1/6+2/3x8/9
3/4+3=.....
5/2x4=.....
2-7/8=.....
9/4-2=.....
5:5/7=.....
5/6:2/7=.....
1/6+2/3x8/9=.....
1/6+2/3:4/5=.....
Cách giải nữa nha các bạn!!!!!
3/4+3= 3/4+12/4=15/4
5/2 x 4 =5 x 4/2 = 20/2 = 10
2-7/8=16/8-7/8=9/8
9/4-2=9/4-8/4=1/4
5: 5/7=5 x 7/5= 35/5=7
5/6:2/7=5/6 x 7/2 = 35/12
1/6+2/3 x 8/9= 1/6+ 16/18= 3/18+16/18=19/18
1/6 + 2/3 : 4/5 = 1/6+ 2/3 x 5/4= 1/6+5/6=6/6=1
đúng cho mình nhé
3/4:2/3x8/9
(1+1/2+1/3+....+1/9+1/10)/ (1/1x10+1/2x9+1/3x8+....+1/8x3+1/9x2+1/10x1)
Tính nhanh
Ta có: \(\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{10\times1}\)
\(=2\times\left(\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{5\times6}\right)\)
\(=\frac{2}{11}\times\left(\frac{11}{1\times10}+\frac{11}{2\times9}+\cdots+\frac{11}{5\times6}\right)\)
\(=\frac{2}{11}\times\left(1+\frac12+\frac13+\cdots+\frac19+\frac{1}{10}\right)\)
Ta có: \(A=\frac{1+\frac12+\cdots+\frac{1}{10}}{\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{9\times2}+\frac{1}{10\times1}}\)
\(=\frac{1+\frac12+\cdots+\frac{1}{10}}{\frac{2}{11}\times\left(1+\frac12+\cdots+\frac{1}{10}\right)}=1:\frac{2}{11}=\frac{11}{2}\)
(1+1/2+1/3+....+1/9+1/10)/ (1/1x10+1/2x9+1/3x8+....+1/8x3+1/9x2+1/10x1)
Tính nhanh
5/12+1/3x8 -1/6
\(\dfrac{5}{12}+\dfrac{1}{3.8}-\dfrac{1}{6}\)
\(=\dfrac{5}{12}+\dfrac{1}{24}-\dfrac{1}{6}\)
\(=\dfrac{10}{24}+\dfrac{1}{24}-\dfrac{4}{24}\)
\(=\dfrac{11}{24}-\dfrac{4}{24}\)
\(=\dfrac{7}{24}\)
5/12+1/3x8 -1/6
= 5/12+8/3 - 1/6
= 37/12 - 1/6
= 35/12
2^15x9^4/6^3x8^3
Ý bạn là như thế này
\(2^{15}.\frac{9^4}{6^3}.8^3=2^{15}\frac{3^8}{3^3.2^3}.2^9=2^{24}.3^5:2^3=2^{21}.3^5=509607936\)
Hay là thế này
\(\frac{2^{15}.9^4}{6^3.8^3}=\frac{2^{15}.3^8}{3^3.2^3.2^9}=\frac{2^{15}.3^8}{3^3.2^{11}}=2^4.3^5=3888\)
Cái nào trong số này là ý của bạn
Cách làm như bạn kia nhưng khi làm bạn ấy làm sai 9 + 3 = 11 ? Thế là kết quả phải ra 1944
2^15x9^4 phần 6^3x8^3
\(\frac{2^{15}.9^4}{6^3.8^3}\)
\(=\frac{2^{15}.\left(3^2\right)^4}{\left(2.3\right)^3.\left(2^3\right)^3}\)
\(=\frac{2^{15}.3^8}{\left(2^3.2^9\right).3^3}\)
\(=\frac{2^{15}.3^8}{2^{12}.3^3}\)
\(=2^3.3^5=8.243=1944\)
\(\dfrac{1+3+6+10+...+45+55}{1x10+9x2+3x8+...9x2+10x1}\)
Ta có: \(1+3+6+10+\cdots+45+55\)
\(=\frac12\times\left(2+6+12+20+\cdots+90+110\right)\)
\(=\frac12\times\left(1\times2+2\times3+\cdots+9\times10+10\times11\right)\)
\(=\frac12\times\left\lbrack1\times\left(1+1\right)+2\times\left(2+1\right)+\cdots+10\times\left(10+1\right)\right\rbrack\)
\(=\frac12\times\left\lbrack\left(1\times1+2\times2+\cdots+10\times10\right)+\left(1+2+\cdots+10\right)\right\rbrack\)
\(=\frac12\times\left\lbrack10\times\left(10+1\right)\times\frac{\left(2\times10+1\right)}{6}+10\times\frac{11}{2}\right\rbrack\)
\(=\frac12\times\left\lbrack10\times11\times\frac{21}{6}+5\times11\right\rbrack=\frac12\times\left\lbrack5\times11\times7+5\times11\right\rbrack\)
\(=\frac12\times5\times11\times\left(7+1\right)=\frac{55}{2}\times8=55\times4=220\)
Ta có: \(1\times10+9\times2+\cdots+10\times1\)
\(=2\times\left(1\times10+2\times9+3\times8+4\times7+5\times6\right)\)
\(=2\times\left\lbrack1\times\left(11-1\right)+2\times\left(11-2\right)+3\times\left(11-3\right)+4\times\left(11-4\right)+5\times\left(11-5\right)\right\rbrack\)
\(=2\times\left\lbrack11\times\left(1+2+3+4+5\right)-\left(1\times1+2\times2+3\times3+4\times4+5\times5\right)\right\rbrack\)
\(=2\times\left\lbrack11\times15-\left(1+4+9+16+25\right)\right\rbrack\)
=2x(165-55)
=2x110
=220
Ta có: \(\frac{1\times10+9\times2+\cdots+10\times1}{1+3+6+10+\cdots+45+55}\)
\(=\frac{220}{220}\)
=1
\(A=\dfrac{1+\dfrac{1}{2}+\dfrac{1}{3}+\dfrac{1}{4}+...+\dfrac{1}{9}+\dfrac{1}{10}}{\dfrac{1}{1x10}+\dfrac{1}{2x9}+\dfrac{1}{3x8}+...+\dfrac{1}{8x3}+\dfrac{1}{9x2}+\dfrac{1}{10x1}}\)
Ta có: \(\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{10\times1}\)
\(=2\times\left(\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{5\times6}\right)\)
\(=\frac{2}{11}\times\left(\frac{11}{1\times10}+\frac{11}{2\times9}+\cdots+\frac{11}{5\times6}\right)\)
\(=\frac{2}{11}\times\left(1+\frac12+\frac13+\cdots+\frac19+\frac{1}{10}\right)\)
Ta có: \(A=\frac{1+\frac12+\cdots+\frac{1}{10}}{\frac{1}{1\times10}+\frac{1}{2\times9}+\cdots+\frac{1}{9\times2}+\frac{1}{10\times1}}\)
\(=\frac{1+\frac12+\cdots+\frac{1}{10}}{\frac{2}{11}\times\left(1+\frac12+\cdots+\frac{1}{10}\right)}=1:\frac{2}{11}=\frac{11}{2}\)