(2+4+6+........+100)*(36*333-108*111)

=(2+4+6+........+100)*(36*111*3-36*3*111)

=(2+4+6+.........+100)*          0

=0(vì số nào nhân với 0 cũng bằng 0)

(2+4+6+.....+100) x (36 x 333-108 x 111)

= (2+4+6+.....+100) x (36 x 3 x 111 - 36 x 3 x 111)

= (2+4+6+.....+100) x 0

= 0

Kunzy Nguyễn cop bài của ĐTV

=> 131.( x - 37 ) = 0

=> x - 37 = 0 : 131

=> x - 37 = 0

=>       x  = 0 + 37

=>       x   = 37

131 . (x - 37) = ( 2 + 4 + 6 + ... + 100) . (36.333 - 108 .111)

=> 131 . (x - 37) = ( 2 + 4 + 6 + ... + 100) . (36.3.111 - 108 .111)

=> 131 . (x - 37) = ( 2 + 4 + 6 + ... + 100) . [111.(36.3 - 108)]

=> 131 . (x - 37) = ( 2 + 4 + 6 + ... + 100) . [111.0]

=> 131 . (x - 37) = 0

=> x - 37 = 0 . 131 = 0

=> x = 0 + 37 = 37

Vậy x = 37

(2 + 4 + 6 + ...+ 98 + 100) x (36 x 333 - 108 x 111)

= (2 + 4 + 6 + ...+ 98 + 100) x (36 x 3 x 111 - 108 x 111)

= (2 + 4 + 6 + ...+ 98 + 100) x ( 108 x 111 - 108 x 111)

= (2 + 4 + 6 + ...+ 98 + 100) x 0 = 0

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tính nhanh 19991999*1998-19981998*1999

   (1+2+3+...+100)(108 x 111 - 36 x 333)

= (1+2+3+...+100)(36 x 3  x 111 - 36 x 3 x 111)

=(1+2+3+....) x 0

=0

(1 + 2 + 3 +..... + 100) (108 x 111 - 36 x 333) = 

(1 + 2 + 3 +..... + 100) (36 x 3 x 111 - 36 x 333) = 

(1 + 2 + 3 +..... + 100) (36 x 333 - 36 x 333) = 

(1 + 2 + 3 +..... + 100) x 0 = 0

(1+2+3+....+100).(108.111-36.333)

=(1+2+...+100).(36.3.111-36.3.111)

=(1+2+...+100).0

=0

Lời giải:
$36.333-108.111=36.3.111-108.111=108.111-108.111=0$

Suy ra:
$(2+4+6+...+100)(36.333-108.111)=(2+4+6+...+100).0=0$

HI

ta gọi (2+4+6+...+100) la a

=a     x     (36x33-108x111)

=a     x      11988-11988

=a     x      0

=0

đừng quên k cho mình nha

\(\left(2+4+6+...+100\right)\left(36.333-108.111\right)=\left(2+4+6+...+100\right).\left[111\left(36.3-108\right)\right]=\left(2+4+6+...+100\right).0=0\)

(2+4+6+.......+100) (36 x 333 -108 X 111 )
=2x(1+2+3+......+50)[36x111(1x3-3x1)
=2x(1+2+3+......+50)(36x111x0)
=2x(1+2+3+......+50)x0
=0

   ( 2 + 4 + 6 + ....... + 100 ) ( 36 x 333 - 108 X 111 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) [36 x 111 ( 1 x 3 - 3 x 1 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) ( 36 x 111 x 0 )
= 2 x ( 1 + 2 + 3 + ...... + 50 ) x 0
= 0

=(2+4+6+...+100)(36*3*111-108*111)

=(2+4+6+...+100)(108*111-108*111)

=(2+4+6+...+100)0

=0

(2+4+6+...+100)x(36x333-108x111)=(2+4+6+...+100)x(36x3x111-108x111)

=(2+4+6+...+100)x(108x111-108x111)

=(2+4+6+...+100)x0

=0