`a)1 4/23 + ( 5/21-4/23)+16/21-1/2`

`=27/23+5/21-4/23+16/21-1/2`

`=(27/23-4/23)+(5/21+16/21)-1/2`

`=23/23+21/21-1/2`

`=1+1-1/2`

`=2-1/2`

`=4/2-1/2`

`=3/2`

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`b)75%-(5/2+5/3)+(-1/2)^3`

`=3/4-5/2+5/3+(-1/8)`

`=(3/4-5/2-1/8)+5/3`

`=(6/8-20/8-1/8)+5/3`

`=-15/8+5/3`

`=-45/24+40/24`

`=-5/24`

___

`c)-3/4(-55/9).8/11`

`=-3/4.(-40/9)`

`=-10/3`

__

`d)-3/8 . 6/13 + 7/13 . (-3/8) + 1 3/8`

`= -3/8 . (6/13 + 7/13) + 11/8`

`= -3/8 . 13/13 + 11/8`

`= -3/8 .1 + 11/8`

`= -3/8 + 11/8`

`= 8/8`

`=1`

a: \(4\sqrt{7}=\sqrt{4^2\cdot7}=\sqrt{112}\)

\(3\sqrt{13}=\sqrt{3^2\cdot13}=\sqrt{117}\)

mà 112<117

nên \(4\sqrt{7}< 3\sqrt{13}\)

b: \(3\sqrt{12}=\sqrt{3^2\cdot12}=\sqrt{108}\)

\(2\sqrt{16}=\sqrt{16\cdot2^2}=\sqrt{64}\)

mà 108>64

nên \(3\sqrt{12}>2\sqrt{16}\)

c: \(\dfrac{1}{4}\sqrt{84}=\sqrt{\dfrac{1}{16}\cdot84}=\sqrt{\dfrac{21}{4}}\)

\(6\sqrt{\dfrac{1}{7}}=\sqrt{36\cdot\dfrac{1}{7}}=\sqrt{\dfrac{36}{7}}\)

mà \(\dfrac{21}{4}>\dfrac{36}{7}\)

nên \(\dfrac{1}{4}\sqrt{84}>6\sqrt{\dfrac{1}{7}}\)

d: \(3\sqrt{12}=\sqrt{3^2\cdot12}=\sqrt{108}\)

\(2\sqrt{16}=\sqrt{16\cdot2^2}=\sqrt{64}\)

mà 108>64

nên \(3\sqrt{12}>2\sqrt{16}\)

42:x=6

x= 42 :6 

X= 7

TH 2

36:x = 6

X = 36: 6

X= 6

a, 64 . 23 + 37 . 23  - 23 

= 23. (64 + 37  - 1) 

= 23 . 100

=2300 

b, 33,76 + 19,52 + 6,24 

= (33,76 + 6,24) + 19,52 

= 40 + 19,52 

= 59,52 

c, 38/11 + (16/13 + 6/11) 

 = 38/11 + 16/13 + 6/11 

= (38/11 + 6/11) + 16/13 

= 4 + 16/13 

= 52/13 + 16/13 

= 68/13 

d, 3/4 : 3/5 - 1/5 

= 3/4 . 5/3 - 1/5 

= 5/4 - 1/5 

= 25/20 - 4/20 

= 21/20

e, \(5\frac{3}{4}\div\frac{12}{13}+6\frac{1}{4}\div\frac{12}{13}\)

\(=\frac{23}{4}\cdot\frac{13}{12}+\frac{25}{4}\cdot\frac{13}{12}\)

\(=\frac{13}{12}\cdot\left(\frac{23}{4}+\frac{25}{4}\right)\)

\(=\frac{13}{12}\cdot12=13\)

f, S = 1 + 2 + 3 + 4 + ... + 99 + 100 

Số số hạng của S là : 

(100 - 1) : 1 + 1 = 100 (số hạng) 

Tổng của S là : 

(1 + 100) . 100 : 2 = 5050

Vậy S = 5050 

Dấu " . " là dấu nhân nhé :D 

a: \(12+2^2+3^2+4^2+5^2\)

\(=12+4+9+16+25\)

\(=16+50=66\)

\(\left(1+2+3+4+5\right)^2=15^2=225\)

=>\(12+2^2+3^2+4^2+5^2< \left(1+2+3+4+5\right)^2\)

b: \(1^3+2^3+3^3+4^3=\left(1+2+3+4\right)^2< \left(1+2+3+4\right)^3\)

c: \(5^{202}=5^2\cdot5^{200}=25\cdot5^{200}>16\cdot5^{200}\)

d: \(18\cdot4^{500}=18\cdot2^{1000}\)

\(2^{1004}=2^4\cdot2^{1000}=16\cdot2^{1000}\)

=>\(18\cdot4^{500}>2^{1004}\)

e: \(2022\cdot2023^{2024}+2023^{2024}=2023^{2024}\left(2022+1\right)\)

\(=2023^{2025}\)

Câu 13 :

\(\left(-\frac{1}{4}+\frac{5}{8}\right)+-\frac{3}{5}\)

\(=\frac{3}{8}-\frac{-3}{5}\)

\(=\frac{39}{40}\)

Câu 14 :

\(M=\frac{5}{9}.\frac{7}{13}+\frac{5}{9}.\frac{9}{13}-\frac{5}{9}.\frac{3}{13}\)

\(=\frac{5}{9}.\left(\frac{7}{13}+\frac{9}{13}-\frac{3}{13}\right)\)

\(=\frac{5}{9}.1=\frac{5}{9}\)

Câu 15 :

\(E=\left(-\frac{3}{4}+\frac{2}{5}\right):\frac{3}{7}+\left(\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)

\(E=\left(-\frac{3}{4}+\frac{2}{5}+\frac{3}{5}+\frac{-1}{4}\right):\frac{3}{7}\)

\(E=0\)

Câu 16 :

\(H=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}\right)+\frac{7}{8}:\left(\frac{1}{36}-\frac{5}{12}\right)\)

\(=\frac{7}{8}:\left(\frac{2}{9}-\frac{1}{8}+\frac{1}{36}-\frac{5}{12}\right)\)

\(=\frac{7}{8}:\frac{-7}{24}=-3\)

huhuhuhuhuhuhuhuhuhuhuhuhu giúp mk đi 

Plssssssssssssssssssssssssssssssssssssssssssssss

Câu 14:

M =  \(\frac{5}{9}\) \(.\) \(\frac{7}{13}\) \(+\) \(\frac{5}{9}\) \(.\) \(\frac{9}{13}\) \(-\) \(\frac{5}{9}\) \(.\) \(\frac{3}{13}\)

M =    \(\frac{5}{9}\)  \(.\) (   \(\frac{7}{13}\)\(+\) \(\frac{9}{13}\) \(-\) \(\frac{3}{13}\))

M =      \(\frac{5}{9}\)  \(.\)    \(1\)

M  =              \(\frac{5}{9}\)

a,

-2,5% - { 1- ( \(\frac{2}{3}\)) \(^2\)} + ( 1 - \(\frac{4}{9}\))

= -250 - { 1 - \(\frac{4}{9}\)} + \(\frac{5}{9}\)

= -250 - \(\frac{5}{9}\)+ \(\frac{5}{9}\)

= -250