x-2016/2016+x-2016/2015+x-2016/2014+x-2016/2013+x-2016/2012
Tính GTNN của B=|x-2016|+|x-2015|+|x-2014|+|x-2013|+|x-2012|+2016
Áp dụng bđt |a|+|b|+|c|+|d| \(\ge\)|a+b+c+d| ta có:
B = |x-2016|+|x-2015|+|x-2014|+|x-2013|+|x-2012|+2016
B = |2016-x|+|2015-x|+|x-2014|+|x-2013|+|x-2012|+2016 \(\ge\) |(2016-x)+(2015-x)+0+(x-2013)+(x-2012)|+2016 = |6|+2016 = 6+2016 = 2022
Dấu "=" xảy ra khi \(\left\{\begin{matrix}x-2015\le0\\x-2014=0\\x-2013\ge0\end{matrix}\right.\) => x = 2014
Ta có: \(\left|x-2016\right|\ge0\forall x\in R\)
\(\left|x-2015\right|\)\(\ge0\forall x\in R\)
.....................
=> |x-2016|+|x-2015|+|x-2014|+|x-2013|+|x-2012| \(\ge0\forall x\in R\)
=> |x-2016|+|x-2015|+|x-2014|+|x-2013|+|x-2012| + 2016 \(\ge0\forall x\in R\)
Dấu "=" xảy ra khi \(\left|x-2016\right|=0\); .....; \(\left|x-2012\right|=0\) Với \(\left|x-2016\right|=0\) => x = \(2016\) Với \(\left|x-2015\right|=0\) => x = 2015 Với \(\left|x-2014\right|=0\) => x = 2014 Với \(\left|x-2013\right|=0\) => x = 2013 Với \(\left|x-2012\right|=0\) => x = 2012 Vậy GTNN của B = 2016 khi x \(\in\) \(\left\{2016;2015;2014;2013;2012\right\}\)Tính A = x2016 - 2016.x2015 + 2016.x2014 - 2016.x2013 + ... + 2016x2 - 2016x +2016 tại x = 2015
x=2015
=> x+1=2016
=> A=x2016-(x+1).x2015+(x+1).x2014-(x+1).x2013+...+(x+1)x2-(x+1)x+2016
=x2016-x2016-x2015+x2015+x2014-x2014-x2013+...+x3+x2-x2-x+2016
=-x+2016
=-2015+2016
=1
Vậy A=1.
2012 + 2013 x 2014 / 2014 x 2015 -2016
2012 + 2013 x 2014 / 2014 x 2015 -2016 = 1
mình trả lời đầu tiên nha
bn giải tri tiết giùm mình được không
2013 x 2014 +2012 / 2015 x2015 -2016=4054182+2012 / 4058210 - 2016= 4056194/4056194=1
x^2013+y^2013=x^2014+y^2014=x^2015+y2015 tinh x^2016+y^2016
2012 +2013 X 2014 / 2014 X 2015-2016
\(\frac{2012+2013.2014}{2014.2015-2016}\)= \(\frac{2012+2013.2014}{2014.\left(2013+2\right)-2016}\) = \(\frac{2012+2013.2014}{2014.2013+2.2014-2016}\)= \(\frac{2012+2013.2014}{2014.2013+4028-2016}\)= \(\frac{2012+2013.2014}{2014.2013+2012}\)= \(1\)
2012 +2013 X 2014/2014X2015-2016=???????????//?????/
Tìm giá trị biểu thức x^2016-x^2015+x^2014-x^2013+...+x^2-2016 tại x = 2016
ai giải bài này giúp mk với
x+2016/2013 + x+2010/2014 + x+2010/2015 + x+2010/2016 + x+2010/2015 + x+2016/2018
\(\dfrac{x+2016}{2013}+\dfrac{x+2010}{2014}+\dfrac{x+2010}{2015}+\dfrac{x+2010}{2016}+\dfrac{x+2010}{2015}+\dfrac{x+2016}{2018}\)
Đề sai.
a, x+1/2013+x+1/2014+x+1/2015=x+1/2016+x+1/2017
b,x-1/2013+x-2/2014+x-3/2015=x-4/2016-2
x-1/2012+x-2/2013 +x-3/2014=x-4/2015+x-5/2016+x-6/2017
\(\dfrac{x-1}{2012}+\dfrac{x-2}{2013}+\dfrac{x-3}{2014}=\dfrac{x-4}{2015}+\dfrac{x-5}{2016}+\dfrac{x-6}{2017}\)
\(\Leftrightarrow\left(\dfrac{x-1}{2012}+1\right)+\left(\dfrac{x-2}{2013}+1\right)+\left(\dfrac{x-3}{2014}+1\right)=\left(\dfrac{x-4}{2015}+1\right)+\left(\dfrac{x-5}{2016}+1\right)+\left(\dfrac{x-6}{2017}+1\right)\)
\(\Leftrightarrow\dfrac{x+2011}{2012}+\dfrac{x+2011}{2013}+\dfrac{x+2011}{2014}-\dfrac{x+2011}{2015}-\dfrac{x+2011}{2016}-\dfrac{x+2011}{2017}=0\)
\(\Leftrightarrow\left(x+2011\right)\left(\dfrac{1}{2012}+\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2015}-\dfrac{1}{2016}-\dfrac{1}{2017}\right)=0\)
\(\Leftrightarrow x=-2011\)( do \(\dfrac{1}{2012}+\dfrac{1}{2013}+\dfrac{1}{2014}-\dfrac{1}{2015}-\dfrac{1}{2016}-\dfrac{1}{2017}\ne0\))