Ta có: 

\(5^{217}>5^{216}\)

Mà: \(5^{216}=5^{3\cdot72}=\left(5^3\right)^{72}=125^{72}\)

Lại có: \(125>119\Rightarrow125^{72}>119^{72}\)

\(\Rightarrow5^{216}>119^{72}\)

\(\Rightarrow5^{217}>119^{72}\)

a. \(5^{127}=5.5^{126}=5.125^{72}>119^{72}\)

\(\Rightarrow5^{217}>119^{72}\)

b. \(2^{1000}=\left(2^5\right)^{200}=32^{200}\)

\(5^{400}=\left(5^2\right)^{200}=25^{200}\)

\(\Rightarrow2^{1000}>5^{400}\)

c. \(9^{12}=\left(3^2\right)^{12}=3^{24}\)

\(27^7=\left(3^3\right)^7=3^{21}\)

\(\Rightarrow9^{12}>27^7\)

d. \(125^{80}=\left(5^3\right)^{80}=5^{240}\)

\(25^{118}=\left(5^2\right)^{118}=5^{236}\)

\(\Rightarrow125^{80}>25^{118}\)

e. \(5^{40}=\left(5^4\right)^{10}=625^{10}\)

\(\Rightarrow5^{40}>620^{10}\)

f. \(27^{11}=\left(3^3\right)^{11}=3^{33}\)

\(81^8=\left(3^4\right)^8=3^{32}\)

\(\Rightarrow27^{11}>81^8\)

Ta co \(\frac{33.10^3}{2^3.10^3+7000}=\frac{33.10^3}{8.10^3+7.10^3}=\frac{33.10^3}{15.10^3}=\frac{33}{15}>\frac{3774}{5217}\)

Ngọc Nguyễn Minh sai be bét rồi -_-        

2³ = 8 chứ ko = 6

what lộn bài rồi bạn

\(2\sqrt{2}=\sqrt{4.2}=\sqrt{8}\)

Vì \(8>1\Rightarrow\sqrt{8}>\sqrt{1}\Rightarrow2\sqrt{2}>1\)

\(2\sqrt{2}=2.\sqrt{2}\\ 2>1;\sqrt{2}>1\rightarrow2\sqrt{2}>1\)

\(2\sqrt{2}=\sqrt{8}\)

mà \(\sqrt{8}>1\)

nên \(2\sqrt{2}>1\)