tinh gia tri bieu thuc
C=x^3+y^3+3xy(x^2+y^2)+6x^2y^2(x+y) với x+y=1
nhanh nha mik tick cho
Những câu hỏi liên quan
cho x+y =1 . tinh gia tri cua bieu thuc A=x^3+y^3+3xy
chox-y=1. tinh gia tri cua bieu thuc B=x^3-y^3-3xy
cho x+y=1 . tinh gia tri cua bieu thuc C=x^3+y^3+3xy(x^2+y^2)+6x^2*y^2(x+y)
Câu 1: Ta có: A = \(x^3+y^3+3xy=x^3+y^3+3xy\times1=x^3+y^3+3xy\left(x+y\right)\)
\(=\left(x+y\right)^3=1^3=1\)
Câu 2: Ta có: \(B=x^3-y^3-3xy=\left(x-y\right)\left(x^2+xy+y^2\right)-3xy\)
\(=x^2+xy+y^2-3xy=x^2-2xy+y^2=\left(x-y\right)^2=1^2=1\)
Câu 3: Ta có: \(C=x^3+y^3+3xy\left(x^2+y^2\right)-6x^2.y^2\left(x+y\right)\)
\(=x^3+y^3+3xy\left(x^2+2xy+y^2-2xy\right)+6x^2y^2\)
\(=x^3+y^3+3xy\left(x+y\right)^2-3xy.2xy+6x^2y^2\)
\(=x^3+y^3+3xy.1-6x^2y^2+6x^2y^3\)
\(=x^3+y^3+3xy\left(x+y\right)=\left(x+y\right)^3=1^3=1\)
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tinh gia tri cua bieu thuc A=\(x^3+y^3+3xy\left(x^2+y^2\right)+6x^2y^2\left(x+y\right)\)
Sửa đề: x+y=1
\(A=\left(x+y\right)^3-3xy\left(x+y\right)+3xy\left[\left(x+y\right)^2-2xy\right]+6x^2y^2\)
\(=1-3xy+3xy\left[1-2xy\right]+6x^2y^2\)
=1
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Cho x - y = 11. Tinh gia tri cua bieu thuc : M = x^3-3xy(x- y) - y^3 -x^2 + 2xy - y^2
Ta có: x^3 -3xy(x-y) -y^3 -x^2 + 2xy-y^2
= x^3 -y^3 - 3xy(x-y) -( x^2 -2xy+y^2)
= (x-y)(x^2+xy +y^2) - 3xy(x-y) -(x-y)^2
= (x-y)(x^2+xy+y^2 -3xy-x+y)
=11( x^2 -2xy+y^2 -x+y)
= 11[ (x-y)^2 -(x-y)]
= 11[ 11^2 -11]
= 11^3 -11^2=...
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tinh nhanh gia tri cua bieu thuc voi x,y nhan bat ki gia tri nao:
\(\frac{1}{3}x^2y\left(3xy\right)^2y^4+\frac{1}{2}x\left(-2xy\right)^3y^4+x^4y^7+18\)
cau1
cho x,y la 2 so khac nhau thoa man x2-y=y2-x tinh gia tri cua bieu thuc
A=x3+y3+3xy(x2+y2)+6x2y2(x+y)
tính gia tri bieu thuc x^3 - y^3 -2x^2 - 2y^2 + 3xy.(x+y) -4xy + 3.(x+y) +10 biet x+y=5
cho x+y=1.Tinh gia tri bieu thuc B=x3+3xy +y3 (bang 2 cach)
C1: \(B=x^3+3xy+y^3\)
\(=\left(x+y\right)^3-3xy\left(x+y\right)+3xy\)
\(=\left(x+y\right)^3-3xy\left(x+y-1\right)\)
Thay \(x+y=1\)ta được:
\(B=1^3-3xy\left(1-1\right)=1\)
C2: \(x+y=1\)\(\Rightarrow\)\(x=1-y\)
\(B=x^3+3xy+y^3=\left(1-y\right)^3+3\left(1-y\right)y+y^3\)
\(=1-3y+3y^2-y^3+3y-3y^2+y^3=1\)
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Cho x - y = 7 . Tinh gia tri cua bieu thuc
a) M = x3 - 3xy . ( x - y ) - y3 - x2 + 2xy - y2
b) N = x2 . ( x + 1 ) - y2 . ( y - 1 ) + xy - 3xy . ( x - y + 1 ) - 95
a)\(M=\text{[}x^3-3xy\left(x-y\right)-y^3\text{]}-\left(x^2-2xy+y^2\right)\)
\(M=\left(x-y\right)^3-\left(x-y\right)^2\)
\(\Rightarrow M=7^3-7^2\)
\(M=294\)
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tinh gia tri bieu thuc:
a,3x^4+5x^2y^2+2y^4+2y^2 biet rang x^2+y^2=1
b,x^3+xy^2-x^2y-y^3+3 biet x-y=0
b, Ta co: \(x^3+xy^2-x^2y-y^3+3\)
\(=\left(x^3-y^3\right)+\left(xy^2-x^2y\right)+3\)
\(=\left(x-y\right)^3+3xy\left(x-y\right)-xy\left(x-y\right)+3\)
= 3 ( vì x-y = 0)
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