(2x-3)3 = -64
(2x-3)2 =25
(3x-4)2 =36
2x+1 = 64
Những câu hỏi liên quan
Tìm x , biết :
a) (3x -1)(2x+7) -(x+1)(6x-5) =16
b) (2x +3)2-2(2x+3)(2x-5)+(2x-5)2= x2+6x+64
c) (x4+2x3+10x-25): (x2+5)=3
a) \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)
\(\Leftrightarrow\left(6x^2+21x-2x-7\right)-\left(6x^2-5x+6x-5\right)-16=0\)
\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5-16=0\)
\(\Leftrightarrow18x-18=0\)
\(\Leftrightarrow18x=18\)
\(\Leftrightarrow x=18:18\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
b) \(\left(2x+3\right)^2-2\left(2x+3\right)\left(2x-5\right)+\left(2x-5\right)^2=x^2+6x+64\)
\(\Leftrightarrow\left[\left(2x+3\right)-\left(2x-5\right)\right]^2-\left(x^2+6x+64\right)=0\)
\(\Leftrightarrow\left(2x+3-2x+5\right)^2-x^2-6x-64=0\)
\(\Leftrightarrow8^2-x^2-6x-64=0\)
\(\Leftrightarrow64-x^2-6x-64=0\)
\(\Leftrightarrow-x^2-6x=0\)
\(\Leftrightarrow x\left(-x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\-x-6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\-x=6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-6\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=-6\)
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a) \(\left(3x-1\right)\left(2x+7\right)-\left(x+1\right)\left(6x-5\right)=16\)
\(\Leftrightarrow\left(6x^2+21x-2x-7\right)-\left(6x^2-5x+6x-5\right)-16=0\)
\(\Leftrightarrow6x^2+21x-2x-7-6x^2+5x-6x+5-16=0\)
\(\Leftrightarrow18x-18=0\)
\(\Leftrightarrow18x=18\)
\(\Leftrightarrow x=18:18\)
\(\Leftrightarrow x=1\)
Vậy \(x=1\)
b, \(\left(2x+3\right)^2-2\left(2x+3\right)\left(2x-5\right)+\left(2x- 5\right)^2=x^2+6x+64\)
\(\Leftrightarrow\left[\left(2x+3\right)-\left(2x-5\right)\right]^2- \left(x^2+6x+64\right)=0\)
\(\Leftrightarrow\left(2x+3-2x+5\right)^2-x^2-6x-64=0\)
\(\Leftrightarrow8^2-x^2-6x-64=0\)
\(\Leftrightarrow64-x^2-6x-64=0\)
\(\Leftrightarrow-x^2-6x=0\)
\(\Leftrightarrow x\left(-x-6\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\-x-6=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\-x=6\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=-6\end{matrix}\right.\)
Vậy \(x=0\) hoặc \(x=6\)
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a) (3x−1)(2x+7)−(x+1)(6x−5)=16(3x−1)(2x+7)−(x+1)(6x−5)=16
⇔(6x2+21x−2x−7)−(6x2−5x+6x−5)−16=0⇔(6x2+21x−2x−7)−(6x2−5x+6x−5)−16=0
⇔6x2+21x−2x−7−6x2+5x−6x+5−16=0⇔6x2+21x−2x−7−6x2+5x−6x+5−16=0
⇔18x−18=0⇔18x−18=0
⇔18x=18⇔18x=18
⇔x=18:18⇔x=18:18
⇔x=1⇔x=1
Vậy x=1x=1
b) (2x+3)2−2(2x+3)(2x−5)+(2x−5)2=x2+6x+64(2x+3)2−2(2x+3)(2x−5)+(2x−5)2=x2+6x+64
⇔[(2x+3)−(2x−5)]2−(x2+6x+64)=0⇔[(2x+3)−(2x−5)]2−(x2+6x+64)=0
⇔(2x+3−2x+5)2−x2−6x−64=0⇔(2x+3−2x+5)2−x2−6x−64=0
⇔82−x2−6x−64=0⇔82−x2−6x−64=0
⇔64−x2−6x−64=0⇔64−x2−6x−64=0
⇔−x2−6x=0⇔−x2−6x=0
⇔x(−x−6)=0⇔x(−x−6)=0
⇔[x=0−x−6=0⇔[x=0−x−6=0
⇔[x=0−x=6⇔[x=0−x=6
⇔[x=0x=−6⇔[x=0x=−6
Vậy x=0x=0 hoặc x=−6
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(3x-1)mũ 2=25
(2x-1)mũ 3=27
5 mũ 2x+1=125
8 mũ x-1=64
( 3x - 1 )^2 = 25 = (+-5)^2
+) 3x - 1 = 5
3x = 6
x = 2
+) 3x - 1 = -5
3x = -4
x = -4/3
Vậy,.........
Các câu còn lại tương tự
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phân tích
1,(x-2)^4+(x-3)^4-1
2,(x-1)^4+(x+3)^4-512
3,(x-2)^6+(x-4)^6-64
4,x^4-3x^3+6x^2+3x+1
5,3x^4-2x^3-15x^2-2x+3
6,x^6-2x^5-4x^4+6x^3+4x^2-2x-1
1) Phân tích thành nhân tử
x^2 - 25 - 2xy + y^2
2x^3 - 1/4
25x^2 - 64y^2
x^4 + 64
2) Tìm x
x(5-3x) +3x(x-3) = 16
3x(x-10)= x-10
27 tháng 11 2021 lúc 16:02
BÀI 4: TÌM X (ghi rõ cách tính và kết quả)
1) 3x – 15 = 45
2) 35 – 5x = 50
3) (2x – 5) + 17 = 6
4) 10 – 2(4 – 3x) = -4
5) - 12 + 3(-x + 7) = -18
6) 24 : (3x – 2) = -3
7) -45 : 5.(-3 – 2x) = 3
1) 3x = 45 + 15 = 60
x = 60 : 3 = 20
2) 5x = 50 - 35 = 15
x = 15 : 5 = 3
3) (2x - 5) + 17 = 6
2x - 5 = 6 - 17
2x - 5 = -11
2x = -11 + 5
2x = -6
x = -6 : 2 = -3
4) 10 - 2(4 -3x) = -4
2(4 - 3x) = -4 - 10 = -14
4 - 3x = -14 : 2 = -7
3x = -7 - 4 = -18
x = -18 : 3 = -6
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27 tháng 11 2021 lúc 7:10
BÀI 4: TÌM X (ghi rõ từng bước của phép tính)
1) 3x – 15 = 45
2) 35 – 5x = 50
3) (2x – 5) + 17 = 6
4) 10 – 2(4 – 3x) = -4
5) - 12 + 3(-x + 7) = -18
6) 24 : (3x – 2) = -3
7) -45 : 5.(-3 – 2x) = 3
\(\left\{{}\begin{matrix}\left\{{}\begin{matrix}3x-15=45\Leftrightarrow3x=60\Leftrightarrow x=20\\35-5x=50\Leftrightarrow5x=-15\Leftrightarrow x=-3\end{matrix}\right.\\\left\{{}\begin{matrix}\left(2x-5\right)+17=6\Leftrightarrow2x+5=-11\Leftrightarrow2x=-16\Leftrightarrow x=-8\\10-2\left(4-3x\right)=-4\Leftrightarrow8-6x=14\Leftrightarrow6x=-6\Leftrightarrow x=-1\end{matrix}\right.\\\left\{{}\begin{matrix}-12+3\left(-x+7\right)=-18\Leftrightarrow-3x+21=-6\Leftrightarrow-3x=-27\Leftrightarrow x=9\\24:\left(3x-2\right)=-3\Leftrightarrow3x-2=-8\Leftrightarrow3x=-6\Leftrightarrow x=-2\end{matrix}\right.\\-45:5\left(-3-2x\right)=3\Leftrightarrow-15-10x=-15\Leftrightarrow10x=0\Leftrightarrow x=0\end{matrix}\right.\)
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27 tháng 11 2021 lúc 15:17
BÀI 4: TÌM X (ghi rõ cách tính và kết quả)
1) 3x – 15 = 45
2) 35 – 5x = 50
3) (2x – 5) + 17 = 6
4) 10 – 2(4 – 3x) = -4
5) - 12 + 3(-x + 7) = -18
6) 24 : (3x – 2) = -3
7) -45 : 5.(-3 – 2x) = 3
phân tích
1,(x-2)^4+(x-3)^4-1
2,(x-1)^4+(x+3)^4-512
3,(x-2)^6+(x-4)^6-64
4,x^4-3x^3+6x^2+3x+1
5,3x^4-2x^3-15x^2-2x+3
6,x^6-2x^5-4x^4+6x^3+4x^2-2x-1
1: \(=x^4-8x^3+24x^2-32x+16+x^4-12x^3+54x^2-108x+81-1\)
\(=2x^4-20x^3+78x^2-140x+96\)
\(=2\left(x-3\right)\left(x-2\right)\left(x^2-5x+8\right)\)
2: \(=x^4-4x^3+6x^2-4x+1+x^4+12x^3+54x^2+108x+81-512\)
\(=2x^4+8x^3+60x^2+104x-430\)
\(=2\left(x^4+4x^3+30x^2+52x-215\right)\)
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a) 3x5 -1=2
b)(x+1)2=25
c)(x-1)3=64
d)(x+1)3=(2x)3
e)(2x-1)3=(3x)3
32=9
33=27
34=104
35=3112