\(2^4.5-\left[131-\left(13-4\right).2\right]\)

\(=16.5-\left(131-9.2\right)\)

\(=80-\left(131-18\right)\)

\(=80-113\)

\(=-33\)

\(2^4.5-\left(131-\left(13-4\right).2\right)\)

\(=16.5-\left(131-18\right)\)

\(=80-118\)

\(=-33\)

2⁴ x 5 - [ 131 - ( 13 - 4 ) 2 ] =

= 16 x 5 - [ 131 - 9 x 2 ]

= 80 - [ 131 - 18 ]

= 80 - 113

= -33

a) 27.(-17)+(-17).73

= -17 ( 27+73)

= -17 . 100

= -1700

b) 512 . ( 2- 128) -128. (-512)

= 512.(2-128) - (-128).512

= 512(2-128+128)

= 512 . 2

= 1024

Phan Bá Cường đúng rồi đó Nguyễn Thị Hồng.

a. -1700

b.1024

\(\left(1-\frac{1}{2}\right)\cdot\left(1-\frac{1}{3}\right)\cdot\left(1-\frac{1}{4}\right)\cdot\left(1-\frac{1}{5}\right)\cdot....\cdot\left(1-\frac{1}{2003}\right)\cdot\left(1-\frac{1}{2004}\right)\)

\(=\frac{1}{2}\cdot\frac{2}{3}\cdot\frac{3}{4}\cdot\frac{4}{5}\cdot....\cdot\frac{2002}{2003}\cdot\frac{2003}{2004}\)

\(=\frac{1\cdot2\cdot3\cdot4\cdot....\cdot2002\cdot2003}{2\cdot3\cdot4\cdot5\cdot....\cdot2003\cdot2004}\)

\(=\frac{1}{2004}\)

phân số thứ nhất bằng 0/2 =0

vậy tích đó chắc chắn bằng 0

chuẩn ko mn?

a: \(=-\left(10x^2+15x-8x-12\right)=-10x^2-7x+12\)

-10x^2-7x+12

= 12-7x-10x^2

1/2*3+1/3*4+1/4*5 + 1/5*6 + .... + 1/99 * 100

= 1/2 -1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 +..... + 1/99 - 1/100

= 1/2 - 1/100 

= 49/100 nha bạn !

1/2x3+1/3x4+1/4x5+1/5x6+....+1/99x100

=1/2-1/3+1/3-1/4+1/4-1/5+1/5-1/6+....+1/99-1/100

=1/2-1/100=49/100

1/2*3+1/3*4+1/4*5 + 1/5*6 + .... + 1/99 * 100

= 1/2 -1/3 + 1/3 - 1/4 + 1/4 - 1/5 + 1/5 - 1/6 +..... + 1/99 - 1/100

= 1/2 - 1/100 

= 49/100

Đúng rồi nha bạn !

\(3^2\cdot5+2^3\cdot10-3^4:3\\ =9\cdot5+8\cdot10-3^4\\ =45+80-27\\ =98\)

\(3^2.5+2^3.10-3^4:3\)

\(=9.5+8.10-3^3\)

\(=45+80-27\)

\(=125-27\)

\(=98\)

\(#WendyDang\)

Anh ơi, dòng 2 ( \(3^4:3\) thì ra \(3^3\) -> a mới đổi thành được \(27\) chứ ạ? )

=2⁷ - 7²⁰²² 

=2⁷ - 7²⁰²² 

B=\(\left[\left(\frac{1}{3}+\frac{1}{4}\right)x\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)

B=\(\left(\frac{7}{12}x\frac{12}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)

B=\(\left(\frac{7}{19}+\frac{12}{19}\right):\frac{4}{5}-\frac{1}{4}+2012\)

B=\(\frac{5}{4}-\frac{1}{4}+2012\)

B=1+2012

B=2013

\(B=[\left(\frac{1}{3}+\frac{1}{4}\right)\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=[\frac{7}{12}\times\frac{12}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=[\frac{7}{19}+\frac{12}{19}]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=1:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=\frac{5}{4}-\frac{1}{4}+2012\)

\(B=1+2012\)

\(B=2013\)

\(B=\left[\left(\frac{1}{3}+\frac{1}{4}\right)\times\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=\left[\frac{7}{12}\times\frac{12}{19}+\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=\left[\left(\frac{7}{12}+1\right)\times\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=\left[\frac{19}{12}\times\frac{12}{19}\right]:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=1:\frac{4}{5}-\frac{1}{4}+2012\)

\(B=\frac{5}{4}-\frac{1}{4}+2012\)

\(B=1+2012\)

\(B=2013\)

Vậy B = 2013

_Chúc bạn học tốt_