Chứng tỏ:
a/ \(\frac{5x^3+5x}{x^4-1}=\frac{5x}{x^3-1}\) b/ \(\frac{x^2+xy+y^2}{3x}=\frac{x^3-y^3}{3x^2-3xy}\)
Những câu hỏi liên quan
Bài 2: Rút gọn phân thứcAfrac{10x^2-7+5x-2xy}{1-2x^2+x}Bài 3: Chứng minh rằnga) frac{x^2y+2xy^2+y^3}{2x^2+xy-y^2}frac{xy+y^2}{2x-y}b) frac{x^2+3xy+2y^2}{x^3+2x^2y-xy^2-2y^3}frac{1}{x-y}Bài 4: Quy đồng mẫu thức các phân thức saua) frac{5x}{left(x+3right)^3}&frac{x-4}{3xleft(x+2right)^2}b) frac{x+1}{x-x^2}&frac{x+2}{2x^2+2-4x}
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Bài 2: Rút gọn phân thức
\(A=\frac{10x^2-7+5x-2xy}{1-2x^2+x}\)
Bài 3: Chứng minh rằng
a) \(\frac{x^2y+2xy^2+y^3}{2x^2+xy-y^2}=\frac{xy+y^2}{2x-y}\)
b) \(\frac{x^2+3xy+2y^2}{x^3+2x^2y-xy^2-2y^3}=\frac{1}{x-y}\)
Bài 4: Quy đồng mẫu thức các phân thức sau
a) \(\frac{5x}{\left(x+3\right)^3}\&\frac{x-4}{3x\left(x+2\right)^2}\)
b) \(\frac{x+1}{x-x^2}\&\frac{x+2}{2x^2+2-4x}\)
Ta có: \(\frac{x^2y+2xy^2+y^3}{2x^2+xy-y^2}\)
\(=\frac{x^2y+xy^2+xy^2+y^3}{2x^2+2xy-xy-y^2}\)
\(=\frac{xy\left(x+y\right)+y^2\left(x+y\right)}{2x\left(x+y\right)-y\left(x+y\right)}\)
\(=\frac{\left(x+y\right)\left(xy+y^2\right)}{\left(2x-y\right)\left(x+y\right)}=\frac{xy+y^2}{2x-y}\left(đpcm\right)\)
Ta có: \(\frac{x^2+3xy+2y^2}{x^3+2x^2y-xy^2-2y^3}\)
\(=\frac{x^2+xy+2xy+2y^2}{x^2\left(x+2y\right)-y^2\left(x+2y\right)}\)
\(=\frac{x\left(x+y\right)+2y\left(x+y\right)}{\left(x^2-y^2\right)\left(x+2y\right)}\)
\(=\frac{\left(x+2y\right)\left(x+y\right)}{\left(x+y\right)\left(x-y\right)\left(x+2y\right)}=\frac{1}{x-y}\left(đpcm\right)\)
bài 1: Thực hiện các phép tính
a.frac{4x-1}{3x^2y}-frac{7x-2}{3x^2y}
b.frac{4x+1}{2}-frac{3x+2}{3}
c.frac{5x^2-y^2}{xy}-frac{3x-2y}{y}
d.frac{3x}{5x+5y}-frac{x}{10x-10y}
e. frac{x+3}{x}-frac{x}{x-3}+frac{9}{x^2-3x}
f..frac{x+3}{x^2-1}-frac{1}{x^2+x}
g. frac{1}{3x-2}-frac{4}{3x+2}-frac{-10x+8}{9x^2-4}
h.frac{x+9y}{x^2-9y^2}-frac{3y}{x^2+3xy}
i.frac{3}{2x+6}-frac{x-6}{2x^2+6x}
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bài 1: Thực hiện các phép tính
a.\(\frac{4x-1}{3x^2y}-\frac{7x-2}{3x^2y}\)
b.\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
c.\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
d.\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
e. \(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
f..\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
g. \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
h.\(\frac{x+9y}{x^2-9y^2}-\frac{3y}{x^2+3xy}\)
i.\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
https://i.imgur.com/zwAtPMZ.jpg
B=\(\frac{-1}{2}xy+3x^2+\left(-2xy\right)+9-5x^2-\frac{1}{2}xy\)
C= \(5x^3-4xy+\left(\frac{-1}{3}x^3\right)-5xy-7x^2y\)
D= \(^{x^2y}-3xy+3x^2y-xy-\frac{1}{2}xy^2\)
bài này mình giải đc rồi các bạn k cần giải nữa đâu
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bài 1 : thực hiện các phép tính
a. frac{4x-1}{3x^2y}-frac{7x-1}{3x^2y}
b.frac{4x+1}{2}-frac{3x+2}{3}
c.frac{5x^2-y^2}{xy}-frac{3x-2y}{y}
d.frac{3x}{5x+5y}-frac{x}{10x-10y}
e.frac{x+3}{x}-frac{x}{x-3}+frac{9}{x^2-3x}
f.frac{x+3}{x^2-1}-frac{1}{x^2+x}
g.frac{1}{3x-2}-frac{4}{3x+2}-frac{-10x+8}{9x^2-4}
h.frac{x+9y}{x^2-9y^2}-frac{3y}{x^2+3xy}
i.frac{3}{2x+6}-frac{x-6}{2x^2+6x}
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bài 1 : thực hiện các phép tính
a. \(\frac{4x-1}{3x^2y}-\frac{7x-1}{3x^2y}\)
b.\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
c.\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
d.\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
e.\(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
f.\(\frac{x+3}{x^2-1}-\frac{1}{x^2+x}\)
g.\(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
h.\(\frac{x+9y}{x^2-9y^2}-\frac{3y}{x^2+3xy}\)
i.\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
https://i.imgur.com/VG57ZF2.jpg
https://i.imgur.com/RVF6CXo.jpg
Bài 1 :Thực hiện phép tính
a, frac{2x}{x^2+2xy}+frac{y}{xy-2y^2}+frac{4}{x^2-4y^2}
bfrac{1}{x-y}+frac{3xy}{y^3-x^3}+frac{x-y}{x^2+xy+y^2}
c, frac{xy}{2x-y}-frac{x^2-1}{y-2x}
d,frac{2left(x+yright)left(x-yright)}{x}-frac{-2y^2}{x}
Bài 2: Thực hiện phép tính
a,frac{4x+1}{2}-frac{3x+2}{3}
b,frac{x+3}{x}-frac{x}{x-3}+frac{9}{x^2-3x}
c,frac{x+3}{x^2+1}-frac{1}{x^2+2}
e,frac{3}{2x^2+2x}+frac{2x-1}{x^2-1}-frac{2}{x}
d,frac{1}{3x-2}-frac{4}{3x+2}-frac{-10x+8}{9x^2-4}
f,frac{3x}{5x+5y}-frac{x}...
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Bài 1 :Thực hiện phép tính
a, \(\frac{2x}{x^2+2xy}+\frac{y}{xy-2y^2}+\frac{4}{x^2-4y^2}\)
b\(\frac{1}{x-y}+\frac{3xy}{y^3-x^3}+\frac{x-y}{x^2+xy+y^2}\)
c, \(\frac{xy}{2x-y}-\frac{x^2-1}{y-2x}\)
d,\(\frac{2\left(x+y\right)\left(x-y\right)}{x}-\frac{-2y^2}{x}\)
Bài 2: Thực hiện phép tính
a,\(\frac{4x+1}{2}-\frac{3x+2}{3}\)
b,\(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
c,\(\frac{x+3}{x^2+1}-\frac{1}{x^2+2}\)
e,\(\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}\)
d,\(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
f,\(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
Bài 1:
a) Ta có: \(\frac{2x}{x^2+2xy}+\frac{y}{xy-2y^2}+\frac{4}{x^2-4y^2}\)
\(=\frac{2x}{x\left(x+2y\right)}+\frac{y}{y\left(x-2y\right)}+\frac{4}{\left(x-2y\right)\left(x+2y\right)}\)
\(=\frac{2}{x+2y}+\frac{y}{x-2y}+\frac{4}{\left(x-2y\right)\left(x+2y\right)}\)
\(=\frac{2\left(x-2y\right)}{\left(x+2y\right)\left(x-2y\right)}+\frac{y\left(x+2y\right)}{\left(x-2y\right)\left(x+2y\right)}+\frac{4}{\left(x-2y\right)\left(x+2y\right)}\)
\(=\frac{2x-4y+xy+2y^2+4}{\left(x-2y\right)\cdot\left(x+2y\right)}\)
b) Ta có: \(\frac{1}{x-y}+\frac{3xy}{y^3-x^3}+\frac{x-y}{x^2+xy+y^2}\)
\(=\frac{x^2+xy+y^2}{\left(x-y\right)\left(x^2+xy+y^2\right)}-\frac{3xy}{\left(x-y\right)\left(x^2+xy+y^2\right)}+\frac{\left(x-y\right)^2}{\left(x-y\right)\left(x^2+xy+y^2\right)}\)
\(=\frac{x^2+xy+y^2-3xy+x^2-2xy+y^2}{\left(x-y\right)\left(x^2+xy+y^2\right)}\)
\(=\frac{2x^2-4xy+2y^2}{\left(x-y\right)\left(x^2+xy+y^2\right)}\)
\(=\frac{2\left(x^2-2xy+y^2\right)}{\left(x-y\right)\left(x^2+xy+y^2\right)}\)
\(=\frac{2\left(x-y\right)^2}{\left(x-y\right)\left(x^2+xy+y^2\right)}\)
\(=\frac{2x-2y}{x^2+xy+y^2}\)
c) Ta có: \(\frac{xy}{2x-y}-\frac{x^2-1}{y-2x}\)
\(=\frac{xy}{2x-y}+\frac{x^2-1}{2x-y}\)
\(=\frac{x^2+xy-1}{2x-y}\)
d) Ta có: \(\frac{2\left(x+y\right)\left(x-y\right)}{x}-\frac{-2y^2}{x}\)
\(=\frac{2\left(x^2-y^2\right)+2y^2}{x}\)
\(=\frac{2x^2-2y^2+2y^2}{x}\)
\(=\frac{2x^2}{x}=2x\)
Bài 2:
a) Ta có: \(\frac{4x+1}{2}-\frac{3x+2}{3}\)
\(=\frac{3\left(4x+1\right)}{6}-\frac{2\left(3x+2\right)}{6}\)
\(=\frac{12x+3-6x-4}{6}\)
\(=\frac{6x-1}{6}\)
b) Ta có: \(\frac{x+3}{x}-\frac{x}{x-3}+\frac{9}{x^2-3x}\)
\(=\frac{\left(x+3\right)\left(x-3\right)}{x\left(x-3\right)}-\frac{x^2}{x\left(x-3\right)}+\frac{9}{x\left(x-3\right)}\)
\(=\frac{x^2-9-x^2+9}{x\left(x-3\right)}=\frac{0}{x\left(x-3\right)}=0\)
c) Ta có: \(\frac{x+3}{x^2+1}-\frac{1}{x^2+2}\)
\(=\frac{\left(x+3\right)\left(x^2+2\right)}{\left(x^2+1\right)\left(x^2+2\right)}-\frac{x^2+1}{\left(x^2+2\right)\left(x^2+1\right)}\)
\(=\frac{x^3+2x+3x^2+6-x^2-1}{\left(x^2+1\right)\left(x^2+2\right)}\)
\(=\frac{x^3+2x^2+2x+5}{\left(x^2+1\right)\left(x^2+2\right)}\)
e) Ta có: \(\frac{3}{2x^2+2x}+\frac{2x-1}{x^2-1}-\frac{2}{x}\)
\(=\frac{3}{2x\left(x+1\right)}+\frac{2x-1}{\left(x+1\right)\left(x-1\right)}-\frac{2}{x}\)
\(=\frac{3\left(x-1\right)}{2x\left(x+1\right)\left(x-1\right)}+\frac{2x\left(2x-1\right)}{2x\left(x+1\right)\left(x-1\right)}-\frac{2\cdot2\cdot\left(x+1\right)\left(x-1\right)}{2x\left(x+1\right)\left(x-1\right)}\)
\(=\frac{3x-3+4x^2-2x-4\left(x^2-1\right)}{2x\left(x+1\right)\left(x-1\right)}\)
\(=\frac{4x^2+x-3-4x^2+4}{2x\left(x+1\right)\left(x-1\right)}\)
\(=\frac{x+1}{2x\left(x+1\right)\left(x-1\right)}=\frac{1}{2x\left(x-1\right)}\)
d) Ta có: \(\frac{1}{3x-2}-\frac{4}{3x+2}-\frac{-10x+8}{9x^2-4}\)
\(=\frac{3x+2}{\left(3x-2\right)\left(3x+2\right)}-\frac{4\left(3x-2\right)}{\left(3x+2\right)\left(3x-2\right)}-\frac{-10x+8}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\frac{3x+2-12x+8+10x-8}{\left(3x-2\right)\left(3x+2\right)}\)
\(=\frac{x+2}{\left(3x-2\right)\left(3x+2\right)}\)
f) Ta có: \(\frac{3x}{5x+5y}-\frac{x}{10x-10y}\)
\(=\frac{3x}{5\left(x+y\right)}-\frac{x}{10\left(x-y\right)}\)
\(=\frac{3x\cdot2\cdot\left(x-y\right)}{10\left(x+y\right)\left(x-y\right)}-\frac{x\cdot\left(x+y\right)}{10\left(x-y\right)\left(x+y\right)}\)
\(=\frac{6x^2-6xy-x^2-xy}{10\left(x-y\right)\left(x+y\right)}\)
\(=\frac{5x^2-7xy}{10\left(x-y\right)\left(x+y\right)}\)
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Ai giúp em với ạ... em đang cần gấp ạ !!! em cảm ơn !
Câu 1: Giải phương trình cos2x-2sin23x+10
Câu 2: Giải hệ: _{^{ }frac{ }{ }frac{ }{ }frac{ }{ }left{{}begin{matrix}frac{2left(x^3+y^3right)}{xy}-frac{3left(x^{ }^2+y^2right)}{sqrt{xy}}+5left(x+yright)8sqrt{xy}sqrt{5x-1}+sqrt{2-y}frac{5x+y}{2}end{matrix}right.
Câu 3: Tìm nghiệm nguyên dương của phương trình: 2(x+y)+163xy
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Ai giúp em với ạ... em đang cần gấp ạ !!! em cảm ơn !
Câu 1: Giải phương trình cos2x-2sin23x+1=0
Câu 2: Giải hệ: \(_{^{ }\frac{ }{ }\frac{ }{ }\frac{ }{ }\left\{{}\begin{matrix}\frac{2\left(x^3+y^3\right)}{xy}-\frac{3\left(x^{ }^2+y^2\right)}{\sqrt{xy}}+5\left(x+y\right)=8\sqrt{xy}\\\sqrt{5x-1}+\sqrt{2-y}=\frac{5x+y}{2}\end{matrix}\right.\)
Câu 3: Tìm nghiệm nguyên dương của phương trình: 2(x+y)+16=3xy
8,Thực hiện phép tínha,frac{5x^2-y^2}{xy}-frac{3x-2y}{y}b,frac{3}{2x+6}-frac{x-6}{2x^2+6x}c,frac{2x}{x^2+2xy}+frac{y}{xy-2y^2}+frac{4}{x^2-4y^2} d,frac{1}{x-y}+frac{3xy}{y^3-x^3}+frac{x-y}{x^2+xy+y^2} e,frac{2x+y}{2x^2-xy}+frac{16x}{y^2-4x^2}+frac{2x-y}{2x^2+xy} f,frac{1}{1-x}+frac{1}{1+x}+frac{2}{1+x^2}+frac{4}{1+x^4}+frac{8}{1+x^8}+frac{16}{1+x^{16}}
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8,Thực hiện phép tính
a,\(\frac{5x^2-y^2}{xy}-\frac{3x-2y}{y}\)
b,\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
c,\(\frac{2x}{x^2+2xy}+\frac{y}{xy-2y^2}+\frac{4}{x^2-4y^2}\)
d,\(\frac{1}{x-y}+\frac{3xy}{y^3-x^3}+\frac{x-y}{x^2+xy+y^2}\)
e,\(\frac{2x+y}{2x^2-xy}+\frac{16x}{y^2-4x^2}+\frac{2x-y}{2x^2+xy}\)
f,\(\frac{1}{1-x}+\frac{1}{1+x}+\frac{2}{1+x^2}+\frac{4}{1+x^4}+\frac{8}{1+x^8}+\frac{16}{1+x^{16}}\)
Bài 1: Tìm x,y biết :
a) \(\frac{2x+3}{5x+2}=\frac{4x+5}{10x+2}\)
b)\(\frac{3x-1}{40-5x}=\frac{25-3x}{5x-34}\)
Bài 2: Timd x,y,z biết:
a)\(5x=-10y=6zvàxyz=-30000\)
b)\(\frac{x-y}{3}=\frac{x+y}{13}=\frac{xy}{200}\)
\(\frac{x-3}{3xy}\)+ \(\frac{5x+3}{3xy}\)
\(\frac{5x-7}{2x-3}+\frac{4-3x}{2x-3}\)
\(\frac{3x+5}{7x-1}-\frac{6-4x}{7x-1}\)
\(\frac{11x-7}{3-5x}-\frac{6x+4}{5x-3}\)
\(\frac{3}{2x+6}-\frac{x-6}{2x^2+6x}\)
\(\frac{1}{2x-10}+\frac{2x}{3x^2-15x}\)
1/ \(\frac{x-3}{3xy}\)+\(\frac{5x+3}{3xy}\)= \(\frac{6x}{3xy}\)=\(\frac{3}{y}\)
2/\(\frac{5x-7}{2x-3}\)+\(\frac{4-3x}{2x-3}\)=\(\frac{2x-3}{2x-3}\)=1
3/\(\frac{11x-7}{3-5x}\)-\(\frac{6x+4}{5x-3}\)=\(\frac{11x-7}{3-5x}\)+\(\frac{6x+4}{3-5x}\)=\(\frac{17x-3}{3-5x}\)
4/\(\frac{3}{2x+6}\)-\(\frac{x-6}{2x^2+6x}\)=\(\frac{3x}{x\left(2x+6\right)}\)-\(\frac{x-6}{x\left(2x+6\right)}\)=\(\frac{2x-6}{x\left(2x+6\right)}\)
5/\(\frac{1}{2x-10}\)+\(\frac{2x}{3x^2-15x}\)=\(\frac{1}{2\left(x-5\right)}\)+\(\frac{2x}{3x\left(x-5\right)}\)=\(\frac{3x}{6x \left(x-5\right)}\)+\(\frac{4x}{6x\left(x-5\right)}\)
=\(\frac{7x}{6x\left(x-5\right)}\)=\(\frac{7}{6\left(x-5\right)}\)
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