105 x 2 = ?
2 x -( 21 x 3 x 105-105 x 61 ) = -11 x 26
tính A=(2+1/315) x (1/651) - (1/105) x (3+650/651) - 4/(315x651) - (4/105)
Tính bằng cách thuận tiện 458 x 105 + 324 x 105 + 217 x 105 + 105
458 x 105 + 324 x 105 + 217 x 105 +105
= 105 x ( 458 + 324 + 217 + 1 )
= 105 x 1000
= 105000
Đây bạn nhé. Nhớ k cho mk nha
tìm x biết:
a, 10 - 2 x ( x - 1 ) = 44
b, ( x + 2 ) x 3 - 10 = 5
c, x - 105 : 5 = 10
d, ( x - 105 ) : 5 = 10
a, 10 - 2 x ( x - 1 ) = 44
2 x ( x - 1 ) = 10 - 44
2 x ( x - 1 ) = -34
x - 1 = -34 : 2
x - 1 = -17
x = -17 + 1
x = -16
Vậy x =-16
b, ( x + 2 ) x 3 - 10 = 5
( x + 2 ) x 3 = 5 + 10
( x + 2 ) x 3 = 15
x + 2 = 15 : 3
x + 2 = 5
x = 5 - 2
x = 3
Vậy x = 3
c, x - 105 : 5 = 10
x - 105 = 10 x 5
x - 105 = 50
x = 50 + 105
x = 155
Vậy x = 155
1. ( x-273 ) . 38 = 0
2. ( 179 -x ) - 12 = 57
3. x- 105 : 21 = 15
4. ( x - 105 ) : 21 = 15
Trình bày luôn nha
1) \(\left(x-273\right)\times38=0\)
\(\Rightarrow x-273=0:38\)
\(\Rightarrow x-273=0\)
\(\Rightarrow x=0+273\)
\(\Rightarrow x=273\)
Vậy x = 273
2) \(\left(179-x\right)-12=57\)
\(\Rightarrow179-x=57+12\)
\(\Rightarrow179-x=69\)
\(\Rightarrow x=179-69\)
\(\Rightarrow x=110\)
Vậy x = 110
3) \(x-105:21=15\)
\(\Rightarrow x-5=15\)
\(\Rightarrow x=15+5\)
\(\Rightarrow x=20\)
Vậy x = 20
4) \(\left(x-105\right):21=15\)
\(\Rightarrow x-105=15\times21\)
\(\Rightarrow x-105=315\)
\(\Rightarrow x=315+105\)
\(\Rightarrow x=420\)
Vậy x = 420
_Chúc bạn học tốt_
1. (x - 273).38 = 0
=> x - 273 = 0
=> x = 0 + 273
=> x = 273
vậy_
Tìm X biết:
1) X - 105 : 21 = 15
2) ( X - 105 ) : 21 = 15
3) ( 32 + X ) : 17 = X
4) 1818 : ( 6X - 37 ) = 18
1)\(x-105:21=15\)
\(x-5=15\)
\(x=15+5\)
\(x=20\)
Vậy \(x=20.\)
2)\(\left(x-105\right):21=15\)
\(\left(x-105\right)=15.21\)
\(x-105=315\)
\(x=315+105\)
\(x=420\)
Vậy \(x=412.\)
4)\(1818:\left(6x-37\right)=18\)
\(6x-37=1818:18\)
\(6x-37=101\)
\(6x=101+37\)
\(6x=138\)
\(x=138:6\)
\(x=23\)
Vậy \(x=23.\)
mk quên,còn phần 3) nữa:
3)\(\left(32+x\right):17=x\)
\(32+x=x.17\)
\(\Leftrightarrow x=2\)
Vậy \(x=2.\)
(x+1)+(x+2)+(x+3)+...+(x+10)=105
(x+1)+(x+2)+(x+3)+...+(x+10)=105
(x+x+x+...+x)+(1+2+3+...+10)\(\text{((10+1)x10:2)}\)=55có 10 số x: 105-55=50mỗi số x = 5vì 50 : 10 =5Số số hạng trong khoảng từ 1 đến 10 là (10-1):1+1=10(số)
Tổng của dãy số từ 1 đến 10 là:
\(\dfrac{10\cdot\left(10+1\right)}{2}=55\)
\(\left(x+1\right)+\left(x+2\right)+\left(x+3\right)+...+\left(x+10\right)=105\)
=>\(10x+\left(1+2+3+...+10\right)=105\)
=>\(10x+55=105\)
=>10x=50
=>x=5
(X+1)+(x+2)+(x+3)+...+(x+10)=105
10x+(1+2+3+...+10)=105
10x+(10+1).10:2=105
10x+55=105
10x. =105-55
10x. =50
X. = 50:10
X. =5.
tìm x
a; 35-15+x=70
b; 568-(2.x+14)=15
c; x-105:21=15
d; (x-105).21=15
a) 35-15+x=70
=> 20+x=70
=> x=50
b) 568-(2x+14)=15
=> 2x+14=553
=> 2x=539
=> x=269,5
c) x-105:21=15
=> x-5=15
=> x=20
d) (x-105)*21=15
=> x-105=5/7
=> x=5/7+105
=> x=740/7
a, 35 - 15 + x = 70 b, 568 - (2.x + 14 )= 15
x = 70 - 35 + 15 2.x + 14 = 568 - 15
x = 50 2.x + 14 =553 => 2.x =553-14=539 =>x=539 : 2 =269.5
c, x - 105 : 21 =15 d, (x - 105) . 21 = 15
x - 105 = 15 x 21 x - 105 = 15 : 21
x - 105 = 315 x - 105 = \(\frac{5}{7}\)
x = 315+105 x = \(\frac{5}{7}\)+ 105
x = 420 x = \(\frac{740}{7}\)
a/ 35-15+x=70 b/ 569-(2x+14)=15 c/ x-105:21=15 d/(x-105).21 =15
20+x =70 2x+14 =569-15 x-5 =15 x-105 =15:21
x =70-20 2x+14 =554 x =15+5 x-105 =5/7
x =50 2x =554-14 x =20 x=5/7+105
x=740/7
2x =540
x =540 : 2
x =270
Tính: 14 x 2 + 105