Các câu hỏi tương tự
Khai triển hằng đẳng thức
1)-(y+6)^2
2)-(4-y)^2
3)-(2/3+x)^2
4)-(x-3/2)^2
5)-(2+3y)^2
6)-(2y-3)^2
7)-(5x+2y)^2
8)-(2x-3/2)^2
a) frac{x-23}{24}+frac{x-23}{25}frac{x-23}{26}+frac{x-23}{27}Leftrightarrowfrac{x-23}{24}+frac{x-23}{25}-frac{x-23}{26}-frac{x-23}{27}0Leftrightarrowleft(x-23right)left(frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}right)0Leftrightarrow x-230( vì frac{1}{24}+frac{1}{25}-frac{1}{26}-frac{1}{27}ne0)Leftrightarrow x23Vậy nghiệm của pt x23
Đọc tiếp
a) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
\(\Leftrightarrow\frac{x-23}{24}+\frac{x-23}{25}-\frac{x-23}{26}-\frac{x-23}{27}=0\)
\(\Leftrightarrow\left(x-23\right)\left(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\right)=0\)
\(\Leftrightarrow x-23=0\)( vì \(\frac{1}{24}+\frac{1}{25}-\frac{1}{26}-\frac{1}{27}\ne0\))
\(\Leftrightarrow x=23\)
Vậy nghiệm của pt x=23
Giải các phương trình sau:
a) \(x+\frac{2x\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{x-23}{24}+\frac{x+23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
Giải các phương trình sau:
a) \(x\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)
(X-19)/24+(X-19)/25=(X-19)/26+(X-19)/27
giải phương trình sau:
\(x = {x-25 \over 25} + {x-26 \over 24} + {x-27 \over 23} + {x-26 \over 22} +{x-17 \over 30}\)
\(\dfrac{x-23}{24}\)+\(\dfrac{x-23}{25}\)=\(\dfrac{x-23}{26}\)+\(\dfrac{x-23}{27}\)
(x - 2)2/3 - (2x - 3)(x + 3)/8 + (x - 4)2/6 =0 x3 - (x - 1)3/(4x + 3)(x - 5) = 7x - 1/4x + 3x - 23/24 + x - 23/25 = x - 23/26201 - x/99 + 203 - x/97 +205 - x/95 +3 =0
Xem chi tiết
Giải các phương trình sau:
a) \(x+\frac{2x+\frac{x-1}{5}}{3}=1-\frac{3x-\frac{1-2x}{3}}{5}\)
b) \(\frac{3x-1-\frac{x-1}{2}}{3}-\frac{2x+\frac{1-2x}{3}}{2}=\frac{\frac{3x-1}{2}}{5}\)
c) \(\frac{x-23}{24}+\frac{x-23}{25}=\frac{x-23}{26}+\frac{x-23}{27}\)