rut gon:
N=2(2x + 5 )^2 - 3(1 + 4x )(1 - 4x)
(4x-3)(3x+2)-(6x+1)(2x-5)+1
rut gon bieu thuc
12x2 + 8x - 9x - 6 - 12x2 + 30x + 2x -5 + 1= 31x - 10
rut gon (x^2+2x+1)\(x-1)^2:(2x^2+4x+2)\(4x^2-8x+4)
\(=\frac{\left(x+1\right)^2}{\left(x-1\right)^2}:\frac{2\left(x+1\right)^2}{4\left(x-1\right)^2}=\frac{\left(x+1\right)^2}{\left(x-1\right)^2}.\frac{4\left(x-1\right)^2}{2\left(x+1\right)^2}=2\)
rut gọn 2x(2 x-1)^2-3x(x+3)(x-3) -4x(x+1)^2
Ta có:
2x(2x-1)2-3x(x+3)(x-3)-4x(x+1)2
=2x(4x2-4x+1)-3x(x2-9)-4x(x2+2x+1)
=8x3-8x2+2x-3x3+27x-4x3-8x2+4x
=x3-16x2 +33x
Rut gon bt
\(A=[\frac{(x-1)^2}{x^2+x+1}-\frac{1+4x-2x^2}{x^3-1}-\frac{1}{1-x}]^2:\frac{8x^3+1}{8x^2-4x+2}\)
Rut gon A=3x^3-7x^2+5x-1 / 2x^3-x^2-4x+3
Cho biểu thức A =(x+5)(4-3x)-(3x+2)^2+(2x+1)^3-(2x-1)(4x^2+2x+1)
a) Rut gọn bthức A
b) Tính A khi x=-3
c) Tìm x để A=0
Rut gon bieu thuc sau: 2x*(2x-1)2-3x*(x+3)2-4x*(x+1)2
rut gon bieu thuc a,(3x+2)^2+4x-3^2+2(5x-2)(5x+2)-75x^2
b,(x-2)^3+(2x+1)^3++2(x+2)(1-x)-9x^3+2x
a: \(\left(3x+2\right)^2+4x-3x^2+2\left(5x-2\right)\left(5x+2\right)-75x^2\)
\(=9x^2+12x+4+4x-3x^2+50x^2-8-75x^2\)
\(=-19x^2+16x-4\)
rut gon cac bieu thuc
2x(2x+1)2 - 3x(x+3)(x-3) - 4x (x+1) 2
Ta có 2x(2x + 1)2 - 3x(x + 3)(x - 3) - 4x(x + 1)2
= 2x(4x2 + 4x + 1) - 3x(x2 - 9) - 4x(x2 + 2x + 1)
= 8x3 + 8x2 + 2x - 3x3 + 27x - 4x3 - 8x2 - 4x
= 8x3 - 3x3 - 4x3 + 8x2 - 8x2 + 2x + 27x - 4x
= x3 + 25x
a oi hinh nhu sai r con +16x2 nua co a , anh tinh lai ho e duoc kh
Kiều Trinh Vũ ko có + 16x2 nhá vì 8x2 - 8x2 = 0 nhá