63 x 34 + 45 x 63 + 63 x 3 ?

= 63 x ( 34 + 45 + 3 ) 

= 63 x         82 

= 5166 

63 x 34 + 45 x 63 +63 x 3 

= 63 x ( 34 + 45 + 3 )

= 63 x 82

= 5166

= 63 x ( 34 + 45 + 3 )

= 63 x         82

= 5166

\(\dfrac{21}{11}\times\dfrac{22}{17}\times\dfrac{68}{63}\) = \(\dfrac{42}{17}\times\dfrac{68}{63}\) = \(\dfrac{8}{3}\)

 Vì \(\dfrac{21}{11}\times\dfrac{22}{17}=\dfrac{21\times22}{11\times17}=\dfrac{42}{17}\)

 Vậy:

 \(\dfrac{21}{11}\times\dfrac{22}{17}\times\dfrac{63}{68}\) =\(\dfrac{42}{17}\times\dfrac{68}{63}\) =\(\dfrac{21\times2\times17\times4}{17\times21\times3}\) =\(\dfrac{8}{3}\) = 

Ta có:

37.41+37.63-63.37+63.41

=41(37+63)

=41.100

=4100

Ta có:

20-5x=15+6x-6

<=>20-5x-15-6x+6=0

<=>11-11x=0

<=>11x=11

<=>x=1

Vậy x=1

a/   100 . 37 + 37. 37 + 200 . 63 - 63 . 63\

  =  37 .[ 100+ 37 ]   + 63 . [ 200 - 63 ]  

  =    37. 137             +  63 . 137 

  =    137. [ 37 + 63 ] 

  =   137 . 100 = 13700

b/  84 + 14 .6 + 7 . 12 + 21. 4 + 3.28 

=  84 + 84 +  84 + 84 +84

= 84. 5 = 420 

[ dấu " ." là " x" nha ] đừng quên tích cho tui 

a, 13700

cảm ơn anh NTN và bạn no_nickname nhé ! :))))

Sửa đề

\(\dfrac{3}{35}+\dfrac{3}{63}+\dfrac{3}{99}+...+\dfrac{3}{x\left(x+2\right)}=\dfrac{24}{35}\)

\(\dfrac{3}{5.7}+\dfrac{3}{7.9}+\dfrac{3}{9.11}+...+\dfrac{3}{x\left(x+2\right)}=\dfrac{24}{35}\)

\(\dfrac{3}{2}.\left(\dfrac{2}{5.7}+\dfrac{2}{7.9}+...+\dfrac{2}{x\left(x+2\right)}\right)=\dfrac{24}{35}\)

\(\dfrac{3}{2}.\left(\dfrac{1}{5}-\dfrac{1}{7}+\dfrac{1}{7}-\dfrac{1}{9}+...+\dfrac{1}{x}-\dfrac{1}{x+2}\right)=\dfrac{24}{35}\)

\(\dfrac{3}{2}.\left(\dfrac{1}{5}-\dfrac{1}{x+2}\right)=\dfrac{24}{35}\)

\(\dfrac{1}{5}-\dfrac{1}{x+2}=\dfrac{24}{35}:\dfrac{3}{2}\)

\(\dfrac{1}{5}-\dfrac{1}{x+2}=\dfrac{16}{35}\)

\(\dfrac{1}{x+2}=\dfrac{1}{5}-\dfrac{16}{35}\)

\(\dfrac{1}{x+2}=\dfrac{-9}{35}\)

\(x+2=35\)

\(x=35-2\)

\(x=33\)

\(-17x=-17-\left(-34\right)\)

\(-17x=-17\)

\(x=-1\)

Bạn coi lại đề: $\frac{3}{69}$ không nằm trong các số hạng có quy luật.

            A=12/15 + 28/315

            A=8/9 

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

a)67/63 x 15/3 + 15/31 x 11/21

Thiếu đề

b)15/31 x 34/63 - 11/21 x 15/31

=15/31 x ( 34/63 -11/21)

= 15/31 x  1/63=  5/651

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: \(=\dfrac{67}{63}\cdot5+\dfrac{11}{31}\cdot\dfrac{5}{7}=5\left(\dfrac{67}{63}+\dfrac{11}{31\cdot7}\right)=\dfrac{10880}{1953}\)

b: =15/31(34/63-11/21)=15/31x1/63=5/651

a: