5 nha !

nhớ k mik nha

1+2-3+4-5+6-7+8-9+10

=1-1-1-1-1+10

=-5+10

=5

1+2-3+4-5+6-7+8-9+10

=(1+2-3)+(4-5+6)-(7-8+9)+10

=     0    +      5    -      8    +10

=            5         +           (10-8) =5+2 =7

số cần tìm là

  1 + 2 + 3 + 4 + 5 + 6+ 7 + 8 + 9 + 10 = 55

      đáp số 55

55 nha bn

bang 55

\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{42+462+55}{77}=\dfrac{559}{77}\)

\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{8}\times\dfrac{3}{12}\times\dfrac{9}{5}=\dfrac{243}{480}=\dfrac{81}{160}\)

\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{8}{28}+2=\dfrac{2}{7}+2=\dfrac{16}{7}\)

\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{49}{15}\)

\(a,\dfrac{6}{11}+6+\dfrac{5}{7}=\dfrac{6}{11}+\dfrac{66}{11}+\dfrac{5}{7}=\dfrac{72}{11}+\dfrac{5}{7}=\dfrac{504}{77}+\dfrac{55}{77}=\dfrac{559}{77}\)

\(b,\dfrac{9}{8}\times\dfrac{3}{12}:\dfrac{5}{9}=\dfrac{9}{32}:\dfrac{5}{9}=\dfrac{9}{32}\times\dfrac{9}{5}=\dfrac{81}{160}\)

\(c,\dfrac{8}{7}:4+2=\dfrac{8}{7}\times\dfrac{1}{4}+2=\dfrac{2}{7}+2=\dfrac{2}{7}+\dfrac{14}{7}=\dfrac{16}{7}\)

\(d,\dfrac{3}{5}+4:\dfrac{6}{4}=\dfrac{3}{5}+4\times\dfrac{4}{6}=\dfrac{3}{5}+\dfrac{8}{3}=\dfrac{9}{15}+\dfrac{40}{15}=\dfrac{49}{15}\)

\(;l\\ 54\backslash54\)

a) 1007-0/2=503.5

b)

Lần sau bạn chú ý viết đầy đủ đề.

1.

\(\sqrt{9+4\sqrt{5}-\sqrt{9-4\sqrt{5}}}=\sqrt{9+4\sqrt{5}-\sqrt{5-2\sqrt{4.5}+4}}\)

\(=\sqrt{9+4\sqrt{5}-\sqrt{(\sqrt{5}-\sqrt{4})^2}}=\sqrt{9+4\sqrt{5}-(\sqrt{5}-\sqrt{4})}\)

\(=\sqrt{9+4\sqrt{5}-\sqrt{5}+2}=\sqrt{11+3\sqrt{5}}\)

2.

\(\sqrt{8-2\sqrt{7}-\sqrt{8+2\sqrt{7}}}=\sqrt{8-2\sqrt{7}-\sqrt{7+2\sqrt{7}+1}}\)

\(=\sqrt{8-2\sqrt{7}-\sqrt{(\sqrt{7}+1)^2}}\)

\(=\sqrt{8-2\sqrt{7}-\sqrt{7}-1}=\sqrt{7-3\sqrt{7}}\)

Phạm Mạnh Kiên: sửa lại theo ý bạn thì làm như sau:

1.

\(\sqrt{9+4\sqrt{5}}-\sqrt{9-4\sqrt{5}}=\sqrt{5+2\sqrt{5}.\sqrt{4}+4}-\sqrt{5-2\sqrt{5}.\sqrt{4}+4}\)

\(=\sqrt{(\sqrt{5}+\sqrt{4})^2}-\sqrt{(\sqrt{5}-\sqrt{4})^2}=|\sqrt{5}+2|-|\sqrt{5}-2|\)

\(=\sqrt{5}+2-(\sqrt{5}-2)=4\)

2.

\(\sqrt{8-2\sqrt{7}}-\sqrt{8+2\sqrt{7}}=\sqrt{7-2\sqrt{7}+1}-\sqrt{7+2\sqrt{7}+1}\)

\(=\sqrt{(\sqrt{7}-1)^2}-\sqrt{(\sqrt{7}+1)^2}=|\sqrt{7}-1|-|\sqrt{7}+1|\)

\(=-2\)

\(a,\frac{5}{4}-\frac{1}{8}=\frac{10-1}{8}=\frac{9}{8}\)

\(b,\frac{6}{7}+\frac{4}{21}=\frac{18+4}{21}=\frac{22}{21}\)

\(c,\frac{6}{7}-\frac{3}{6}=\frac{36-21}{42}=\frac{5}{14}\)

\(d,\frac{5}{9}+\frac{3}{4}=\frac{20+27}{36}=\frac{47}{36}\)

\(e,\frac{2}{5}\times\frac{4}{7}=\frac{8}{35}\)

a) 5/4 - 1/8           b) 6/7 + 4/21            c) 6/7 - 3/6               d) 5/9 + 3/4              e) 2/5 x 4/7         h) 3/10 : 6/10

= 10/8 - 1/8           = 18/21 + 4/21         = 6/7 - 1/2                = 20/36 + 27/36       = 8/35                 = 3/10 : 3/5

= 9/8                     = 22/21                     = 6/7 + ( -1/2 )         = 47/36                                               = 3/10 x 5/3

                                                               = 12/14 + ( -7/14 )                                                              = 15/30

                                                               = 5/14                                                                                 = 1/2 chúc bạn học tốt nhé !

oh thanks m.n nhìu!chúc 2 bạn học tốt nhé