66 . 25 + 5 .66 + 66 . 14 + 33 . 66 = 66( 25+5+14+33)

= 66. 77

= 5082

66x25 + 5x66 + 66x14 + 33x66

= 66x(25 + 5 + 66 + 14)

= 66x100

6600

Tíck cho mình đi

*Tên Cristiano Ronaldo kiêu lắm

quỳnh như ơi bạn chọn sai rồi 

phải chọn Vũ Khánh Linh

1: =66+34-73-27+99=99

2: =54-45+30-54-30+5=-40

3: =42-56+33-33+56-42=0

4: =50-47-50+18+47-18=0

5: =10-28+30-4=2-4+10=12-4=8

\(\text{1.-(-66)+34+(-73)-27+99}.\)

\(=66+34-73-27+99=100-100+99=-99.\)

\(\text{2.54-(45-30+54)-30+5}.\)

\(54-45+30-54-30+5=\left(54-54\right)+\left(-45+5\right)+\left(30-30\right)=-40.\)

\(\text{3.42-56+33-(33-56+42)}.\)

\(=42-56+33-33+56-42=\left(42-42\right)+\left(-56+56\right)+\left(33-33\right)=0.\)

\(\text{4.50-(47+50-18)+(47-18)}.\)

\(=50-47-50+18+47-18=\left(50-50\right)+\left(-47+47\right)+\left(18-18\right)=0.\)

\(\text{5.10-(28-30+4)}.\)

\(=10-28+30-4=10+30-20-8-4=20-12=8.\)

\(\text{6.-(-73)+(44-94+27)+94}.\)

\(=73+44-94+27+94=\left(73+27\right)+\left(-94+94\right)+44=100+44=144.\)

a: =50-52=-2

b: =-35+149-114

=-149+149

=0

c: =-29x100=-2900

|25 - 24 -10| - (28 - 30 + 4)
= |1 - 10| - (-2 + 4)
= |-9| - 2
= 9 - 2
= 7
-(-73) + (44 - 94 + 27) + 94
= 73 + (-50 + 27) + 94
= 73 + (-23) + 94
= 73 - 23 + 94
= 50 + 94
= 144
(-33 + 108 - 75) - (108 + 25)
= (75 - 75) - 133
= 0 - 133
= -133
120 - (-2 + 120 - 18) - 92
= 120 - (118 - 18) - 92
= 120 - 100 - 92
= 20 - 92
= -72

Sửa đề:

\(A=\dfrac{3}{5}+\dfrac{3}{20}+\dfrac{3}{44}+\dfrac{3}{77}\)

\(A=2.\left(\dfrac{3}{5}+\dfrac{3}{20}+\dfrac{3}{44}+\dfrac{3}{77}\right)\)

\(A=\dfrac{6}{10}+\dfrac{6}{40}+\dfrac{6}{88}+\dfrac{6}{154}\)

\(A=6.\left(\dfrac{1}{2.5}+\dfrac{1}{5.8}+\dfrac{1}{8.11}+\dfrac{1}{11.14}\right)\)

\(A=6.\left(\dfrac{1}{2}-\dfrac{1}{5}+\dfrac{1}{5}-\dfrac{1}{8}+\dfrac{1}{8}-\dfrac{1}{11}+\dfrac{1}{11}-\dfrac{1}{14}\right)\)

\(A=6.\left(\dfrac{1}{2}-\dfrac{1}{14}\right)\)

\(A=6.\dfrac{6}{14}\)

\(A=\dfrac{36}{14}=\dfrac{18}{7}\)

\(=\dfrac{1}{5}.3+\dfrac{1}{5}.\dfrac{3}{4}+\dfrac{1}{11}.\dfrac{3}{4}+\dfrac{1}{11}.\dfrac{3}{7}\)

\(=\dfrac{1}{5}.\left(3+\dfrac{3}{4}\right)+\dfrac{1}{11}.\left(\dfrac{3}{4}+\dfrac{3}{7}\right)\)

\(=\dfrac{1}{5}.\dfrac{15}{4}+\dfrac{1}{11}.\dfrac{33}{28}=\dfrac{3}{4}+\dfrac{3}{28}=\dfrac{6}{7}\)

\(a.\left(-83\right)+302+83\\ =\left(-83+83\right)+302\\ =0+302\\ =302\\ b.14.\left(-7\right)-216:2\\ =-98-108\\ =-206\\ c.56.\left(-32\right)+\left(-68\right).56\\ =56.\left[\left(-32\right)+\left(-68\right)\right]\\ =57.\left(-100\right)\\ =-5700\\ d.2^3-6.\left[25-\left(33-28\right)^2\right]\\ =8-6\left[25-5^2\right]\\ =8-6\left[25-25\right]\\ =8-6.0\\ =8-0\\ =8\\ e.15.\left(-6\right)-420:\left(-4\right)\\ =-90-\left(-105\right)\\ =-90+105\\ =15\)

\(f.63.\left(-52\right)+\left(-48\right).63\\ =63.\left[\left(-52\right)+\left(-48\right)\right]\\ =63.\left(-100\right)\\ =-6300\)

\(25-\left(44-756+12\right)+\left(44-756+12\right)\)

\(=25-44+756-12+44-756+12\)

\(=25+\left(44-44\right)+\left(756-756\right)+\left(12-12\right)\)

=25