1 13/15 . 0,75 - (11/20+25%) : 1 2/5
1 và 13/15 . 0,75 - (11/20 + 25%) : 1 và 2/5
\(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):1\dfrac{2}{5}\)
\(=\dfrac{28}{15}.\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{1}{4}\right):\dfrac{7}{5}\)
\(=\dfrac{7}{5}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right):\dfrac{7}{5}\)
\(=\dfrac{7}{5}-\dfrac{16}{20}:\dfrac{7}{5}=\dfrac{7}{5}-\dfrac{4}{5}.\dfrac{5}{7}=\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{49}{35}-\dfrac{20}{35}=\dfrac{29}{35}\)
A,. 1 13/15 .0,75 -(11/20+25%):7/5
B, (2/3)^2:(-8)-(-1/4+9/20):1 4/5
Giúp em với ạ 🥺
= 4/9 : -8 - (-1/4 + 9/20) : 14/5
= 4/9 : -8 - 1/5 : 14/5
= -1/18 - 1/5 : 14/5
= -1/18 - 1/14
= -8/63
1 13/15 . 0,75 - (11/20 + 25/100) : 7/5
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}.\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)
\(1\frac{13}{15}\cdot0,75-\left(\frac{11}{20}+\frac{25}{100}\right):\frac{7}{5}\)
\(=\frac{28}{15}\cdot\frac{3}{4}-\frac{4}{5}:\frac{7}{5}\)
\(=\frac{7}{5}-\frac{4}{7}\)
\(=\frac{29}{35}\)
\(1\dfrac{13}{15}.0,75-\left[\dfrac{11}{20}+25\%\right]:\dfrac{7}{5}\)
\(1\dfrac{13}{15}\cdot0,75-\left[\dfrac{11}{20}+25\%\right]\div\dfrac{7}{5}\\ =\dfrac{28}{15}\cdot0,75-\dfrac{4}{5}\cdot\dfrac{5}{7}\\ =\dfrac{7}{5}-\dfrac{4}{7}=\dfrac{29}{35}\)
Tìm thương của B và nghịch đảo của B biết:
B= 1/13/15. 0,75 - ( 11/20+25%): 2/5 là
A.-3/5 B.16/25 C.-9/25 D. 9/25
1 13/15 . 0,75 - ( 11/20 + 25%) : 7/3
\(1\frac{13}{15}.0,75-\left(\frac{11}{20}+25\%\right):\frac{7}{3}\)
\(=\frac{28}{15}.\frac{3}{4}-\left(\frac{11}{20}+\frac{1}{4}\right):\frac{7}{3}\)
\(=\frac{7}{5}-\frac{4}{5}.\frac{3}{7}\)
\(=\frac{7}{5}-\frac{12}{35}\)
\(=\frac{37}{35}\)
Đặt A=\(1\frac{13}{15}\). \(0,75\) - (\(\frac{11}{20}\)+25%):\(\frac{7}{3}\)
A=\(\frac{28}{15}\). \(\frac{3}{4}\)-(\(\frac{11}{20}\)+\(\frac{1}{4}\)). \(\frac{3}{7}\)
A=\(\frac{7}{5}\)- \(\frac{4}{5}\).\(\frac{3}{7}\)
A=\(\frac{7}{5}\)-\(\frac{12}{35}\)
A=\(\frac{37}{35}\)
1, A= \(\dfrac{-3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
2, B= \(1\dfrac{13}{15}.0,75-\left(\dfrac{11}{20}+25\%\right):\dfrac{7}{3}\)
3, C= \(\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
4, D= \(6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(1,A=-\dfrac{3}{4}.\left(0,125-1\dfrac{1}{2}\right):\dfrac{33}{16}-25\%\)
\(A=-\dfrac{3}{4}.\left(0,125-\dfrac{3}{2}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=-\dfrac{3}{4}.\left(-\dfrac{11}{8}\right):\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}:\dfrac{33}{16}-\dfrac{1}{4}\)
\(A=\dfrac{33}{32}.\dfrac{16}{33}-\dfrac{1}{4}\)
\(A=\dfrac{1}{2}-\dfrac{1}{4}\)
\(A=\dfrac{2}{4}-\dfrac{1}{4}\)
\(A=\dfrac{1}{4}\)
\(D=6\dfrac{5}{12}:2\dfrac{5}{4}+11\dfrac{1}{4}.\left(\dfrac{1}{3}-\dfrac{1}{5}\right)\)
\(D=\dfrac{77}{12}:\dfrac{13}{4}+\dfrac{45}{4}.\dfrac{2}{15}\)
\(D=\dfrac{77}{39}+\dfrac{3}{2}\)
\(D=\dfrac{271}{78}\)
\(C=\dfrac{5}{16}:0,125-\left(2\dfrac{1}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\left(\dfrac{9}{4}-0,6\right).\dfrac{10}{11}\)
\(C=\dfrac{5}{16}:0,125-\dfrac{33}{20}.\dfrac{10}{11}\)
\(C=\dfrac{5}{2}-\dfrac{3}{2}\)
\(C=1\)
5-7/39÷7/13+8/9÷4
1 và 13/15:0,75-(11/20+25%) ÷7/3
a:\(=5-\dfrac{7}{39}\cdot\dfrac{13}{7}+\dfrac{2}{9}=5-1+\dfrac{2}{9}=4+\dfrac{2}{9}=\dfrac{38}{9}\)
b: \(=\dfrac{28}{15}:\dfrac{3}{4}-\left(\dfrac{11}{20}+\dfrac{5}{20}\right)\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{4}{5}\cdot\dfrac{3}{7}\)
\(=\dfrac{112}{45}-\dfrac{12}{35}=\dfrac{676}{315}\)
\(1\dfrac{13}{15}\) . 0,75 - \((\dfrac{11}{20}\) + 25%) : \(\dfrac{7}{3}\)
Help me!!!! Giúp tớ với ạ🥺👉🏻👈🏻
= 28/15 . 3/4 - ( 11/20 + 1/4 ) : 7/3
= 28/15 . 3/4 - 4/5 : 7/3
= 7/5 - 12/35
= 37/35
= \(\dfrac{28}{15}\) . \(\dfrac{3}{4}\) - (\(\dfrac{11}{20}\) + \(\dfrac{1}{4}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - (\(\dfrac{11}{20}\) + \(\dfrac{5}{20}\)) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) : \(\dfrac{7}{3}\)
= \(\dfrac{7}{5}\) - \(\dfrac{16}{20}\) x \(\dfrac{3}{7}\)
= \(\dfrac{7}{5}\) - \(\dfrac{12}{35}\)
= \(\dfrac{49}{35}\) - \(\dfrac{12}{35}\)
= \(\dfrac{37}{35}\)