2^28/2^24x5^2-2^27x3

=2^25x(9-2^3)/2^24x(5^2-2^3x3)

=2^25/2^24

=2^1=2

x + 1/5 = 26/25 - 17/25                                                                         x       = 9/25 - 1/5                                                                           x       =      4/5                                                                                                                                                                                                                                                                                                                           

Tất cả đều trừ 1 vào mỗi thừa số=>tử số là:x-29(cái cuối+3)

=> cả cái đó=0

=> x-29=0 

=>x=29

\(\frac{x-2}{27}+\frac{x-3}{26}+\frac{x-4}{25}+\frac{x-5}{24}+\frac{x-44}{5}=1\)

\(\Rightarrow\left(\frac{x-2}{27}-1\right)+\left(\frac{x-3}{26}-1\right)+\left(\frac{x-4}{25}-1\right)+\left(\frac{x-5}{24}-1\right)+\left(\frac{x-44}{5}+3\right)=0\)

\(\Rightarrow\frac{x-29}{27}+\frac{x-29}{26}+\frac{x-29}{25}+\frac{x-29}{24}+\frac{x-29}{5}=0\)

\(\Rightarrow\left(x-29\right)\left(\frac{1}{27}+\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{5}\right)=0\)

\(\Rightarrow x-29=0\)

\(\Rightarrow x=29\)