Tìn x ạ?

-1 5/27-(3x-7/9)3=-24/27

 (3x-7/9)3 =-32/27-(-24/27)

 (3x-7/9)3=-8/27 

(3x-7/9)3=(-2/3)3

⇒3x-7/9=-2/3

  3x =-2/3+7/9

 3x =1/9

x =1/9:3

x =1/27

Chúc bạn học tốt!

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báo cáo

báo cáo nha NGÔ QUANG LÍ

-1 5/27-(3x-7/9)³=-24/27

           (3x-7/9)³ =-32/27-(-24/27)

           (3x-7/9)³=-8/27

           (3x-7/9)³=(-2/3)³

⇒3x-7/9=-2/3

   3x      =-2/3+7/9

   3x      =1/9

     x      =1/9:3

     x      =1/27

Chúc bạn học tốt!

-1 . \(\dfrac{5}{27}\) - \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = -\(\dfrac{24}{27}\)

\(\Rightarrow\) \(\dfrac{-5}{27}\) - \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = \(\dfrac{-24}{27}\)

\(\Rightarrow\) \(\left(3x.\dfrac{7}{9^{ }}\right)^3\) = \(\dfrac{-5}{27}\) - \(\dfrac{-24}{27}\) = \(\dfrac{19}{27}\)

\(\Rightarrow\) \(3^3\) . \(\dfrac{7^3}{3^6}\) = \(\dfrac{19}{3^3}\)

\(\Rightarrow\) \(\dfrac{x^3.7^3}{3^3}\) = \(\dfrac{19}{3^3}\)

\(\Rightarrow\) \(x^3\) . \(7^3\) = 19

=> [3x-7/9]^3= -8/27

=> 3x -7/9 = -2/3 => 3x = 1/9=> x= 1/27

đúng cái nhé

17 - 2x = -15

2x = 17 - (-15)

2x = 32

x = 32 : 2

x = 16

--------

54 : (x + 2) = -6

x + 2 = 54 : (-6)

x + 2 = -9

x = -9 - 2

x = -11

--------

12.(3 - x) = 72

3 - x = 72 : 12

3 - x = 6

x = 3 - 6

x = -3

-------

-3(x + 5) + 18 = -27

-3(x + 5) = -27 - 18

-3(x + 5) = -45

x + 5 = -45 : (-3)

x + 5 = 15

x = 15 - 5

x = 10

-------

(x + 5)² = 9

x + 5 = 3 hoặc x + 5 = -3

*) x + 5 = 3

x = 3 - 5

x = -2

*) x + 5 = -3

x = -3 - 5

x = -8

Vậy x = -8; x = -2

--------

(3 - x)³ = 27

(3 - x)³ = 3³

3 - x = 3

x = 3 - 3

x = 0

=00

- 3\(x\) + 24  = -24

  3\(x\)          = 24 + 24

   3\(x\)          = 48

     \(x\)           = 48 : 3

     \(x\)           = 16

\(\Leftrightarrow\left(3x-\dfrac{7}{9}\right)^3=-1-\dfrac{5}{27}+\dfrac{24}{27}=-1+\dfrac{19}{27}=-\dfrac{8}{27}\)

=>3x-7/9=-2/3

=>3x=-2/3+7/9=1/9

hay x=1/27

sửa nha chỗ 24/7 thay = \(-\frac{24}{7}\)

\(-1\frac{5}{27}-\left(3x-\frac{7}{9}\right)^3=-\frac{24}{27}\)

\(\left(3x-\frac{7}{9}\right)^3=\frac{-32}{27}-\left(-\frac{24}{27}\right)\)

\(\left(3x-\frac{7}{9}\right)^3=\frac{-8}{27}=\left(\frac{-2}{3}\right)^3\)

\(\Rightarrow3x-\frac{7}{9}=\frac{-2}{3}\)

\(3x=\frac{-2}{3}+\frac{7}{9}\)

\(3x=\frac{1}{9}\)

\(x=\frac{1}{9}:3\)

\(x=\frac{1}{27}\)

(3x-7/9)³ = -32/27-(-24/27)

(3x-7/9)³ = -8/27

(3x)³-(7/9)³ = -8/27

(3x³)-343/729 = -8/27

(3x)³ = -8/27+ -343/729

(3x)³ = -559/729

3³ *x³ = -559/729

9*x³ = -559/729

x³ = -559/729: 9

x³ = -559/6561

x = -0,4400282812