Tìm x biết (2600+6400)-3.x=1200
giúp mình với
tìm x biết
(2600-6400)-3x=1200
(3x-1)3=125
\(\left(2600-6400\right)-3x=1200\\ -3800-3x=1200\\ 3x=-3800-1200\\ 3x=-5000\\ x=-5000:3\\ x=\dfrac{-5000}{3}\)
\(\left(3x-1\right)^3=125\\ \left(3x-1\right)^3=5^3\\ 3x-1=5\\ 3x=6\\ x=6:3\\ x=2\)
Tìm số tự nhiên x, biết: (2600 + 6400) – 3x = 1200
(2600 + 6400) – 3x = 1200
9000 – 3x = 1200
3x = 9000 - 1200
3x = 7800
x = 7800 : 3
x = 2600
Vậy x = 2600
( 2600 + 6400 ) - 3 . x = 1200
( 2600 + 6400 ) - 3 . x = 1200
9000 -3x =1200
3x = 9000-1200= 7800
x = 7800 : 3
x =2600
( 2600 + 6400 ) - 3 . x = 1200
=> 9000 -3x =1200
=> 3x = 9000-1200= 7800
=> x = 7800 : 3
=> x = 2600
9000-3.x=1200
=> 3x= 9000-1200
=>3x=7800
=>x=7800:3=2600
t i c k cho mình nha
(2600+6400)-3.x=1200
(2600 + 6400) - 3.x = 1200
9000 - 3.x = 1200
3.x = 9000 - 1200
3.x = 7800
x = 7800 : 3
x = 2600
<=>9000-3x=1200
<=> 9000-1200=3x
<=>7800=3x
<=>x=260
(2600+6400)-3.x=1200
9000-3.x =1200
3.x =9000 -1200
3.x =7800
x = 7800 :3
x = 2600
Tìm số tự nhiên x, biết :
a) (2600 + 6400) - 3 . =1200;
b) [(6 . x - 72) :2 - 84] . 28 + 5628
GIÚP!!!!!!!!!
a) (2600 + 6400) - 3 . x = 1200
9000 - 3.x = 1200
3x = 9000-1200
3x = 7800
x = 7800:3
x = 2600
b) câu này ko có tổng hả Công chúa nhí nhảnh? check lại giùm Nhi nha!
a) \(\left(2600+6400\right)-3x=1200\)
\(9000-3x=1200\)
\(3x=9000-1200\)
\(3x=7800\)
\(x=\frac{7800}{3}\)
\(x=2600\)
vậy \(x=2600\)
b) \(\left[\left(6x-72\right):2-84\right].28+5628=0\)
\(\left[\frac{6x}{2}-\frac{72}{2}-84\right].28+5628=0\)
\(\left[3x-36-84\right].28=-5628\)
\(3x-120=\frac{-5628}{28}\)
\(3x-120=-201\)
\(3x=-201+120\)
\(3x=-81\)
\(x=-27\)
vậy \(x=-27\)
Nhanh k hết suất tick nè
(2600 + 6400) - 3 x X = 1200
2p
\(\left(2600+6400\right)-3.X=1200\)
\(9000-3.X=1200\)
\(3.X=9000-1200\)
\(3.X=7800\)
\(X=7800:3\)
\(X=2600\)
(2600+6400)-3xX=1200
⇒ 9000-3xX=1200
⇒ 3xX=9000-1200=7800
⇒ X=7800:3=2600
⇒ X=2600
\(\left(2600+6400\right)-3\times x=1200\)
\(9000-3.x=1200\)
\(3.x=9000-1200\)
\(3.x=7800\)
\(x=7800:3\)
\(x=2600\)
( 2600+ 6400 ) - 3 . x = 1200
=>9000-3x=1200
=>3x=9000-1200
=>3x=7800
=>x=7800:3
=>x=2600
(2600+6400)-3.x=1200
=>9000-3.x=1200
=>3.x=9000-1200
=>3.x=7800
=>x=7800:3
=>x=2600
tìm số tự nhiên x
a, (2600+6400) - 3 . x = 1200
b,[ (6.x -72 ) : 2 - 84 ] . 28 = 5628
a,(2600+6400)-3 .x = 1200
=> 9000-3 .x= 1200
=> 3.x= 7800
=. x=2600
b, (6.x-72):2-84= 201
(6x-72):2=285
6x-72=570
6x=642
x=107
a) ( 2600 + 6400 ) - 3 . x = 1200
9000 - 3 . x = 1200
3 . x = 9000 - 1200
3 . x = 7800
x = 7800 : 3
x = 2600
Tìm số tự nhiên x, biết:
a) (2600+6400) - 3 . x = 1200 | b) [(6 .x - 72) : 2 - 84] . 28 = 5628
a) (2600+6400) - 3x = 1200
=> 9000 - 3x = 1200
=> 3x = 9000 - 1200
=> 3x = 7800
=> x = 7800 : 3
=> x = 2600
Vậy x = 2600.
b) [(6x - 72) : 2 - 84] . 28 = 5628
=> [(6x - 72) : 2 - 84] = 5628 : 28
=> (6x - 72) : 2 - 84 = 201
=> (6x - 72) : 2 = 201 + 84
=> (6x - 72) : 2 = 285
=> (6x - 72) = 285 . 2
=> 6x - 72 = 570
=> 6x = 570 + 72
=> 6x = 642
=> x = 642 : 6
=> x = 107
Vậy x = 107.