Cho a,b khác 0. CMR: \(\frac{a^2}{b^2}+\frac{b^2}{a^2}+4\ge3\left(\frac{a}{b}+\frac{b}{a}\right)\)
Giúp với nhé các thiên tài
1.Cho a,b,c dương. CMR: \(\left(x+y+z\right)\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)\ge9\)
2. Cho a,b khác 0. CMR: \(a^4+b^4\le3\left(\frac{a^6}{b^2}+\frac{b^6}{a^2}\right)\)
CÁC THIÊN TÀI ĐÂU!!! Giúp với nhé!
1) Sửa lại:Cho x,y,z dương nhé!
\(\left(x+y+z\right)\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)=x\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)+y\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)+z\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)\)
\(=1+\frac{x}{y}+\frac{x}{z}+\frac{y}{x}+1+\frac{y}{z}+\frac{z}{x}+\frac{z}{y}+1=\left(1+1+1\right)+\left(\frac{x}{y}+\frac{x}{z}+\frac{y}{x}+\frac{y}{z}+\frac{z}{x}+\frac{z}{y}\right)\)
\(=3+\left(\frac{x}{y}+\frac{y}{x}\right)+\left(\frac{y}{z}+\frac{z}{y}\right)+\left(\frac{z}{x}+\frac{x}{z}\right)\)
Vì x,y,z là các số dương ,ta áp dụng bất đẳng thức Cô-Si:
\(\frac{x}{y}+\frac{y}{x}\ge2\sqrt{\frac{x}{y}.\frac{y}{x}}=2\)
\(\frac{y}{z}+\frac{z}{y}\ge2\sqrt{\frac{y}{z}.\frac{z}{y}}=2\)
\(\frac{z}{x}+\frac{x}{z}\ge2\sqrt{\frac{z}{x}.\frac{x}{z}}=2\)
Do đó \(\left(x+y+z\right)\left(\frac{1}{x}+\frac{1}{y}+\frac{1}{z}\right)\ge3+2+2+2=9\)
Dấu "=" xảy ra <=> \(x=y=z\)
câu 2) mk chịu
câu 2 đề sai . sửa số 3 thành số 2 . neu sua thanh co 2 thi co the ap dung bdt cosi hoac trebusep
Cho a,b khác o
CMR:\(\frac{a^2}{b^2}+\frac{b^2}{a^2}+4\ge3\left(\frac{a}{b}+\frac{b}{a}\right)\)
Lời giải :
Đặt \(\frac{a}{b}=t\Leftrightarrow\frac{b}{a}=\frac{1}{t}\)
BĐT \(\Leftrightarrow t^2+\frac{1}{t^2}+4\ge3\left(t+\frac{1}{t}\right)\)
\(\Leftrightarrow\left(t+\frac{1}{t}\right)^2-3\left(t+\frac{1}{t}\right)+2\ge0\)
\(\Leftrightarrow\left(t+\frac{1}{t}-1\right)\left(t+\frac{1}{t}-2\right)\ge0\)
\(\Leftrightarrow\frac{t^2-t+1}{t}\cdot\frac{t^2-2t+1}{t}\ge0\)
\(\Leftrightarrow\frac{\left(t^2-t+1\right)\left(t-1\right)^2}{t^2}\ge0\)( luôn đúng )
Dấu "=" xảy ra \(\Leftrightarrow t=1\Leftrightarrow\frac{a}{b}=1\Leftrightarrow a=b\)
1. Choa>b>0 . CMR:
a. \(a+\frac{1}{b\left(a-b\right)}\ge3\)
b. \(a+\frac{4}{\left(a-b\right)\left(b+1\right)^2}\ge3\)
c. \(a+\frac{1}{b\left(a-b\right)^2}\ge2\sqrt{2}\)
\(a-b+b+\frac{1}{b\left(a-b\right)}\ge3\sqrt[3]{\frac{\left(a-b\right)b.1}{b\left(a-b\right)}}=3\)
Dấu "=" xảy ra khi \(\left\{{}\begin{matrix}a=2\\b=1\end{matrix}\right.\)
\(VT=a-b+\frac{4}{\left(a-b\right)\left(b+1\right)^2}+\frac{b+1}{2}+\frac{b+1}{2}-1\)
\(VT\ge4\sqrt[4]{\frac{4\left(a-b\right)\left(b+1\right)^2}{4\left(a-b\right)\left(b+1\right)^2}}-1=3\)
Dấu "=" xảy ra khi \(\left\{{}\begin{matrix}b=1\\a=2\end{matrix}\right.\)
\(\frac{a-b}{2}+\frac{a-b}{2}+\frac{1}{b\left(a-b\right)^2}+b\ge4\sqrt[4]{\frac{b\left(a-b\right)^2}{4b\left(a-b\right)^2}}=\frac{4}{\sqrt{2}}=2\sqrt{2}\)
Dấu "=" xảy ra khi \(\left\{{}\begin{matrix}a=\frac{3\sqrt{2}}{2}\\b=\frac{\sqrt{2}}{2}\end{matrix}\right.\)
Cho a,b,c > 0 và abc = 1
CMR: \(\frac{2}{a^2\left(b+c\right)}+\frac{2}{b^2\left(a+c\right)}+\frac{2}{c^2\left(a+b\right)}\ge3\)
Cho a, b khác 0. CMR: \(\frac{a^2}{b^2}+\frac{b^2}{a^2}+4\ge3(\frac{a}{b}+\frac{b}{a})\)
Đặt \(\frac{a}{b}=t\)
Ta có:\(t^2+\frac{1}{t^2}+4\ge3\left(t+\frac{1}{t}\right)\)
\(\Leftrightarrow t^2+\frac{1}{t^2}+4-3t-\frac{3}{t}\ge0\)
\(\Leftrightarrow\left(t^2-2t+1\right)+\left(\frac{1}{t^2}-\frac{3}{t}+1\right)+2-t-\frac{1}{t}\ge0\)
\(\Leftrightarrow\left(t-1\right)^2+\left(\frac{1}{t}-1\right)^2+1-t-\frac{1}{t}+t\cdot\frac{1}{t}\ge0\)
\(\Leftrightarrow\left(t-1\right)^2+\left(\frac{1}{t}-1\right)^2+\left(t-1\right)\left(\frac{1}{t}-1\right)\ge0\)
Đặt \(\left(t-1;\frac{1}{t}-1\right)\rightarrow\left(p,q\right)\)
Ta có:
\(p^2+q^2+pq\ge0\)
\(\Leftrightarrow\left(p^2+pq+\frac{q^2}{4}\right)+\frac{3q^2}{4}\ge0\)
\(\Leftrightarrow\left(p+\frac{q}{2}\right)^2+\frac{3q^2}{4}\ge0\) *luôn đúng*
Chứng minh với \(a,b\in R\)(a, b khác 0), ta luôn có: \(\frac{a^2}{b^2}+\frac{b^2}{a^2}+4\ge3\left(\frac{a}{b}+\frac{b}{a}\right)\)
Cho \(\frac{1}{c}=\frac{1}{2}\left(\frac{1}{a}+\frac{1}{b}\right)\)(với a,b,c khác 0, b khác c)
CMR:\(\frac{a}{b}=\frac{a-c}{c-b}\)
Giúp mk nhé mina
Giúp tôi giải các bài toán sau với.
Bài 1: Cho 2 số a và b khác 0. Chứng minh rằng: \(y=\frac{4a^2b^2}{\left(a^2+b^2\right)^2}+\frac{a^2}{b^2}+\frac{b^2}{a^2}\ge3\)
cho a,b,c > 0 thỏa mãn \(a^2+b^2+c^2=3\) . Cmr:
\(\left(\frac{4}{a^2+b^2}+1\right)\left(\frac{4}{b^2+c^2}+1\right)\left(\frac{4}{c^2+a^2}+1\right)\ge3\left(a^2+b^2+c^2\right)\)