\(\frac{-3}{-7}\)\(+\) \(\frac{5}{19}+\)\(\frac{-4}{7}\)

\(=\frac{16}{133}\)

Tl

-3/-7 + 5/19 + -4/ 7 += 16/133

nha HT 

nhớ k cho mik

cái đầu bòi

Mot nghin khong tram ba hai phan hai nghin hai tram sau muoi mot

mười sáu phần một trăn ba mươi ba

sorry mik mới lớp 5 thôi mik ko biết cách tính

\(\frac{\text{-7}}{\text{6}}:x=\frac{\text{3}}{\text{7}}\)

=>\(x=\frac{\text{-7}}{\text{6}}:\frac{\text{3}}{\text{7}}\)

=> x = \(-2\frac{\text{13}}{\text{18}}\)

Vậy x = \(-2\frac{\text{13}}{\text{18}}\)

x=-49/18

\(\frac{1}{2}+-\frac{1}{5}+-\frac{5}{7}+\frac{1}{6}-\frac{3}{35}+\frac{1}{3}+\frac{1}{41}=\frac{1}{41}\)

1/41 giai ra dai nam cu rut gon roi quy dong

\(\frac{1}{2}+\left(-\frac{1}{5}\right)+\left(-\frac{5}{7}\right)+\frac{1}{6}+\left(-\frac{3}{35}\right)+\frac{1}{3}+\frac{1}{41}\)

\(=\left(\frac{1}{2}+\frac{1}{6}+\frac{1}{3}\right)+\left[\left(\frac{-1}{5}\right)+\left(-\frac{5}{7}\right)+\left(-\frac{3}{35}\right)\right]+\frac{1}{41}\)

\(=1+\left(-1\right)+\frac{1}{41}\)

=0+1/41=1/41

\(\dfrac{-7}{6}+\dfrac{18}{6}=\dfrac{11}{6}\)

` 5/9 . ( -2/13)+5/9.(-7/13)+(-8/13) = 5/9(-2/13-7/13)-8/13=5/9.(-9/13)-8/13=-5/13-8/13=-13/13=-1 `

GHI ra phân số đc ko

=100/273 hả đk ???🤔🤔😵😵