a) ta có:  \(1-\frac{2012}{2013}=\frac{1}{2013}\)

                 \(1-\frac{2013}{2014}=\frac{1}{2014}\)

mà \(\frac{1}{2013}>\frac{1}{2014}\) nên   \(\frac{2013}{2014}>\frac{2012}{2013}\)

sao giống lớp 4 thế ta

a)12/5<5/2

b)6/15>3/8

c)\(\frac{17}{18}<\frac{18}{19}\)

d) \(\frac{24}{23}\) < \(\frac{23}{22}\)

A , 34 - \(\dfrac{x}{30}\) = \(\dfrac{5}{6}\) 

             \(\dfrac{x}{30}\) = 34 - \(\dfrac{5}{6}\)

             \(\dfrac{x}{30}=\) \(\dfrac{199}{6}\)

               \(\dfrac{x}{30}=\) \(\dfrac{995}{30}\)

                x = 995

B x +\(\dfrac{13}{34}\) = \(\dfrac{12}{17}\)

   x          = \(\dfrac{12}{17}-\dfrac{13}{34}\)  

   x         = \(\dfrac{11}{34}\) 

\(\dfrac{7}{9}=\dfrac{21}{27};\dfrac{7}{10}=\dfrac{21}{30}\) 

hai số nằm giữa \(\dfrac{7}{9}\) và \(\dfrac{7}{10}\) 

\(\dfrac{21}{27}>\dfrac{21}{28}>\dfrac{21}{29}>\dfrac{21}{30}\) 

\(\dfrac{13}{15}=\dfrac{91}{105};\dfrac{14}{15}=\dfrac{98}{105}\)

6 số nằm giữa \(\dfrac{13}{15}\) và \(\dfrac{14}{15}\) 

\(\dfrac{91}{105}< \dfrac{92}{105};\dfrac{93}{105};\dfrac{94}{105};\dfrac{95}{105};\dfrac{96}{105};\dfrac{97}{105}< \dfrac{98}{105}\)

Bài 1:

a) \(\dfrac{-17}{36}\) và \(\dfrac{23}{-48}\) 

\(\dfrac{-17}{36}=\dfrac{-17.4}{36.4}=\dfrac{-68}{144}\) 

\(\dfrac{23}{-48}=\dfrac{-23}{48}=\dfrac{-23.3}{144.3}=\dfrac{-69}{144}\) 

Vì \(\dfrac{-68}{144}>\dfrac{-69}{144}\) nên \(\dfrac{-17}{36}>\dfrac{23}{-48}\) 

b) \(\dfrac{-1}{3}\) và \(\dfrac{2}{5}\) 

Vì \(\dfrac{-1}{3}\) là số âm mà \(\dfrac{2}{5}\) là số dương nên \(\dfrac{-1}{3}< \dfrac{2}{5}\) 

c) \(\dfrac{2}{7}\) và \(\dfrac{5}{4}\) 

Vì \(\dfrac{2}{7}< 1\) mà \(\dfrac{5}{4}>1\) nên \(\dfrac{2}{7}< \dfrac{5}{4}\) 

d) \(\dfrac{267}{-268}\) và \(\dfrac{-1347}{1343}\) 

\(\dfrac{267}{-268}=\dfrac{-267}{268}=\dfrac{-267.449}{268.449}=\dfrac{-119883}{120332}\) 

\(\dfrac{-1347}{1343}=\dfrac{-1347.89}{1343.89}=\dfrac{-119883}{119527}\) 

Vì \(\dfrac{-119883}{120332}>\dfrac{-119883}{119527}\) nên \(\dfrac{267}{-268}>\dfrac{-1347}{1343}\)

Bài 2:

\(\dfrac{5}{2}-\left(1\dfrac{3}{7}-0,4\right)=\dfrac{5}{2}-\dfrac{10}{7}-\dfrac{2}{5}=\dfrac{47}{70}\) 

a) \(\frac{-1}{5}< 0\)

\(\frac{1}{1000}>0\)

=> -1/5 < 1/1000

b) 267/-268 = -267/268 < -1

 -134/134 = -1

=> 267/-268< -134/134

Chúc bạn học giỏi

a; -1/5<0;;1/1000>0

-1/5<1/1000

B,-134/134=-1

267/-268=-1+1/268

267/-268<-134/134

k cho mk nha

\(\dfrac{16}{27}=\dfrac{15}{27}+\dfrac{1}{27}\\ Vì:\dfrac{15}{27}>\dfrac{15}{29}\\ Nên:\dfrac{15}{27}+\dfrac{1}{27}>\dfrac{15}{29}\\ Vậy:\dfrac{16}{27}>\dfrac{15}{29}\)