\(\sqrt{\frac{16}{36}}+\sqrt{\frac{9}{49}}+\sqrt{\frac{121}{25}}\)
Những câu hỏi liên quan
Tính
a) \(2\sqrt{\frac{25}{16}}-3\sqrt{\frac{49}{36}}+4\sqrt{\frac{81}{64}}\)
b) \(\left(3\sqrt{2}\right)^2-\left(4\sqrt{\frac{1}{2}}\right)^2+\frac{1}{16}.\left(\sqrt{\frac{3}{4}}\right)^2\)
c) \(\frac{2}{3}\sqrt{\frac{81}{16}}-\frac{3}{4}\sqrt{\frac{64}{9}}+\frac{7}{5}.\sqrt{\frac{25}{196}}\)
a) = \(\frac{7}{2}\)
b) = \(\frac{643}{64}\)
c) = 0
Đúng 0
Bình luận (0)
a) sqrt{9}+sqrt{4} b) sqrt{0,25}-sqrt{0,01} c) sqrt{frac{16}{25}}-sqrt{frac{1}{81}} d) 2-sqrt{0,36}2. a) sqrt{64}-sqrt{16}+sqrt{left(-3^2right)} b) sqrt{121}+sqrt{left(-5right)^2}-sqrt{9}c) sqrt{frac{9}{4}}-sqrt{frac{16}{36}}-sqrt{49} d) sqrt{left(-4right)^2}+sqrt{left(-5right)^2}-sqrt{left(-6right)^2}
Đọc tiếp
a) \(\sqrt{9}+\sqrt{4}\) b) \(\sqrt{0,25}-\sqrt{0,01}\) c) \(\sqrt{\frac{16}{25}}-\sqrt{\frac{1}{81}}\) d) \(2-\sqrt{0,36}\)
2. a) \(\sqrt{64}-\sqrt{16}+\sqrt{\left(-3^2\right)}\) b) \(\sqrt{121}+\sqrt{\left(-5\right)^2}-\sqrt{9}\)
c) \(\sqrt{\frac{9}{4}}-\sqrt{\frac{16}{36}}-\sqrt{49}\) d) \(\sqrt{\left(-4\right)^2}+\sqrt{\left(-5\right)^2}-\sqrt{\left(-6\right)^2}\)
1. a) 3+2=5
b) 0,5-0,1=0,4
c) 4/5-1/9=31/45
d) 2-0,6=1,4
2. a) 8-4+3=7
b) 11+5-3=13
c) 3/2-4/6-7-37/6
d) 4+5-6=3
Đúng 0
Bình luận (0)
A = \(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
B = \(\sqrt{4+36+81}\)
C = \(\sqrt{1^{3^{ }}+}2^3\)
E = \(\left(\sqrt{\frac{1}{9}+\sqrt{\frac{25}{36}-\sqrt{\frac{49}{81}}:}\sqrt{\frac{441}{324}}}\right)\)
F = \(-4.\sqrt{\frac{1}{16}+3.\sqrt{\frac{1}{9}}-}5.\sqrt{0,04}\)
Mg các bạn giúp mik ạ
Cảm ơn ạ
\(\sqrt{\frac{1}{9}+\frac{1}{16}}\)
\(=\frac{1}{3}+\frac{1}{4}\)
\(=\frac{7}{12}\)
\(\sqrt{4+36+81}\)
\(=\sqrt{121}\)
\(=\pm11\)
\(\sqrt{1^3}+2^3\)
\(=\sqrt{1}+8\)
\(=1+8\)
\(=9\)
Xem thêm câu trả lời
Cho y=\(\frac{1+\sqrt{x}}{1-\sqrt{x}}\)
Cmr Với mọi x thuộc A=\((\frac{16}{9};\frac{25}{16};\frac{49}{36};\frac{100}{81})\)
thì y thuộc Z
Trong các số sau đây số nào có căn bậc hai cho biết căn bậc hai không âm của số đó :
36 ; -3600 ; - 0,125 ; 36/49 ; 121 ; 0,04 ; \(\sqrt{\frac{16}{81}}\); \(\sqrt{\frac{49}{9}}\)
cây kiếm hay cây rùi nặng hơn vậy
Giúp mik với
Tính
a)\(\frac{2}{3}\sqrt{81}-\left(\frac{-3}{4}\right).\sqrt{\frac{9}{64}}+\left(\frac{\sqrt{2}}{3}\right)^2\)
b)\(\left(-\sqrt{\frac{5}{4}}\right)^2-\sqrt{\frac{9}{4}}:\left(-4,5\right)-\sqrt{\frac{25}{16}}.\sqrt{\frac{64}{9}}\)
c)\(-2^4-\left(-2\right)^2:\left(-\sqrt{\frac{16}{121}}\right)-\left(-\sqrt{\frac{2}{3}}\right)^2:\left(-2\frac{2}{3}\right)\)
Rút gọn biểu thức:
a)\(\sqrt{\frac{25}{81}\cdot\frac{16}{49}\cdot\frac{169}{9}}\)
b) \(\sqrt{3\frac{1}{16}\cdot2\frac{14}{25}\cdot2\frac{34}{81}}\)
a) \(\sqrt{\frac{25}{81}\cdot\frac{16}{49}\cdot\frac{169}{9}}\\ =\sqrt{\left(\frac{5}{9}\right)^2\cdot\left(\frac{4}{7}\right)^2\cdot\left(\frac{13}{3}\right)^2}\\ =\sqrt{\left(\frac{5}{9}\cdot\frac{4}{7}\cdot\frac{13}{3}\right)^2}\\ =\frac{5}{9}\cdot\frac{4}{7}\cdot\frac{13}{3}\\ =\frac{260}{189}\)
b) \(\sqrt{3\frac{1}{6}\cdot2\frac{14}{25}\cdot2\frac{34}{81}}\\ =\sqrt{\frac{19}{6}\cdot\frac{64}{25}\cdot\frac{196}{81}}\\ =\sqrt{\frac{19}{6}\cdot\left(\frac{8}{5}\right)^2\cdot\left(\frac{14}{9}\right)^2}\\ =\sqrt{\frac{19}{6}\cdot\left(\frac{8}{5}\cdot\frac{14}{9}\right)^2}\\ =\sqrt{\frac{19}{6}\cdot\frac{112}{45}}\\ =\sqrt{\frac{1064}{135}}\)
Đúng 0
Bình luận (1)
Bổ sung câu b :
\(\sqrt{3\frac{1}{16}.2\frac{14}{25}.2\frac{34}{81}}=\sqrt{\frac{49}{16}.\frac{64}{25}.\frac{196}{81}}=\sqrt{\frac{49}{16}}.\sqrt{\frac{64}{25}}.\sqrt{\frac{196}{81}}=\frac{7}{4}.\frac{8}{5}.\frac{14}{9}=\frac{196}{45}\)
Đúng 0
Bình luận (0)
Bạn kia làm sai nhé :
a) \(\sqrt{\frac{25}{81}.\frac{16}{49}.\frac{169}{9}}=\sqrt{\frac{25}{81}}.\sqrt{\frac{16}{49}}.\sqrt{\frac{169}{9}}=\frac{5}{9}.\frac{4}{7}.\frac{13}{3}=\frac{260}{189}\)
Đúng 0
Bình luận (3)
Choxleft(1+frac{1}{sqrt{1}}right)+left(1+frac{1}{sqrt{9}}right)+left(frac{1}{sqrt{25}}right)+left(1+frac{1}{sqrt{49}}right)+left(1+frac{1}{sqrt{81}}right) yleft(1+frac{1}{sqrt{4}}right)+left(1+frac{1}{sqrt{16}}right)+left(1+frac{1}{sqrt{36}}right)+left(1+frac{1}{sqrt{64}}right)+left(1+frac{1}{sqrt{100}}right)Tính x.yMn ơi, giúp mk nha, mai mk nộp òi!
Đọc tiếp
\(Cho\)\(x=\left(1+\frac{1}{\sqrt{1}}\right)+\left(1+\frac{1}{\sqrt{9}}\right)+\left(\frac{1}{\sqrt{25}}\right)+\left(1+\frac{1}{\sqrt{49}}\right)+\left(1+\frac{1}{\sqrt{81}}\right)\)
\(y=\left(1+\frac{1}{\sqrt{4}}\right)+\left(1+\frac{1}{\sqrt{16}}\right)+\left(1+\frac{1}{\sqrt{36}}\right)+\left(1+\frac{1}{\sqrt{64}}\right)+\left(1+\frac{1}{\sqrt{100}}\right)\)
Tính x.y
Mn ơi, giúp mk nha, mai mk nộp òi!
=(1/1+1/3+1/5+1/7+1/9).(1/2+1/4+1/6+1/8+1/10)
=(1+1/3+1/5+1/7+1/9).137/120
=258/315.137/120
=5891/6300
Đúng 0
Bình luận (0)
a, \(\sqrt{1\frac{24}{25}.5\frac{1}{16}.0,01}=\sqrt{\frac{49}{25}.\frac{81}{16}.\frac{1}{100}}\)
b, \(\sqrt{2,25.1,46-2,25.0,02}\)