Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
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Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
I don't know English very much so i can't answere your question. Sory about that :(
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Given the right triangle ABC (A^ = 90o), BD is the bisector of the angle at B ( D of AC ). If AD = 6cm and AB = 12cm then the area of the right triangle ABC is ...... cm2.
Given a right triangle ABC (AB is perpendicular to AC) and tthe bisector BD (D \(\in\) AC). Find the area of ABC if AD = 6cm and CD = 10cm
ta có \(\frac{AB}{AD}=\frac{BC}{DC}\)
mà AB2+AC2=BC2
nên AB =12 ;BC=20
vậy diện h là:96
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Let ABC be an isoceles triangle (AB = AC) and its area is 501cm2. BD is the internal bisector of the angle ABC (D ∈ AC), E is a point on the opposite ray of CA such that CE = CB. I is a point on BC such that CI = 1/2 BI. The line EI meets AB at K, BD meets KC at H. Find the area of the triangle AHC.
bái phục giờ vẫn còn thi toán tiếng anh á ghê á nha
thi xog cấp tỉnh là vứt luôn nhác thi lắm luôn
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Let ABC be an isoceles triangle (AB = AC) and its area is 501cm2. BD is the internal bisector of the angle ABC (D ∈ AC), E is a point on the opposite ray of CA such that CE = CB. I is a point on BC such that CI = 1/2 BI. The line EI meets AB at K, BD meets KC at H. Find the area of the triangle AHC.
Giúp mình với! Mình sắp thi rồi.
Let ABC be an isoceles triangle (AB = AC) and its area is 501cm2. BD is the internal bisector of the angle ABC (D ∈ AC), E is a point on the opposite ray of CA such that CE = CB. I is a point on BC such that CI = 1/2 BI. The line EI meets AB at K, BD meets KC at H. Find the area of the triangle AHC.
Ghi lời giải dùm mình nha.
Thaks nhiều
Give the triangle ABC and the bisector BD, AB = 5cm, CB = 7cm. If the length of AD is 1cm less than the length of CD then the length of AC is ....... cm.
Because BD is bisector, we have: \(\frac{DC}{AD}=\frac{BC}{AB}=\frac{7}{5}\)
On the other hand, CD - AD = 1.
Hence we have \(\hept{\begin{cases}CD=3,5\\AD=2,5\end{cases}}\)
Thus the length of AC equal : 3,5 + 2,5 = 6 (cm).
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In triangle ABC, BC=AC and BCA=900. D and E are points on AC and AB respectively such that AD=AE and 2CD =BE.Let P be the point of intersection of BD with the bisector of angle CAB. What is the angle PCB in degrees?
In triangle ABC, BC=AC and BCA=900. D and E are points on AC and AB respectively such that AD=AE and 2CD =BE.Let P be the point of intersection of BD with the bisector of angle CAB. What is the angle PCB in degrees?