\(\left(x+2,5\right):2\frac{1}{2}-1,5=-1\frac{1}{4}\)
Những câu hỏi liên quan
1) frac{2}{5}xfrac{1}{3}-frac{2}{15}:frac{1}{5}+frac{3}{5}xfrac{1}{3}2)left(3frac{1}{3}+2,5right):left(3frac{1}{6}-4frac{1}{5}right)-frac{11}{31}3)left[6+left(frac{1}{2}right)^3-left|-frac{1}{2}right|right]:frac{3}{12}4)frac{18}{37}+frac{8}{24}+frac{19}{37}-1frac{23}{24}+frac{2}{3}5)left(-2right)^3xleft(frac{3}{4}-0,25right):left(2frac{1}{4}-1frac{1}{6}right)6)left(frac{2}{5}right)^2+5frac{1}{2}xleft(45-2right)+frac{23}{4}7)frac{4}{9}-19frac{1}{3}-frac{4}{9}x39frac{1}{3}8)left(-frac{1}{2}right)^...
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1) \(\frac{2}{5}x\frac{1}{3}-\frac{2}{15}:\frac{1}{5}+\frac{3}{5}x\frac{1}{3}\)
2)\(\left(3\frac{1}{3}+2,5\right):\left(3\frac{1}{6}-4\frac{1}{5}\right)-\frac{11}{31}\)
3)\(\left[6+\left(\frac{1}{2}\right)^3-\left|-\frac{1}{2}\right|\right]:\frac{3}{12}\)
4)\(\frac{18}{37}+\frac{8}{24}+\frac{19}{37}-1\frac{23}{24}+\frac{2}{3}\)
5)\(\left(-2\right)^3x\left(\frac{3}{4}-0,25\right):\left(2\frac{1}{4}-1\frac{1}{6}\right)\)
6)\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}x\left(45-2\right)+\frac{23}{4}\)
7)\(\frac{4}{9}-19\frac{1}{3}-\frac{4}{9}x39\frac{1}{3}\)
8)\(\left(-\frac{1}{2}\right)^2:\frac{1}{4}-2x\left(-\frac{1}{2}\right)^2\)
9)\(125\%x\left(-\frac{1}{2}\right)^3:\left(1\frac{5}{16}-1,5\right)+2008^0\)
giúp mình nha mai mình học rùi
Xem thêm câu trả lời
Thực hiện phép tính :a, sqrt{12frac{1}{4}}.left(-frac{2}{7}right)^2-left[2,left(4right).2frac{5}{11}right]:(-frac{42}{5})b, left(1-frac{1}{2}right).left(1-frac{1}{3}right).left(1-frac{1}{4}right)...left(1-frac{1}{2007}right)c, frac{0,375-0,3+frac{3}{11}+frac{3}{12}}{-0,625+0,5-frac{5}{11}-frac{5}{12}}+frac{1,5+1-0,75}{2,5+frac{5}{3}-1,25}Các bạn giải nhanh giúp mình nha!
Đọc tiếp
Thực hiện phép tính :
a, \(\sqrt{12\frac{1}{4}}.\left(-\frac{2}{7}\right)^2-\left[2,\left(4\right).2\frac{5}{11}\right]:(-\frac{42}{5})\)
b, \(\left(1-\frac{1}{2}\right).\left(1-\frac{1}{3}\right).\left(1-\frac{1}{4}\right)...\left(1-\frac{1}{2007}\right)\)
c, \(\frac{0,375-0,3+\frac{3}{11}+\frac{3}{12}}{-0,625+0,5-\frac{5}{11}-\frac{5}{12}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
Các bạn giải nhanh giúp mình nha!
a)\(/x-2/=2\)
b)\(/x-\frac{4}{5}/=\frac{3}{4}\)
c)\(6-/\frac{1}{2}-x/=\frac{2}{5}\)
d)\(\frac{1}{5}-/\frac{1}{5}\cdot x/=\frac{1}{5}\)
e)\(-2,5+/3x+5/=-1,5\)
g)\(\left(\frac{2}{3}x-1\right)+\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
a ) \(\left|x-2\right|=2\)
\(\Rightarrow\orbr{\begin{cases}x-2=2\\x-2=-2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=2+2\\x=-2+2\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=4\\x=0\end{cases}}\)
Vậy \(x=4\) hoặc \(x=0\)
b ) \(\left|x-\frac{4}{5}\right|=\frac{3}{4}\)
\(\Rightarrow\orbr{\begin{cases}x-\frac{4}{5}=\frac{3}{4}\\x-\frac{4}{5}=-\frac{3}{4}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{4}+\frac{4}{5}\\x=-\frac{3}{4}+\frac{4}{5}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{15}{20}+\frac{16}{20}\\-\frac{15}{20}+\frac{16}{20}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{31}{20}\\x=\frac{1}{20}\end{cases}}\)
Vậy \(x=\frac{31}{20}\) hoặc \(x=\frac{1}{20}\)
c ) \(6-\left|\frac{1}{2}-x\right|=\frac{2}{5}\)
\(\left|\frac{1}{2}-x\right|=6-\frac{2}{5}\)
\(\left|\frac{1}{2}-x\right|=\frac{28}{5}\)
\(\Rightarrow\orbr{\begin{cases}\frac{1}{2}-x=\frac{28}{5}\\\frac{1}{2}-x=-\frac{28}{5}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{1}{2}-\frac{28}{5}\\x=\frac{1}{2}-\left(-\frac{28}{5}\right)\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{51}{10}\\x=\frac{61}{10}\end{cases}}\)
Vậy \(x=-\frac{51}{10}\) hoặc \(x=\frac{61}{10}\)
d ) \(\frac{1}{5}-\left|\frac{1}{5}.x\right|=\frac{1}{5}\)
\(\left|\frac{1}{5}.x\right|=\frac{1}{5}-\frac{1}{5}\)
\(\left|\frac{1}{5}.x\right|=0\)
\(\Rightarrow\frac{1}{5}.x=0\)
\(x=0:\frac{1}{5}\)
\(x=0\)
Vậy \(x=0\)
e ) \(-2,5+\left|3x+5\right|=-1,5\)
\(\left|3x+5\right|=-1,5-\left(-2,5\right)\)
\(\left|3x+5\right|=1\)
\(\Rightarrow\orbr{\begin{cases}3x+5=1\\3x+5=-1\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x=1-5\\3x=-1-5\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}3x=-4\\3x=-6\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-4:3\\x=-6:3\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=-\frac{4}{3}\\x=-2\end{cases}}\)
Vậy \(x=-\frac{4}{3}\) hoặc \(x=-2\)
g ) \(\left(\frac{2}{3}x-1\right)+\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
\(\Rightarrow\orbr{\begin{cases}\left(\frac{2}{3}x-1\right)=0\\\left(\frac{3}{4}x+\frac{1}{2}\right)=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x-1=0\\\frac{3}{4}x+\frac{1}{2}=0\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x=0+1\\\frac{3}{4}x=0-\frac{1}{2}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}\frac{2}{3}x=1\\\frac{3}{4}x=-\frac{1}{2}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=1:\frac{2}{3}\\x=-\frac{1}{2}:\frac{3}{4}\end{cases}}\)
\(\Rightarrow\orbr{\begin{cases}x=\frac{3}{2}\\x=-\frac{2}{3}\end{cases}}\)
Vậy \(x=\frac{3}{2};x=-\frac{2}{3}\)
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Trả lời:
a, | x - 2 | = 2
=> x - 2 = 2 hoặc x - 2 = -2
=> x = 4 x = 0
Vậy x = 4; x = 0
b, \(\left|x-\frac{4}{5}\right|=\frac{3}{4}\)
\(\Rightarrow x-\frac{4}{5}=\frac{3}{4}\)hoặc \(x-\frac{4}{5}=\frac{-3}{4}\)
\(\Rightarrow x=\frac{31}{20}\)hoặc \(x=\frac{1}{20}\)
Vậy \(x=\frac{31}{20};x=\frac{1}{20}\)
c, \(6-\left|\frac{1}{2}-x\right|=\frac{2}{5}\)
\(\Rightarrow\left|\frac{1}{2}-x\right|=\frac{28}{5}\)
\(\Rightarrow\frac{1}{2}-x=\frac{28}{5}\)hoặc \(\frac{1}{2}-x=\frac{-28}{5}\)
\(\Rightarrow x=\frac{-51}{10}\)hoặc \(x=\frac{61}{10}\)
Vậy \(x=\frac{-51}{10};x=\frac{61}{10}\)
d, \(\frac{1}{5}-\left|\frac{1}{5}\cdot x\right|=\frac{1}{5}\)
\(\Rightarrow\left|\frac{1}{5}\cdot x\right|=0\)
\(\Rightarrow\frac{1}{5}\cdot x=0\)
\(\Rightarrow x=0\)
Vậy x = 0
e, \(-2,5+\left|3x+5\right|=-1,5\)
\(\Rightarrow\left|3x+5\right|=1\)
\(\Rightarrow3x+5=1\)hoặc \(3x+5=-1\)
\(\Rightarrow3x=-4\)hoặc \(3x=-6\)
\(\Rightarrow x=\frac{-4}{3}\)hoặc \(x=-2\)
Vậy \(x=\frac{-4}{3};x=-2\)
g, \(\left(\frac{2}{3}x-1\right)+\left(\frac{3}{4}x+\frac{1}{2}\right)=0\)
\(\Rightarrow\frac{2}{3}x-1+\frac{3}{4}x+\frac{1}{2}=0\)
\(\Rightarrow\frac{17}{12}x-\frac{1}{2}=0\)
\(\Rightarrow\frac{17}{12}x=\frac{1}{2}\)
\(\Rightarrow x=\frac{6}{17}\)
Vậy \(x=\frac{6}{17}\)
Bài 1: Tìm x thuộc Z, biết: 12 - x = 4( 2x - 3 ) + 2
Bài 2: Tìm giá trị của các biểu thức sau:
a, \(\left(-1,5\right).\frac{-2}{3}+\left(2,5-\frac{3}{4}\right):1\frac{3}{4}\)
b, \(B=\frac{1}{1.4}+\frac{1}{4.7}+\frac{1}{7.10}+....+\frac{1}{100.103}\)
Mk cần gấp
tìm x
\(\left|2,5-x\right|=1,3\)
\(\left|x-1,5\right|+\left|2,5-x\right|=0\)
\(\left(x-\frac{1}{2}\right)^2=0\)
\(\left(x-2\right)^2=1\)
|2,5-x|=1,3
\(\orbr{\begin{cases}2,5-x=1,3\\2,5-x=-1,3\end{cases}}\Rightarrow\orbr{\begin{cases}x=1,2\\x=3,8\end{cases}}\)
Vậy x=1,2 hoặc x=3,8
|x-1,5|+|2,5-x|=0
\(\Rightarrow\hept{\begin{cases}VT:x-1,5=0\\VP:2,5-x=0\end{cases}}\Rightarrow\hept{\begin{cases}x=1,5\\x=2,5\end{cases}}\)
Vậy x của VT là 1,5 và x của VP là 2,5
\(\left(x-\frac{1}{2}\right)^2=0\)
\(\Rightarrow x-\frac{1}{2}=0\)
x=\(0+\frac{1}{2}\)
x=\(\frac{1}{2}\)
(x-2)2=1
=> x-2=1
x=1+2
x=3
=> x-2=-1
x=(-1)+2
x=1
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a, / 2,5 - x / = 1,3
Với 2,5 - x > hoặc = 0 => 2, 5 - x = 1,3
=> x = 1, 2
Với 2,5 - x < hoặc = 0 => - ( 2,5 - x ) = 1,3
=> - 2,5 + x = 1,3
=> x = 3,8
Vậy x thuộc tập hợp 1,2 ; 3,8
p/s: > hoặc = 0, < hoặc = 0 , thuộc tập hợp bạn ghi kí hiệu nha
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Bài 1:
1) \(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
2) \(\frac{0,375-0,3+\frac{3}{11}-\frac{3}{17}}{0,625-0,5+\frac{5}{11}-\frac{5}{17}}+\frac{1,5+1-0,75}{2,5+\frac{5}{3}-1,25}\)
tìm x
a) \(\frac{3}{4}+\frac{1}{4}.x=\frac{1}{2}+\frac{1}{2}.x\)
b) \(\frac{1}{3}.x-\frac{2}{5}.\left(x+1\right)=0\)
c)\(\left(\frac{1}{4}.x-1,5\right)+\left(\frac{5}{6}.x-3\right)-\left(\frac{5}{8}.x-0,5\right)=-4,5\)
a) \(\frac{3}{4}+\frac{1}{4}.x=\frac{1}{2}+\frac{1}{2}x\)
\(\Rightarrow3.\frac{1}{4}+\frac{1}{4}.x=\frac{1}{2}.\left(x+1\right)\)
\(\Rightarrow\frac{1}{4}.\left(x+3\right)=\frac{1}{2}.\left(x+1\right)\)
\(\Rightarrow\frac{x+1}{x+3}=\frac{1}{4}:\frac{1}{2}=\frac{1}{2}\)\(\Rightarrow\left(x+1\right).2=x+3\Rightarrow2x+2=x+3\)
\(\Rightarrow2x-x=3-2\Rightarrow x=1\)
vay x=1
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1. \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
2 . \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
3 . \(4\left(3x-2\right)-3\left(x-4\right)=7x+10\)
4. \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
1) \(\frac{7}{8}x-5\left(x-9\right)=\frac{20x+1,5}{6}\)
<=> \(\frac{21x}{24}-\frac{100\left(x-9\right)}{24}=\frac{80x+6}{24}\)
<=> 21x - 100x + 900 = 80x + 6
<=> -79x - 80x = 6 - 900
<=> -159x = -894
<=> x = 258/53
Vậy S = {258/53}
2) \(\frac{\left(2x+1\right)^2}{5}-\frac{\left(x+1\right)^2}{3}=\frac{7x^2-14x-5}{15}\)
<=> \(\frac{3\left(4x^2+4x+1\right)}{15}-\frac{5\left(x^2+2x+1\right)}{15}=\frac{7x^2-14x-5}{15}\)
<=> 12x2 + 12x + 3 - 5x2 - 10x - 5 = 7x2 - 14x - 5
<=> 7x2 + 2x - 7x2 + 14x = -5 + 2
<=> 16x = 3
<=> x = 3/16
Vậy S = {3/16}
3) 4(3x - 2) - 3(x - 4) = 7x+ 10
<=> 12x - 8 - 3x + 12 = 7x + 10
<=> 9x - 7x = 10 - 4
<=> 2x = 6
<=> x = 3
Vậy S = {3}
4) \(\frac{\left(x+10\right)\left(x+4\right)}{12}-\frac{\left(x+4\right)\left(2-x\right)}{4}=\frac{\left(x+10\right)\left(x-2\right)}{3}\)
<=> \(\frac{x^2+14x+40}{12}+\frac{3\left(x^2+2x-8\right)}{12}=\frac{4\left(x^2+8x-20\right)}{12}\)
<=> x2 + 14x + 40 + 3x2 + 6x - 24 = 4x2 + 32x - 80
<=> 4x2 + 20x - 4x2 - 32x = -80 - 16
<=> -12x = -96
<=> x = 8
Vậy S = {8}
1.Tìm x biếta) left(frac{2}{5}-xright):1frac{1}{3}+frac{1}{2}-4b) left(-3+frac{3}{x}-frac{1}{3}right):left(1+frac{2}{5}+frac{2}{3}right)-frac{5}{4}c) frac{-3x}{4}.left(frac{1}{x}+frac{2}{7}right)0d) 3-frac{1-frac{1}{2}}{1+frac{1}{x}}2frac{2}{3}e)left(2x+frac{1}{3}right)^2frac{9}{16}f) 4^x+4^{x+3}4160g) left(x-2,5right):1frac{1}{2}x:2h) left(frac{1}{3}+xright):left(x+frac{3}{4}right)frac{7}{9}i) 0,81:frac{x}{2}frac{16}{x^4}:left(-0,9right)2. Tìm x, biết:a)left(152frac{2}{4}-148frac{3}{8}right):0,...
Đọc tiếp
1.Tìm x biết
a) \(\left(\frac{2}{5}-x\right)\):\(1\frac{1}{3}+\frac{1}{2}=-4\)
b) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
c) \(\frac{-3x}{4}.\left(\frac{1}{x}+\frac{2}{7}\right)=0\)
d) 3-\(\frac{1-\frac{1}{2}}{1+\frac{1}{x}}=2\frac{2}{3}\)
e)\(\left(2x+\frac{1}{3}\right)^2=\frac{9}{16}\)
f) \(4^x+4^{x+3}=4160\)
g) \(\left(x-2,5\right):1\frac{1}{2}=x:2\)
h) \(\left(\frac{1}{3}+x\right):\left(x+\frac{3}{4}\right)=\frac{7}{9}\)
i) 0,81:\(\frac{x}{2}=\frac{16}{x^4}:\left(-0,9\right)\)
2. Tìm x, biết:
a)\(\left(152\frac{2}{4}-148\frac{3}{8}\right):0,2=x:0,3\)
b) \(\left[\left(6\frac{3}{5}-3\frac{3}{14}\right):2,5\right]:\left(21-1,25\right)=x:5\frac{5}{6}\)
a ) \(\left(\frac{2}{5}-x\right):1\frac{1}{3}+\frac{1}{2}=-4\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}+\frac{1}{2}=-4\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}=-4-\frac{1}{2}\)
\(\left(\frac{2}{5}-x\right):\frac{4}{3}=-\frac{9}{2}\)
\(\frac{2}{5}-x=-\frac{9}{2}.\frac{4}{3}\)
\(\frac{2}{5}-x=-3\)
\(x=\frac{2}{5}-\left(-3\right)\)
\(x=\frac{2}{5}+3\)
\(x=\frac{3}{5}-\frac{15}{5}\)
\(x=-\frac{12}{5}\)
Vay \(x=-\frac{12}{5}\)
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b ) \(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(1+\frac{2}{5}+\frac{2}{3}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(\frac{15}{15}+\frac{6}{15}+\frac{10}{15}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\left(\frac{15+6+10}{15}\right)=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right):\frac{31}{15}=-\frac{5}{4}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right)=-\frac{5}{4}.\frac{31}{15}\)
\(\left(-3+\frac{3}{x}-\frac{1}{3}\right)=-\frac{1}{4}.\frac{31}{3}\)
\(-3+\frac{3}{x}-\frac{1}{3}=-\frac{31}{12}\)
\(-3+\frac{3}{x}=-\frac{31}{12}+\frac{1}{2}\)
\(-3+\frac{3}{x}=-\frac{31}{12}+\frac{6}{12}\)
\(-3+\frac{3}{x}=\frac{-25}{12}\)
\(\frac{3}{x}=\frac{-25}{12}+3\)
\(\frac{3}{x}=\frac{-25}{12}+\frac{36}{12}\)
\(\frac{3}{x}=\frac{5}{6}\)
\(\frac{18}{6x}=\frac{5x}{6x}\)
Đèn dây , bạn tự làm tiếp nhé , de rồi chứ
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