a: -10/8<-1

-19/19=-1

-1<-2/10<0

0<5/12<1<17/15

=>17/15>1>5/12>-2/10>-19/19>-10/8

b: -1/3=-4/12; -5/12=-5/12; -3/4=-9/12; -1/4=-3/12; -7/12=-7/12

=>-3/4<-7/12<-5/12<-1/3<-1/4

Theo thứ tự từ lớn đến bé:\(\dfrac{17}{15};1;\dfrac{5}{12};0;\dfrac{2}{-10};-\dfrac{19}{19};-\dfrac{10}{8}\)

Theo thứ tự từ bé đến lớn : \(-\dfrac{3}{4};-\dfrac{7}{12};-\dfrac{5}{12};-\dfrac{1}{3};\dfrac{1}{-4}\)

\(\dfrac{12}{7};\dfrac{3}{2}\)

12/7 , 3/2

12 / 7 , 3 / 2

3/4   1/2   3/7

3/4 1/2 

Bé đến lớn :: 7/9  ,   5/6   ,    5/4      ,     21/5

Lớn đến bé : 3/2   ,   5/4   ,   7/10     ,     3/5

a. 3/7 ; 1/3 ; 1/7

b. 7/3 ; 3/1 ; 7/1

a) \(\frac{3}{7};\frac{1}{3};\frac{1}{7}\)

b) \(\frac{7}{1};\frac{3}{1};\frac{7}{3}\)

giải giúp mình mình cần gấp!!!

=> 5/6; 4/5; 2/3; 7/12; 1/2

                                1/2    ; 4/5    ; 2/3   ; 5/6     ; 7/12

Khi quy đồng ta có: 30/60; 48/60; 40/60; 50/60; 35/60

Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\)     ;    \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\)     ;     \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\) 

\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\)     ;    \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)

⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)
 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 . 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 .

\(\dfrac{1}{2}=\dfrac{1\cdot24}{2\cdot24}=\dfrac{24}{48}\)

\(\dfrac{3}{48}=\dfrac{3\cdot1}{48\cdot1}=\dfrac{3}{48}\)

\(\dfrac{8}{12}=\dfrac{8\cdot4}{12\cdot4}=\dfrac{32}{48}\)

\(\dfrac{5}{6}=\dfrac{5\cdot8}{6\cdot8}=\dfrac{40}{48}\)

\(\dfrac{7}{12}=\dfrac{7\cdot4}{12\cdot4}=\dfrac{28}{48}\)

mà 3<24<28<32<40

nên \(\dfrac{3}{48}< \dfrac{1}{2}< \dfrac{7}{12}< \dfrac{8}{12}< \dfrac{5}{6}\)