4/3/4-0,37+1/8-1,28-2,5+3/1/1
4/3/4+(-0,37)+1/8+(-1,28)+(-2,5)+3/1/12
Ta có:
\(\text{4/3/4+(-0,37)+1/8+(-1,28)+(-2,5)+3/1/12}\)
\(=4:4:3-0,37+1:8-1,28-2,5+3:1:12\)
\(=\frac{1}{3}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{1}{4}\)
\(=\frac{200}{600}-\frac{222}{600}+\frac{75}{600}-\frac{768}{600}-\frac{1500}{600}+\frac{150}{600}\)
\(=\frac{200-222+75-768-1500+150}{600}\)
\(=-\frac{2065}{600}\)
\(=-\frac{413}{120}\)
Tính \\(B=4\\dfrac{3}{4}+\\left(-0,37\\right)+\\dfrac{1}{8}=\\left(-1,28\\right)+\\left(-2,5\\right)+3\\dfrac{1}{2}\\)
\(4\frac{3}{4}\)+(-0,37)+\(\frac{1}{8}\)+(-1,28)+(-2,5)+\(3\frac{1}{12}\)
\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{12}\)
\(=4,75-0,37+0,125-1,28-2,5+\frac{37}{12}\)
\(=0,725+\frac{37}{12}\)
\(=\frac{457}{120}\)
\(4\frac{3}{4}+\left(-0,37\right)+\frac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\frac{1}{2}\)
tính theo 2 cách
\(\frac{19}{4}-\frac{37}{100}+\frac{1}{8}-\frac{32}{25}-\frac{5}{2}+\frac{7}{2}=\left(\frac{19}{4}-\frac{37}{100}-\frac{32}{25}\right)+\left(\frac{7}{2}-\frac{5}{2}\right)+\frac{1}{8}=\frac{31}{10}+1+\frac{1}{8}=\frac{169}{40}\)
\(4\frac{3}{4}\)+(-0,37)+\(\frac{1}{8}\)(-1,28)+(-2,5)+\(3\frac{1}{2}\)
tính theo 2 cách
tính 2 cách
a)4/3/4+(−0,37)+1/8+(−1,28)+(−2,5)+3/1/2)
b)5/22+3/13−1/2trên 4/13−2/11+3/2
tính 2 cách
a)4/3/4+(−0,37)+1/8+(−1,28)+(−2,5)+3/1/2)
b)5/22+3/13−1/2trên 4/13−2/11+3/2
Tính một cách hợp lý:
3\(\frac{4}{4}\)+ (-0,37) +\(\frac{1}{8}\)+ (-1,28) + (-2,5) + 3\(\frac{1}{12}\)
\(\left(4\frac{3}{4}+\frac{1}{8}+3\frac{1}{12}\right)-\left(0,37+1,28+2,25\right)\)
\(=7\frac{23}{24}-4,15\)
\(=7\frac{23}{24}-4\frac{3}{20}\)
\(=3\frac{97}{120}\)
Tính một cách hợp lý:
\(4\dfrac{3}{4}+\left(-0,37\right)+\dfrac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\dfrac{1}{12}\)
\(4\dfrac{3}{4}+\left(-0,37\right)+\dfrac{1}{8}+\left(-1,28\right)+\left(-2,5\right)+3\dfrac{1}{12}\)
\(=\dfrac{19}{4}+-\dfrac{37}{100}+\dfrac{1}{8}+-\dfrac{32}{25}+-\dfrac{5}{2}+\dfrac{37}{12}\)
\(=\dfrac{219}{50}+\dfrac{1}{8}+-\dfrac{32}{25}+-\dfrac{5}{2}+\dfrac{37}{12}\)
\(=\dfrac{901}{200}+-\dfrac{32}{25}+-\dfrac{5}{2}+\dfrac{37}{12}\)
\(=\dfrac{129}{40}+-\dfrac{5}{2}+\dfrac{37}{12}\)
\(=\dfrac{29}{40}+\dfrac{37}{12}\)
\(=\dfrac{457}{120}\)
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