\(\left(x-2\right)^4=\left(x-2\right)^8\)

TH1: \(x-2\ne0\Rightarrow x\ne2\)TA CÓ:

\(\left(x-2\right)^8:\left(x-2\right)^4=1\)

\(\Rightarrow\left(x-2\right)^4=1\)

\(\Rightarrow\orbr{\begin{cases}x-2=1\\x-2=-1\end{cases}}\Rightarrow\orbr{\begin{cases}x=3\\x=1\end{cases}}\)

TH2: \(x-2=0\Rightarrow x=2\)Ta có: 

\(\left(2-2\right)^4=\left(2-2\right)^8\Rightarrow0=0\)(luôn đúng)

Vậy với \(x\in\left\{1;2;3\right\}\)thì \(\left(x-2\right)^4=\left(x-2\right)^8\)

CHÚC BẠN HỌC TỐT!

x:4+x=3,75

x/4+x=3,75

x(1/4+1)=3,75

x (5/4)=15/4

x=15/4x4/5

x=3

X = 3 nha!

 x: 4 + x = 3.75

x : 4 = 3.75 - x

x = 4(3.75 - x)

x = 15 - 4x

x + 4x = 15 

5x = 15 

=> x = 15 : 5 

x = 3 

Xong rùi nha bạn

a)

\(\sqrt{9+4\sqrt{5}}\cdot\sqrt{6-2\sqrt{5}}\\ =\sqrt{4+4\sqrt{5}+5}\cdot\sqrt{1-2\sqrt{5}+5}\\ =\sqrt{\left(2+\sqrt{5}\right)^2}\cdot\sqrt{\left(1-\sqrt{5}\right)^2}\\ =\left(2+\sqrt{5}\right)\left(1-\sqrt{5}\right)\)

b)

\(\sqrt{3+2\sqrt{2}}-\sqrt{6-4\sqrt{2}}\\ =\sqrt{2+2\sqrt{2}+1}-\sqrt{4-4\sqrt{2}+2}\\ =\sqrt{\left(\sqrt{2}+1\right)^2}-\sqrt{\left(2-\sqrt{2}\right)^2}\\ =\sqrt{2}+1-2+\sqrt{2}=2\sqrt{2}-1\)

2017-{5^2.2^2-11[7^2-5.2^3+8(11^2-121)]}=

=2017-{25.4-11[49-5.8+8(121-121)]}=

= 2017-{100-11[49-40+0]}=2017-{100-11.9}=2017-1=2016

\(2017-\left\{5^2.2^2-11.\left[7^2-5.2^3+8\left(11^2-121\right)\right]\right\}\)\(=1017-\left\{100-11\left[49-40+8\left(121-121\right)\right]\right\}\)

\(=2017-\left\{100-11\left[9+8.0\right]\right\}\)

\(=2017-\left\{100-11.9\right\}\)

\(=2017-\left(100-99\right)=1017-1=2016\)

cảm ơn các pạn nhìu lms

a+3=a-2+5

=>a-2+5 chia hết cho a-2

=> 5 chia hết cho a-2

=>a-2 thuộc Ư(5)

Ư(5)={-5;-1;1;5}

a={-3;1;3;7}

cho mk hoi 5 lay o dau ra va vi sao 5 chia het cho a-2

mk thay gia bao gioi toan

hieu roi ban giup mk tim ra cach giai dang toan nay no gap nhieu

trong violympic

a = 0, b= 0

a 64 b 48

a=0,b=0

a=64  b=48

0,5m=5dm

45,2cm=4,52dm

a) 5        b)4,52          c)24,3       d) 24,5

a/ \(0,5m=5dm\)

b/ \(45,2cm=4,52dm\)

c/ \(2,43m=24,3dm\)

d/ \(2450mm=24,5dm\)

a=1,b=2,c=3,d=4