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Minh Lệ
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Người Già
22 tháng 8 2023 lúc 22:54

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Quân hoàng
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Nguyễn Đức Nhuận
17 tháng 4 2020 lúc 16:53

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

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Nguyễn Đức Nhuận
17 tháng 4 2020 lúc 16:53

d=43/37d=43/37 × 23/15−43/3723/15−43/37 × 8/15+31/378/15+31/37

=43/37=43/37 x 23/15+43/3723/15+43/37 x (−8/15)+31/37(−8/15)+31/37

=43/37(23/15−8/15)+31/37=43/37(23/15−8/15)+31/37

=43/37.1+31/37=43/37.1+31/37

=2=2

E=−5/24E=−5/24 × 9/11−5/249/11−5/24 × 2/11+7/122/11+7/12

=−5/24(9/11+2/11)+7/12=−5/24(9/11+2/11)+7/12

=−5/24.1+7/12=−5/24.1+7/12

=3/8=3/8

a)3/7–−11/14−7/3×6/7a)3/7–−11/14−7/3×6/7

=3/7−−11/14−2=3/7−−11/14−2

=3/7+11/14−2=3/7+11/14−2

=−11/14=−11/14

b)6/5:3/2+−2/3×9/14b)6/5:3/2+−2/3×9/14

=4/5−3/7=4/5−3/7

=13/35

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Hương Thanh
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『Kuroba ム Tsuki Ryoo...
24 tháng 6 2023 lúc 13:00

`@` `\text {Ans}`

`\downarrow`

`a)`

\(\dfrac{1}{2}-\dfrac{5}{6}+\dfrac{11}{33}-\dfrac{35}{40}\)

`=`\(\dfrac{1}{2}-\dfrac{5}{6}+\dfrac{1}{3}-\dfrac{7}{8}\)

`=`\(\dfrac{12}{24}-\dfrac{20}{24}+\dfrac{8}{24}-\dfrac{21}{24}\)

`= -21/24 = -7/8`

`b)`

\(\dfrac{2}{3}\cdot1\dfrac{3}{4}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)

`=`\(\dfrac{2}{3}\cdot\dfrac{7}{4}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)

`=`\(\dfrac{7}{6}-\dfrac{8}{9}-\dfrac{17}{51}-\dfrac{1}{5}\)

`=`\(\dfrac{5}{18}-\dfrac{17}{51}-\dfrac{1}{5}\)

`=`\(-\dfrac{1}{18}-\dfrac{1}{5}=-\dfrac{23}{90}\)

`c)`

\(\dfrac{1}{2}\cdot2-2\dfrac{5}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)

`=`\(1-\dfrac{19}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)

`=`\(-\dfrac{12}{7}+\dfrac{6}{4}-\dfrac{10}{15}\)

`=`\(-\dfrac{3}{14}-\dfrac{10}{15}=-\dfrac{37}{42}\)

`d) `

\(\dfrac{1}{6}\cdot\dfrac{1}{11}+\dfrac{4}{11}\cdot\left(-\dfrac{1}{6}\right)+\dfrac{8}{11}\cdot\dfrac{1}{6}+\dfrac{1}{6}\cdot\dfrac{6}{11}\)

`=`\(\dfrac{1}{6}\cdot\left(\dfrac{1}{11}-\dfrac{4}{11}+\dfrac{8}{11}+\dfrac{6}{11}\right)\)

`=`\(\dfrac{1}{6}\cdot\left(\dfrac{1-4+8+6}{11}\right)\)

`=`\(\dfrac{1}{6}\cdot1=\dfrac{1}{6}\)

`e)`

\(-17\cdot\left(-23\right)+\left(-53\right)\cdot17+17\cdot14+17\cdot\left(-24\right)\)

`= 17*(23-53+14-24)`

`= 17*(-40)`

`= -680`

`f)`

\(-19\cdot218+\left(-82\right)\cdot19-533\cdot19+\left(-19\right)\cdot167\)

`= 19*(-218-82-533-167)`

`= 19*(-1000)`

`= -19000`

`g)`

\(\dfrac{2}{5}+\dfrac{3}{8}-\dfrac{11}{44}+\dfrac{9}{16}\)

`=`\(\dfrac{2}{5}+\dfrac{3}{8}-\dfrac{1}{4}+\dfrac{9}{16}\)

`=`\(\dfrac{31}{40}-\dfrac{1}{4}+\dfrac{9}{16}\)

`=`\(\dfrac{21}{40}+\dfrac{9}{16}=\dfrac{87}{80}\)

`h)`

\(\dfrac{4}{10}-1\dfrac{5}{6}\cdot2+\dfrac{7}{8}-\dfrac{1}{9}\)

`=`\(\dfrac{4}{10}-\dfrac{11}{6}\cdot2+\dfrac{7}{8}-\dfrac{1}{9}\)

`=`\(\dfrac{4}{10}-\dfrac{11}{3}+\dfrac{7}{8}-\dfrac{1}{9}\)

`=`\(-\dfrac{49}{15}+\dfrac{7}{8}-\dfrac{1}{9}\)

`=`\(-\dfrac{287}{120}-\dfrac{1}{9}=-\dfrac{901}{360}\)

`i )`

\(3\cdot\dfrac{1}{5}-\dfrac{2}{8}-\dfrac{12}{36}+\dfrac{15}{9}\)

`=`\(\dfrac{3}{5}-\dfrac{1}{4}-\dfrac{1}{3}+\dfrac{15}{9}\)

`=`\(\dfrac{7}{20}-\dfrac{1}{3}+\dfrac{15}{9}\)

`=`\(\dfrac{1}{60}+\dfrac{15}{9}=-\dfrac{33}{20}\)

`k)`

\(\dfrac{6}{8}\cdot3\dfrac{1}{2}+4\dfrac{2}{3}-\dfrac{11}{55}+\dfrac{17}{51}\)

`=`\(\dfrac{3}{4}\cdot\dfrac{7}{2}+\dfrac{14}{3}-\dfrac{1}{5}+\dfrac{17}{51}\)

`=`\(\dfrac{21}{8}+\dfrac{14}{3}-\dfrac{1}{5}+\dfrac{17}{51}\)

`=`\(\dfrac{175}{24}-\dfrac{1}{5}+\dfrac{17}{51}\)

`=`\(\dfrac{851}{120}+\dfrac{17}{51}=\dfrac{297}{40}\)

`l )`

\(\dfrac{1}{3}\cdot3\dfrac{1}{2}-4\dfrac{2}{5}-\dfrac{26}{78}+\dfrac{17}{51}\)

`=`\(\dfrac{1}{3}\cdot\dfrac{7}{2}-\dfrac{22}{5}-\dfrac{1}{3}+\dfrac{17}{51}\)

`=`\(\dfrac{1}{3}\left(\dfrac{7}{2}-1\right)-\dfrac{22}{5}+\dfrac{17}{51}\)

`=`\(\dfrac{1}{3}\cdot\dfrac{5}{2}-\dfrac{22}{5}+\dfrac{17}{51}\)

`=`\(\dfrac{5}{6}-\dfrac{22}{5}+\dfrac{17}{51}\)

`=`\(-\dfrac{107}{30}+\dfrac{17}{51}=-\dfrac{97}{30}\)

P/s: Bạn tách bài ra hỏi nhé! Và ghi đề rõ ràng chứ đừng ghi ntnay, nhiều bạn nhìn vào rất khó nhìn!

`# \text {KaizulvG}`

Phạm Duy Anh
24 tháng 6 2023 lúc 12:58

a) 

`  1/2 - 5/6 + 11/33 - 35/40 `

 

`= 1/2 - 5/6 + 1/3 - 7/8 `

 

`= ( 1/2 - 5/6 ) + ( 1/3 - 7/8 ) `

 

`= ( 3/6 - 5/6 ) + ( 8/24 - 21/24 ) `

 

`= -2/6 + (-13)/24 `

 

`= -1/3 + (-13)/24 `

 

`= -8/24 + (-13)/24 `

 

`= -21/24 = -7/8 `

 

Gia Hân
26 tháng 6 2023 lúc 9:22

Tuấn Dương Lương
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Công chúa bong bóng
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thuỳ nga
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Giang シ)
3 tháng 1 2022 lúc 8:26

1,  17.( 85+15) -120 = 17. 100 -120 =1700 - 120 =1580

2, 

23 . 17 - 23 . 14

= 23(17-14)

=23. 3= 24

khanh vo
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Toru
12 tháng 11 2023 lúc 8:43

\(\left[\left(\dfrac{-3}{8}+\dfrac{11}{23}\right):\dfrac{5}{9}+\left(\dfrac{-5}{8}+\dfrac{12}{23}\right):\dfrac{5}{9}\right]\cdot\dfrac{11}{235}\)

\(=\left[\left(\dfrac{-3}{8}+\dfrac{11}{23}\right)\cdot\dfrac{9}{5}+\left(\dfrac{-5}{8}+\dfrac{12}{23}\right)\cdot\dfrac{9}{5}\right]\cdot\dfrac{11}{235}\)

\(=\dfrac{9}{5}\cdot\left(\dfrac{-3}{8}+\dfrac{11}{23}+\dfrac{-5}{8}+\dfrac{12}{23}\right)\cdot\dfrac{11}{235}\)

\(=\dfrac{9}{5}\cdot\left[\left(\dfrac{-3}{8}+\dfrac{-5}{8}\right)+\left(\dfrac{11}{23}+\dfrac{12}{23}\right)\right]\cdot\dfrac{11}{235}\)

\(=\dfrac{9}{5}\cdot\left(-1+1\right)\cdot\dfrac{11}{235}\)

\(=\dfrac{9}{5}\cdot0\cdot\dfrac{11}{235}\)

\(=0\)

Pham Trong Bach
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Cao Minh Tâm
16 tháng 11 2019 lúc 12:07

Giải bài 2 trang 177 sgk Toán 4 | Để học tốt Toán 4

a)24579 + 43867 = 68446

82604 - 35246 = 47358

Giải bài 3 trang 177 sgk Toán 4 | Để học tốt Toán 4

b)235 x 325 = 76 375

Meizwho
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