Điền các sô thích hợp vào chỗ trống
e, \(\sqrt{\frac{0,09}{25}}=-\frac{4,7}{5}+...\)
g, \(\sqrt{5^2+3^2}=-\sqrt{81}-...\)
1. Điền các số thích hợp vào chỗ chấm:
a)\(\frac{16}{3}\):.. = \(\frac{50}{12}\):(-0,06)
b)(2. ...-1)\(^3\)=-8
c)\(\frac{\left(0,8^5\right)}{\left(0,4^6\right)}\)=...
d) 0,944-2. ...= 3,26
e)\(\sqrt{\frac{0,09}{25}}\)=-\(\frac{4,7}{5}\)+ ...
g)\(\sqrt{5^2}-3^2\)= -\(\sqrt{81}\)- ...
e)=0,94
d)= -1,158
a) (câu này mk ko chắc) = 3/155,25
câu b chịu
c) = 0,32768/0,4096
g) khả năng là đề sai
Điền số thích hợp vào chỗ chấm
a) \(\frac{16}{3}:....=\frac{50}{12}:\left(-0,06\right)\) d) \(0,944-2\times........=3,268\)
b) \(\left(2\times......-1\right)^3=-8\) e )\(\sqrt{\frac{0,09}{25}}\)\(=-\frac{4,7}{5}+........\)
c) \(\frac{\left(0,8\right)^5}{\left(0,4\right)^6}=.......\) g) \(\sqrt{5^2-3^2}\)\(=-\sqrt{81}\)\(-.........\)
a) \(-\frac{48}{625}\)
b) không có giá trị
c) 1:125
d) \(-\frac{1053}{500}\)
e) 1
g) -13
a) \(-\dfrac{48}{625}\)
b) \(\varnothing\)
c) \(\dfrac{1}{125}\)
d) \(-\dfrac{1053}{500}\)
e) 1
f) -13
TÍNH GIÁ TRỊ CÁC BIỂU THỨC SAU
A,\(\sqrt{0,09}-\sqrt{0,64}\)
B,\(0,1\times\sqrt{225}-\sqrt{\frac{1}{4}}\)
C,\(\sqrt{0,36}\times\sqrt{\frac{25}{16}+\frac{1}{4}}\)
D,\(\sqrt{\frac{4}{81}}:\sqrt{\frac{25}{81}-1\frac{2}{5}}\)
a) \(\sqrt{0,09}-\sqrt{0,64}=\frac{-1}{2}=-0,5\)
b) \(0,1\cdot\sqrt{225}-\sqrt{\frac{1}{4}}=0,1\cdot15-\frac{1}{2}=1\)
c) \(\sqrt{0,36}\cdot\sqrt{\frac{25}{16}+\frac{1}{4}}=\frac{3\sqrt{29}}{20}\)
d) đề baì có sai ko ban?
Tìm giá trị các biểu thức sau bằng cách biến đổi, rút gọn thích hợp:
a) \(\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{196}{9}}\) b) \(\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}\)
c) \(\frac{\sqrt{640}.\sqrt{34,3}}{\sqrt{567}}\) d) \(\sqrt{21,6}.\sqrt{810}.\sqrt{11^2-5^2}\)
Tính
1. \(\sqrt{\left(\frac{2}{3}\right)^2}-\sqrt{0,09}+\sqrt{\frac{9}{25}}\)
2. \(\sqrt{\left(\frac{-2}{5}\right)^2}+\sqrt{1,44}-\sqrt{\frac{25}{4}}\)
a) \(\dfrac{2}{5}\sqrt{25}\) -\(\dfrac{1}{2}\sqrt{4}\) b)0,5\(\sqrt{0,09}\) +5\(\sqrt{0,81}\) c)\(\dfrac{2}{5}\sqrt{\dfrac{25}{36}}\) -\(\dfrac{5}{2}\sqrt{\dfrac{4}{25}}\)
d)-2\(\sqrt{\dfrac{-36}{-16}}\) + 5\(\sqrt{\dfrac{-81}{-25}}\)
`#3107.101107`
a)
`2/5 \sqrt{25} - 1/2 \sqrt{4}`
`= 2/5 * \sqrt{5^2} - 1/2 * \sqrt{2^2}`
`= 2/5*5 - 1/2*2`
`= 2 - 1`
`= 1`
b)
`0,5*\sqrt{0,09} + 5*\sqrt{0,81}`
`= 0,5*\sqrt{(0,3)^2} + 5*\sqrt{(0,9)^2}`
`= 0,5*0,3 + 5*0,9`
`= 0,15 + 4,5`
`= 4,65`
c)
`2/5\sqrt{25/36} - 5/2\sqrt{4/25}`
`= 2/5*\sqrt{(5^2)/(6^2)} - 5/2*\sqrt{(2^2)/(5^2)}`
`= 2/5*5/6 - 5/2*2/5`
`= 1/3 - 1`
`= -2/3`
d)
`-2 \sqrt{(-36)/(-16)} + 5 \sqrt{(-81)/(-25)}`
`= -2*\sqrt{36/16} + 5*\sqrt{81/25}`
`= -2*\sqrt{(6^2)/(4^2)} + 5*\sqrt{(9^2)/(5^2)}`
`= -2*6/4 + 5*9/5`
`= -3 + 9`
`= 6`
Tìm x:
a) \(\dfrac{16}{3}:x=\dfrac{50}{12}\left(-0,06\right)\) b) \(2.x-1^3=-8\) c) \(\dfrac{\left(0.8\right)^5}{\left(0.4\right)^6}=x\)
d)\(0,944-2.x=3,268\) e)\(\sqrt{\dfrac{0,09}{25}=-\dfrac{4,7}{5}+x}\) g)\(\sqrt{5^2-3^2}=-\sqrt{81-x}\)
a) x = \(\dfrac{-64}{3}\)
b) x = -3,5
c) x = 80
d) x = -1.162
e) x = 0,9436
g) x \(\in\varnothing\)
a) 16/3 : x = -1/4
=> x = 16/3 : (-1/4)
=> x = 16/3 . (-4)
=> x = -64/3
Vậy x= -64/3
b)2x - 13 = -8
=> 2x = (-8) + 1
=> 2x = -7
=> x = -7/2
d) 0,944 - 2x = 3,268
=> 2x = 0,944 - 3,268
=> 2x = -2,324
=> x = (-2,324) : 2
=> x = -1,162
g) \(\sqrt{5^2-3^2}=-\sqrt{81-x}\)
=> \(\sqrt{25-9}\)= \(-\sqrt{81-x}\)
=> \(\sqrt{16}\)=\(-\sqrt{81-x}\)
=> 4=\(-\sqrt{81-x}\)
tới đây mik bí r hk bt lm nữa
Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
a) = \(\frac{7}{2}\)
b) = \(\frac{643}{64}\)
c) = 0
giúp mik vs
\[ 5\sqrt{\frac{9x - 27}{25}} - 7\sqrt{\frac{4x - 12}{9}} - 7\sqrt{x^2 - 9} + 18\sqrt{\frac{9x^2 - 81}{81}} = 0 \]
=>\(5\cdot\dfrac{3\sqrt{x-3}}{5}-7\cdot\dfrac{2\sqrt{x-3}}{3}-7\cdot\sqrt{x^2-9}+18\cdot\sqrt{\dfrac{9}{81}\left(x^2-9\right)}=0\)
=>\(3\cdot\sqrt{x-3}-\dfrac{14}{3}\sqrt{x-3}=7\cdot\sqrt{x^2-9}-18\cdot\dfrac{3}{9}\cdot\sqrt{x^2-9}\)
=>\(-\dfrac{5}{3}\sqrt{x-3}=\sqrt{x^2-9}\)
=>\(\sqrt{x-3}\left(\sqrt{x+3}+\dfrac{5}{3}\right)=0\)
=>x-3=0
=>x=3