5 x 100
[-2083/100 x 2/10+-917/100 x 2/10] : [247/100 x 5/10--(-353)/100 x 5/10] = ?
Tính nhanh đó
Tính giá trị :
a) 100 x 15 + 100 x 95 - 100 x 10
b) 8 : 4 x 5 + 15 - 5
a) 100 x 15 + 100 x 95 -100 x10
= 100 x ( 15 +95 - 10 )
= 100 x 100
= 10000
b) 8: 4 x 5 + 15-5
= 2 x 5 + 15-5
= 10+15 -5
= 25-5
= 20
a) 100x15+100x95-100x10
=100x(15+95-10)
=100x100
=10000
mik chỉ làm 1 phần thôi nha
k mik nha cac bạn
a) 100 x 15 + 100 x 95 - 100 x 10
= 100 x (15+95-10)
= 100 x 100
= 10000
b) 8 : 4 x 5 + 15 - 5
=2 x5 + 10
=10+10
= 20
[x-5] x 30/100= 200x : 100+5
(x-5) x \(\frac{30}{100}\)= 200x : 100 + 5
(x-5) x \(\frac{3}{10}\)= 200x : 100 + 5
\(\frac{x.3-15}{10}\)= 2x + 5
\(\frac{x.3-15}{10}-2x=5\)
\(\frac{x.3-15}{10}-\frac{20x}{10}=5\)
\(\frac{3x-15-20x}{10}=5\)
3x - 20x - 15 = 50
-17x - 15 = 50
-17x = 65
x = 65 : -17
x = \(\frac{-65}{17}\)
100 x 1 = ?
100 x 2 = ?
100 x 3 = ?
100 x 4 = ?
100 x 5 = ?
100.1=100
100.2=200
100.3=300
100.4=400
100.5=500
100 x 1 = 100
100 x 2 = 200
100 x 3 = 300
100 x 4 = 400
100 x 5 = 500
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tìm x:
x - 10 + 5 = 100 ; x + 10 - 5 = 100
x-10+5=100
x-10=100-5
x-10=95
x=95+10
x=105
tìm x:
a
x - 10 + 5 = 100
x - 10 =100-5=95
x=95+10=105
b
x + 10 - 5 = 100
x + 10 = 100 + 5 = 105
x = 105 - 10 = 95
tích mik ủng hộ nha bà con cô bác ơi
tìm x:
a
x - 10 + 5 = 100
x - 10 =100-5=95
x=95+10=105
b
x + 10 - 5 = 100
x + 10 = 100 + 5 = 105
x = 105 - 10 = 95
tích mik ủng hộ nha bà con cô bác ơi
a,x-5/100+x-4/101+x-3/102=x-100/5+x-101/4+x-102/3
=>\(\dfrac{x-5}{100}-1+\dfrac{x-4}{101}-1+\dfrac{x-3}{102}-1=\dfrac{x-100}{5}-1+\dfrac{x-101}{4}-1+\dfrac{x-102}{3}-1\)
=>x-105=0
=>x=105
a/ (x - 1 5 ) - 3 5 = 5 8 b/ x - 7 100 = 1 100 + 1
a) \(\left(x-15\right)-35=58\)
\(x-15=58+35\)
\(x-15=93\)
\(x=93+15\)
\(x=108\)
b) \(x-7100=1100+1\)
\(x-7100=1101\)
\(x=1101+7100\)
\(x=8201\)
TÌM X biết:
(x-5).30/100= 20 X 100 +5
(x-5).3/10=2000+5
(x-5).3/10=2005
x-5=2005:3/10
x-5=2005.10/3
x-5=20050/3
x=20050/3 +5
x=20065/3
\(\left(x-5\right)\)\(.\)\(\frac{30}{100}\)\(=\)\(20\times100+5\)
\(\left(x-5\right)\)\(.\)\(\frac{3}{10}\)\(=\)\(2005\)
\(\left(x-5\right)\)\(=\)\(2005\)\(\div\)\(\frac{3}{10}\)
\(\left(x-5\right)\)\(=\)\(2005\)\(.\)\(\frac{10}{3}\)
\(\left(x-5\right)\)\(=\)\(\frac{20050}{3}\)
\(x=\frac{20055}{3}\)
Hok tốt
(x-5).30/100=20x/100+5
tìm x biết :(x-5)30/100=20x/100+5
Ta có thể viết thành: (x - 5)3/10 = x/5 + 5
Nhân hai vế với 10, ta có : 3(x - 5) = (x/5 + 5) * 10
3x - 15 = 2x + 50
3x = 2x + 50 = 2x + 65
3x - 2x = 65
x = 65
Chúc bạn ht ~~