\(C,\dfrac{1}{2}.\dfrac{3}{4}+\dfrac{1}{2}.\dfrac{1}{4}=\dfrac{1}{2}.\left(\dfrac{3}{4}+\dfrac{1}{4}\right)\)

\(=\dfrac{1}{2}.\dfrac{4}{4}=\dfrac{1}{2}.1=\dfrac{1}{2}\)

\(D,\dfrac{11}{3}.\dfrac{26}{7}-\dfrac{26}{7}.\dfrac{8}{3}=\dfrac{26}{7}.\left(\dfrac{11}{3}-\dfrac{8}{3}\right)\)

\(=\dfrac{26}{7}.\dfrac{3}{3}=\dfrac{26}{7}.1=\dfrac{26}{7}\)

Giải chi tiết cho mình nha

\(\dfrac{2}{5}+\dfrac{11}{15}=\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)

\(\dfrac{7}{8}-\dfrac{7}{9}=\dfrac{63}{72}-\dfrac{56}{72}=\dfrac{7}{72}\)

\(\dfrac{11}{13}\times\dfrac{26}{31}=\dfrac{22}{31}\)

\(\dfrac{16}{24}:4=\dfrac{16}{24}\times\dfrac{1}{4}=\dfrac{4}{24}=\dfrac{1}{6}\)

\(30:\dfrac{6}{5}=30\times\dfrac{5}{6}=25\)

\(\dfrac{9}{16}:4=\dfrac{9}{16}\times\dfrac{1}{4}=\dfrac{9}{64}\)

\(\dfrac{1}{2}:\dfrac{1}{3}\times\dfrac{8}{15}=\dfrac{1}{2}\times3\times\dfrac{8}{15}=\dfrac{4}{5}\)

2/5 + 11/15 = 17/15
7/8 - 7/9 = 7/72
11/13 x 26/31 = 22/31
16/24 : 4 = 1/6
30 : 6/5 = 25
9/16 : 4 = 9/64
1/2 : 1/3 x 8/15 = 3/2 x 8/15 = 4/5

a) \(\dfrac{2}{5}+\dfrac{11}{15}=\dfrac{6}{15}+\dfrac{11}{15}=\dfrac{17}{15}\)

b) \(\dfrac{7}{8}-\dfrac{7}{9}=\dfrac{63}{72}-\dfrac{56}{72}=\dfrac{7}{72}\)

c) \(\dfrac{11}{13}\cdot\dfrac{26}{31}=\dfrac{26}{13}\cdot\dfrac{11}{31}=\dfrac{22}{31}\)

d) \(\dfrac{1}{2}:\dfrac{1}{3}\cdot\dfrac{2}{5}=\dfrac{1}{2}\cdot3\cdot\dfrac{2}{5}=\dfrac{3}{5}\)

a ) 2/5 + 11/15 = 6/15 + 11/ 15 = 17/15.

b ) 7/8 -7/9 = 63/72 -56/72 = 7/72.

c ) 11/13 x 26/31 = 22/31

d ) 1/2 : 1/3 x 2/5= 1/2 x 3/1 x 2/5 = 3/5

đúng thì tick mình nhé!!! cảm ơn bạn

a)  \(0,75\times26+49\times\frac{3}{4}+\frac{3}{4}\times24+\) \(0,75\)

    \(=\) \(0,75\times\left(26+1\right)+\frac{3}{4}\times\left(49+24\right)\)

     \(=\)  \(\frac{3}{4}\times27+\frac{3}{4}\times73\)

      \(=\) \(\frac{3}{4}\times\left(27+73\right)\)

        \(=\)\(\frac{3}{4}\times100=75\)

b) câu b,c làm tương tự

a) \(\dfrac{3}{5}+x=\dfrac{4}{3}\) 

\(\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}\)

\(\Leftrightarrow x=\dfrac{20}{15}-\dfrac{9}{15}\) 

\(\Leftrightarrow x=\dfrac{11}{15}\)

b) \(x+\dfrac{5}{6}=\dfrac{1}{7}\)

\(\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}\)

\(\Leftrightarrow x=\dfrac{6}{42}-\dfrac{35}{42}\)

\(\Leftrightarrow x=-\dfrac{29}{42}\)

c) \(x\times\dfrac{3}{8}=\dfrac{3}{4}\)

\(\Leftrightarrow x=\dfrac{3}{4}:\dfrac{3}{8}\)

\(\Leftrightarrow x=\dfrac{3}{4}\times\dfrac{8}{3}\)

\(\Leftrightarrow x=2\)

d) \(\dfrac{4}{5}\times x=\dfrac{3}{7}\)

\(\Leftrightarrow x=\dfrac{3}{7}:\dfrac{4}{5}\)

\(\Leftrightarrow x=\dfrac{3}{7}\times\dfrac{5}{4}\)

\(\Leftrightarrow x=\dfrac{15}{28}\)

a, \(\dfrac{3}{5}+x=\dfrac{4}{3}\Leftrightarrow x=\dfrac{4}{3}-\dfrac{3}{5}=\dfrac{20-9}{15}=\dfrac{11}{15}\)

b, \(x+\dfrac{5}{6}=\dfrac{1}{7}\Leftrightarrow x=\dfrac{1}{7}-\dfrac{5}{6}=\dfrac{6-35}{42}=\dfrac{-29}{42}\)

c, \(\dfrac{3x}{8}=\dfrac{3}{4}\Leftrightarrow\dfrac{3x}{8}=\dfrac{6}{8}\Rightarrow3x=6\Leftrightarrow x=2\)

d, \(\dfrac{4x}{5}=\dfrac{3}{7}\Leftrightarrow\dfrac{28x}{35}=\dfrac{15}{35}\Rightarrow x=\dfrac{15}{28}\)

a, \(\dfrac{3}{5}\) + \(X\) = \(\dfrac{4}{3}\)

           \(X\) = \(\dfrac{4}{3}\) - \(\dfrac{3}{5}\)

           \(X\) = \(\dfrac{11}{15}\)

b, \(X\) + \(\dfrac{5}{6}\) = \(\dfrac{1}{7}\)

    \(X\)        = \(\dfrac{1}{7}\) - \(\dfrac{5}{6}\)

    \(X\)        = -\(\dfrac{29}{42}\)

c, \(X\) x \(\dfrac{3}{8}\) = \(\dfrac{3}{4}\)

    \(X\)       = \(\dfrac{3}{4}\) : \(\dfrac{3}{8}\)

    \(X\)       = 2

d, \(\dfrac{4}{5}\) x \(X\) = \(\dfrac{3}{7}\)

          \(X\) = \(\dfrac{3}{7}\) : \(\dfrac{4}{5}\)

          \(X\) = \(\dfrac{15}{28}\)

#Yu