Tính \(\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}+\frac{7}{33.43}\)
Những câu hỏi liên quan
A=\(\left(1+\frac{1}{2}\right)\left(1+\frac{1}{3}\right)\left(1+\frac{1}{4}\right)...\left(1+\frac{1}{98}\right)\left(1+\frac{1}{99}\right)\)
B=\(\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}+\frac{7}{33.43}+\frac{7}{43.53}+\frac{7}{53.63}\)
\(B=\frac{7}{3.13}+\frac{7}{13.23}+...+\frac{7}{53.63}\)
\(B=10.\left(\frac{1}{3.13}+\frac{1}{13.23}+....+\frac{1}{53.63}\right)\)
\(B=10.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+...+\frac{1}{53}+\frac{1}{63}\right)\)
\(B=10.\left(\frac{1}{3}-\frac{1}{63}\right)\)
\(B=10.\frac{20}{63}\)
\(B=\frac{200}{63}\)
Đúng 0
Bình luận (0)
Tính A = 7/3.13+7/13.23+7/23.33+7/33.43+7/43.53+7/53.63
là khoảng cách : 13 - 3 = 10 thì ta cho 10 là mẫu số của 7, bn hiểu ko???
Đúng 0
Bình luận (0)
A \(=\frac{7}{3.13}+\frac{7}{13.23}+...+\frac{7}{53.63}=\frac{7}{10}.\left(\frac{10}{3.13}+\frac{10}{13.23}+...+\frac{10}{53.63}\right)\)
\(=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+...+\frac{1}{53}-\frac{1}{63}\right)=\frac{7}{10}.\left(\frac{1}{3}-\frac{1}{63}\right)\)
\(=\frac{7}{10}.\frac{20}{63}=\frac{2}{9}\)
đúng cái nhé
Đúng 1
Bình luận (0)
\(A=\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}+.......+\frac{7}{53.63}\)
ƯU TIÊN DƯỚI 25 NHÁ
\(A=\frac{7}{3.13}+\frac{7}{13.23}+...+\frac{7}{53.63}\)
\(A=7.\left(\frac{1}{3.13}+\frac{1}{13.23}+...+\frac{1}{53.63}\right)\)
\(10A=7.\left(\frac{10}{3.13}+\frac{10}{13.23}+...+\frac{10}{53.63}\right)\)
\(10A=7.\left(\frac{1}{3}-\frac{1}{63}\right)\)
\(10A=7.\frac{20}{63}\)
\(10A=\frac{20}{9}\)
\(A=\frac{20}{9}:10\)
\(A=\frac{20}{9}.\frac{1}{10}\)
\(A=\frac{2}{9}\)
Vậy A=\(\frac{2}{9}\)
Chúc bạn học tốt~
Đúng 0
Bình luận (0)
A = \(\frac{7}{3.13}\)\(+\)\(\frac{7}{13.23}\)\(+\)\(\frac{7}{23.33}\)\(+\).......... \(+\)\(\frac{7}{53.63}\)
\(\Rightarrow\)A = 7 . (\(\frac{1}{3.13}\)\(+\)\(\frac{1}{13.23}\)\(+\)\(\frac{1}{23.33}\)\(+\)...... \(\frac{1}{53.63}\))
\(\Rightarrow\)A = \(\frac{1}{10}\). 7 . ( \(\frac{1}{3}\)\(-\)\(\frac{1}{13}\)\(+\)\(\frac{1}{13}\)\(-\)\(\frac{1}{23}\)\(+\)\(\frac{1}{23}\)\(-\)\(\frac{1}{33}\)\(+\)....... \(+\)\(\frac{1}{53}\)\(-\)\(\frac{1}{63}\))
\(\Rightarrow\)A = \(\frac{7}{10}\). ( \(\frac{1}{3}\)\(-\)\(\frac{1}{63}\))
\(\Rightarrow\)A = \(\frac{7}{10}\). \(\frac{20}{63}\)
\(\Rightarrow\)A = \(\frac{2}{9}\)
Chúc các anh em học tốt !!!
Đúng 0
Bình luận (0)
A=1/3-1/13+1/13-1/23+1/23-1/33+.........+1/53-1/63
=1/3-1/63
=21/63-1/63
=20/63
Đúng 0
Bình luận (0)
A=7/3.13+7/13.23+7/23.33+7/33.43+7/43.53+7/53.63 giúp mình nha bài toán tính nhanh phân số nha
A=7/10.(1/3 - 1/13 + 1/13 - 1/23 +.......+ 1/53 - 1/63)
= 7/10 .( 1/3 - 1/63 )
=7/10 . 20/63
= 2/9
Đúng 0
Bình luận (0)
A=7/10.(1/3 - 1/13 + 1/13 - 1/23 +.......+ 1/53 - 1/63)
A = 7/10 .( 1/3 - 1/63 )
A =7/10 . 20/63
A = 2/9
Đúng 0
Bình luận (0)
Đố mấy bạn
A = \(\frac{7}{3.13}\) +\(\frac{7}{13.23}\) + \(\frac{7}{23.33}\) +\(\frac{7}{43.53}\) +\(\frac{7}{53.63}\)
A=\(\frac{7}{10}\)*(\(\frac{10}{3\cdot13}\)+\(\frac{10}{13\cdot23}\)+\(\frac{10}{23\cdot33}\)+\(\frac{10}{43\cdot53}\)+\(\frac{10}{53\cdot63}\))
A=\(\frac{7}{10}\)*(\(\frac{1}{3}\)-\(\frac{1}{13}\)+\(\frac{1}{13}\)-\(\frac{1}{23}\)+\(\frac{1}{23}\)-\(\frac{1}{33}\)+\(\frac{1}{43}\)-\(\frac{1}{53}\)+\(\frac{1}{53}\)-\(\frac{1}{63}\))
A=\(\frac{7}{10}\)*(\(\frac{1}{3}\)-\(\frac{1}{33}\)+\(\frac{1}{43}\)-\(\frac{1}{63}\))
A=\(\frac{7}{10}\)*(\(\frac{10}{33}\)+\(\frac{20}{2709}\))
A=\(\frac{7}{10}\)*\(\frac{9250}{29799}\)
A=\(\frac{925}{4257}\)
Đúng 0
Bình luận (1)
Xem thêm câu trả lời
Kết quả rút gọn biểu thức A là bao nhiêu, biết:
A=7/3.13+7/13.23+7/23.33+7/33.43+7/43.53+7/53.63
A.
−3/9
B.
−2/9
C.
3/9
D.
2/9
a)Tính\(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right)\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.23}+\frac{7}{23.33}}\)
b) Chứng tò rằng:\(1-\frac{1}{2}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{199}-\frac{1}{200}\)\(=\frac{1}{101}+\frac{1}{102}+...+\frac{1}{200}\)
phần a dễ bạn tự làm đi tử thì bạn tính như bình thường còn mẫu thì:7.(\(\frac{1}{3.13}\)+\(\frac{1}{13.23}\)+\(\frac{1}{23.33}\))
\(\frac{7}{10}\).(\(\frac{1}{3}\)-\(\frac{1}{33}\))=\(\frac{7}{33}\)
b)(1+1/3+1/5+..+1/199)-(1/2+1/4+...+1/200)
(1+1/2+1/3+...+1/199+1/200)-(1/2+1/2+1/4+1/4+...+1/200+1/200)
=1+1/2+1/3+...+1/199+1/200-(1+1/2+1/3+...+1/100)
=1/101+1/102+...+1/200
Đúng 0
Bình luận (0)
https://olm.vn/hoi-dap/question/60726.html
Đúng 0
Bình luận (0)
Tính S=\(\frac{5}{3.13}\)+ \(\frac{5}{13.23}\)+ \(\frac{5}{23.33}\)+ ....+ \(\frac{5}{83.33}\)
Nhanh! Khẩn cấp! Mai thì tớ thi rồi! Giải nhanh tớ tick cho!
\(S=\frac{5}{3.13}+\frac{5}{13.23}+.....+\frac{5}{83.93}\)
\(2S=\frac{2.5}{3.13}+\frac{2.5}{13.23}+....+\frac{2.5}{83.93}\)
\(2S=\frac{10}{3.13}+\frac{10}{13.23}+.....+\frac{10}{83.93}\)
\(2S=\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+....+\frac{1}{83}-\frac{1}{93}\)
\(2S=\frac{1}{3}-\frac{1}{93}=\frac{30}{93}\)
\(S=\frac{30}{93}.\frac{1}{2}=\frac{15}{93}\)
Đúng 1
Bình luận (0)
Sửa đề:
\(S=\frac{5}{3.13}+\frac{5}{13.23}+.....+\frac{5}{83.93}\)
\(S=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{13}+\frac{1}{13}-\frac{1}{23}+....+\frac{1}{83}-\frac{1}{93}\right)\)
\(S=\frac{1}{2}.\left(\frac{1}{3}-\frac{1}{93}\right)\)
\(S=\frac{1}{2}.\left(\frac{31}{93}-\frac{1}{93}\right)\)
\(S=\frac{1}{2}.\frac{10}{31}\)
\(S=\frac{5}{31}\)
Đúng 0
Bình luận (0)
Xem thêm câu trả lời
Tính nhanh (nếu có thể):
a,\(\frac{27^2.8^5}{66.32^3}\)
b, \(\frac{4^6.9^5+6^9.120}{8^4.3^{12}-6^{11}}\)
c, \(\frac{\left(17\frac{8}{19}-16\frac{9}{18}\right).\left(17,5+16\frac{17}{51}-32\frac{15}{22}\right)}{\frac{7}{3.13}+\frac{7}{13.3}+\frac{7}{23.33}}\)
a)\(\frac{243}{22}\)
b)\(\frac{4}{5}=0,8\)
Đúng 0
Bình luận (0)