3 x X +2x ( X-1) =17
Tìm x, biết:
a) |2x + 1| = 17
b) |3x − 17| = |2x − 3|
c) |x − 5| = 2x
d) |x − 1| + |x − 5| = 3
c) l x - 5 l = 2x
\(\Leftrightarrow\orbr{\begin{cases}x-5=2x\\x-5=-2x\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x-2x=5\\x+2x=5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}-x=5\\3x=5\end{cases}}\)
\(\Leftrightarrow\orbr{\begin{cases}x=-5\\x=\frac{5}{3}\end{cases}}\)
Hok tốt!!!!!!!
Tìm x, biết:
a) |2x + 1| = 17
<=>\(\orbr{\begin{cases}2x+1=17\\2x+1=-17\end{cases}}\)
<=>\(\orbr{\begin{cases}2x=16\\2x=-18\end{cases}}\)
<=> \(\hept{\begin{cases}x=8\\x=-9\end{cases}}\)
Phần d không biết , thông cảm
a) Ta có :
| 2x + 1 | = 17
\(\Rightarrow\orbr{\begin{cases}2x+1=17\\2x+1=-17\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}2x=16\\2x=-18\end{cases}}\Rightarrow\orbr{\begin{cases}x=8\\x=-9\end{cases}}\)
b) | 3x - 17 | = | 2x - 3 |
Xét các trường hợp :
+) 3x - 17 = - 2x + 3
=> 3x + 2x = 3 + 17
=> 5x = 20
=> x = 4
+) 3x - 17 = 2x - 3
=> 3x - 2x = -3 + 17
=> x = 14
+) -3x + 17 = 2x - 3
=> 2x + 3x = 17 + 3x
=> 5x = 20
=> x = 4
c) | x - 5 | = 2x
\(\Rightarrow\orbr{\begin{cases}x-5=2x\\x-5=-2x\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}-x=5\\3x=5\end{cases}}\Rightarrow\orbr{\begin{cases}x=5\\x=\frac{5}{3}\end{cases}}\)
|-2x + 1|=3
(x+9-17)-24=11-(x+17)
-3.(2x+1)-11=-8-2.(x+3)
|x+4|+x=12-x
Giúp mình với mình cần gấp lắm
bài 3: tìm x , biết:
a)(x+3).(2x-1)-(x-3).(x+1)=0
b)(x+4).(2x-3)-3.(x-2).(x+2)=0
c)x.(x-5).(x+5)-(x+2).(x2-2x+4)=17
a) \(\left(x+3\right)\left(2x-1\right)-\left(x-3\right)\left(x+1\right)=0\)
\(\Leftrightarrow2x^2+5x-3-x^2+2x+3=0\)
\(\Leftrightarrow x^2+7x=0\Leftrightarrow x\left(x+7\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-7\end{matrix}\right.\)
b) \(\left(x+4\right)\left(2x-3\right)-3\left(x-2\right)\left(x+2\right)=0\)
\(\Leftrightarrow2x^2+5x-12-3x^2+12=0\)
\(\Leftrightarrow x^2-5x=0\Leftrightarrow x\left(x-5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
3(x+2)-2(2x--1)=-7
-4(2x-1)+3(x-5)=4
5+|x|=11
-7-2|x|=-17
|x+3|=0
3|x-2|-10=17
2^x+1+2^x-1=160
1. tìm số nguyên x
a)-2x-3.(x-17)=34-(-x+25)
b)-2x-3.(x-17)=34-2(-x+25)
c)17x-(-16x-37)=2x +43
a)-2x - 3.(x - 17) = 34 - (-x + 25)
- 2x - 3x + 51 = 34 + x - 25
- 2x - 3x - x = -51 + 34 - 25
- 6x = - 42
x = 7
Vậy x = 7
b)-2x-3.(x-17)=34-2(-x+25)
- 2x - 3x + 51 = 34 + 2x - 50
- 2x - 3x - 2x = - 51 + 34 - 50
7x = - 67
x = \(-\frac{67}{7}\)
Vậy \(x=-\frac{67}{7}\)
c)17x-(-16x-37)=2x +43
17x + 16x + 37 = 2x + 43
17x + 16x - 2x = -37 + 43
31x = 6
x = \(\frac{6}{31}\)
Vậy \(x=\frac{6}{31}\)
Tìm x:,để:
a,x^20=x ; b,(2x-17)^5=(2x-17)^5
c,5^x=3^x ;d,(x-1)^3=(3-2x)^5
e,4.8^x-4=2.2^3x
tìm x
a, ( x - 3 ) mũ 3 + x (1 - x ) = 3
b, 4x ( x - 20 ) - ( 2x - 1 )( 2x + 3 )= 0
c, ( 2x - 1 ) mũ 2 + ( 3 + 2x )(3 - 2x )= 8
d, ( x - 20 )( x mũ 2 + 2x + 4 ) - x mũ 2 ( x + 1 ) = - 17
(1+2x)^2 - (x-2)^3 < (1-x)(x^2-2x+17)
Câu 1:
a) -2x-(x-17)=34-(-x+25)
b) 17x-(-16x-27)=2x+43
c) -2x-3(x-17)=34-2(-x+25)
d) 17x+3(-16x-37)=2x+43-4x
e) 3x-32>-5x+1
f)15+4x<2x-145
g)-3(2x+5)-16<-4(3-2x)
h) -2x+15<3x-7<19-x
i)x+(x+1)+(x+2)+(x+3)+....+13+14=14
j)25+24+23+...+x+(x-2)+(x-3)=25
Câu 2:
a) (x-3).(y+5)=-17
b) (x+1).(xy-2)=11
c) xy-7x+y=-22
d) xy-3x+y=-20
Câu 1:
a: =>-2x-x+17=34+x-25
=>-3x+17=x+9
=>-4x=-8
hay x=2
b: =>17x+16x+27=2x+43
=>33x+27=2x+43
=>31x=16
hay x=16/31
c: =>-2x-3x+51=34+2x-50
=>-5x+51=2x-16
=>-7x=-67
hay x=67/7
e: 3x-32>-5x+1
=>8x>33
hay x>33/8
14, giải các PT sau.
1, 4-(x-5)=5(x-3x)
2, 32-4(0,5y-5)=3y+2
3, 19-2(x+11)=5(2x-3)-4(5x-7)
4, 4(x+3)-7x+17=8(5x-1)+166
5, 17-14(x+1)=13-4(x+1)-5(x-3)
6, 5(x+10)2+2x=5x2-3
7, (2x-1)2+5=(2x+3)(2x-3)-x
8, 3(x-2)2+2(x+3)(x-3)=5(x+1)2