\(A=\frac{1}{2}-\frac{1}{4}+\frac{1}{8}-\frac{1}{16}+\frac{1}{32}-\frac{1}{64}+\frac{1}{128}-\frac{1}{256}\)

\(2A=1-\frac{1}{2}+\frac{1}{4}-\frac{1}{8}+\frac{1}{16}-\frac{1}{32}+\frac{1}{64}-\frac{1}{128}\)

\(A+2A=\left(\frac{1}{2}-\frac{1}{4}+...-\frac{1}{256}\right)+\left(1-\frac{1}{2}+\frac{1}{4}-...-\frac{1}{128}\right)\)

\(3A=1-\frac{1}{256}< 1\)

\(\Rightarrow A< \frac{1}{3}\).

1/2 + 1/4 +1/8 + 1/16 + 1/32 
= 16/32 + 3/32 + 4/32 + 2/32 + 1/32 

=26/32 =13/16

13/36 nha bn

\(\frac{1}{2}+\frac{1}{4}+\frac{1}{8}+\frac{1}{16}+\frac{1}{32}\)

\(=\frac{16}{32}+\frac{8}{32}+\frac{4}{32}+\frac{2}{32}+\frac{1}{32}\)

\(=\frac{31}{32}\)

A,(2016*2017-1)/2015*2017+2016

   =2015*2017+2016/2015*2017+2016

   =1

B,18*(1919/2121+888/999)

  =18*(19/21+8/9)

  =18*(19/21)+18*(8/9)=114/7+16=16+2/7+16=32/2/7

c,gọi s=1/2+1/4+...+1/32

2s=1+1/2+...+1/16

2s-s=(1+1/2+...+1/16)-(1/2+1/4+...+1/32)

s=1-1/32=31/32

a) \(27^{64}:81^{20}=3^{192}:3^{80}=3^{112}\)

b) \(\left(\dfrac{1}{8}\right)^{20}:\left(\dfrac{1}{16}\right)^9=\left(\dfrac{1}{2}\right)^{60}:\left(\dfrac{1}{2}\right)^{36}=\left(\dfrac{1}{2}\right)^{24}\)

c) \(\dfrac{1}{3}:\dfrac{1}{5}-\dfrac{1}{6}=\dfrac{5}{3}-\dfrac{1}{6}=\dfrac{10}{6}-\dfrac{1}{6}=\dfrac{9}{6}=\dfrac{3}{2}\)

Tk mình đi mọi người mình bị âm nè!

ai tk mình mình tk lại cho!!!

Cứu tớ với 

Ai đúng mình tự cho 

bài 5 ta tính tổng cả ba số đi rồi quy đồng tử số là ra có gì đâu

             \(\frac{1}{2}+\frac{1}{4}+...+\frac{1}{1024}\)

         = \(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{4}+....+\frac{1}{512}-\frac{1}{1024}\)

        =  \(1-\frac{1}{1024}\)

       = \(\frac{1023}{1024}\)

k mình nha các bạn