Ta có:

\(\frac{196}{197+198}<\frac{196}{197}\)

\(\frac{197}{197+198}<\frac{197}{198}\)

\(\Rightarrow\frac{196}{197+198}+\frac{197}{197+198}<\frac{196}{197}+\frac{197}{198}\left(1\right)\)

Mà \(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\left(2\right)\)

Từ ( 1 ) và ( 2 )

\(\Rightarrow B<\frac{196}{197}+\frac{197}{198}\)

\(\Rightarrow B

Gọi 196/197 là a/c, 197/198 la b/d

Có a/c+b/d=a+b/c+d( tính chất của dãy tỉ số bằng nhau)

\(A=\frac{196}{197}+\frac{197}{198}\)            \(B=\frac{196+197}{197+198}\)          

 \(A=\frac{196}{197}+\frac{197}{198}\)           \(B=\frac{196}{197+198}+\frac{197}{197+198}\)

Ta có: \(\frac{196}{197}>\frac{196}{197+198}\) vì \(197<197+198\)

         \(\frac{197}{198}>\frac{197}{197+198}\) vì \(198<197+198\)

\(\Rightarrow\)\(\frac{196}{197}+\frac{197}{198}\)  \(>\frac{196}{197+198}+\frac{197}{197+198}\)

\(\Leftrightarrow\)\(\frac{196}{197}+\frac{197}{198}\)\(>\)\(\frac{196+197}{197+198}\)

Vậy \(A>B\)

\(Do:\frac{196}{197}>\frac{196}{197+198}\)

         \(\frac{197}{198}>\frac{197}{197+198}\)

\(\Rightarrow\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}=\frac{196+197}{197+198}\)

Vậy : \(A>B\)

\(A>B\)

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\(A>\frac{196}{198}+\frac{197}{198}=\frac{196+197}{198}>\frac{196+197}{197+198}=B\)

=>A>B

vậy...

A>B nhé bạn

196+197/197+198=196/197+198   +   197/197+198

=>A>B

Ta có :

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

Mà \(\frac{196}{197}>\frac{196}{197+198}\)và \(\frac{197}{198}>\frac{197}{197+198}\)

\(\Leftrightarrow A>B\)

Ta có : \(A=\frac{196}{197}+\frac{197}{198}=\frac{196.198}{197.198}+\frac{197.197}{198.197}=\frac{196.198+197.197}{197.198}>\frac{196+197}{197+198}=B\)

\(\Rightarrow A>B\)

câu trả lời là :

  A= \(\frac{196}{197}\)>  \(\frac{197}{198}\)

tui trả lời lộn

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

ta có:

\(\frac{196}{197}>\frac{196}{197+198};\frac{197}{198}>\frac{197}{197+198}\)

=>A=\(\frac{196}{197}+\frac{197}{198}\)>B=\(\frac{196+197}{197+198}\)

=>A>B

Ta có:

\(A=\frac{196}{197}+\frac{197}{198}\) và \(B=\frac{196}{197+198}+\frac{197}{197+198}\)

Ta xét:

\(\frac{196}{197}>\frac{196}{197+198}\)

\(\frac{197}{198}>\frac{197}{197+198}\)

\(\Rightarrow\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}\)

\(\Rightarrow A>B\)

A = 196/197 + 197/198 > 196/197+198 + 197/197+198

A > 196 + 197/197 + 198

A > B

cho tui lời giải nữa nha^^

\(B=\frac{196+197}{197+198}=\frac{196}{197+198}+\frac{197}{197+198}\)

\(Vì\frac{196}{197}>\frac{196}{197+198}Và\frac{197}{198}>\frac{197}{197+198}\)

Suy ra \(\frac{196}{197}+\frac{197}{198}>\frac{196}{197+198}+\frac{197}{197+198}\)

Suy ra A>B