\(D=\frac{6}{15\times18}+\frac{6}{18\times21}+\frac{6}{21\times24}+...+\frac{6}{87\times90}\)

\(=2\times\left(\frac{3}{15\times18}+\frac{3}{18\times21}+...+\frac{3}{87\times90}\right)\)

\(=2\times\left(\frac{18-15}{15\times18}+\frac{21-18}{18\times21}+...+\frac{90-87}{87\times90}\right)\)

\(=2\times\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{87}-\frac{1}{90}\right)\)

\(=2\times\left(\frac{1}{15}-\frac{1}{90}\right)=\frac{1}{9}\)

=-3/4-5/7=-21/28-20/28=-41/28

\(\dfrac{-18}{24}-\dfrac{15}{21}=\dfrac{-3}{4}-\dfrac{5}{7}=\dfrac{-21}{28}-\dfrac{20}{28}=\dfrac{-41}{28}\)

3/4-5/7=-21/28-20/28=-41/28

k mik nha bn

\(A=\frac{9}{15.18}+\frac{9}{18.21}+.....+\frac{9}{89.92}\)

\(A=3.\left(\frac{3}{15.18}+\frac{3}{18.21}+....+\frac{3}{89.92}\right)\)

\(A=3.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+......+\frac{1}{89}-\frac{1}{92}\right)\)

\(A=3.\left(\frac{1}{15}-\frac{1}{92}\right)\)

\(A=3.\frac{77}{1380}=\frac{77}{460}\)

$A=\frac{9}{15.18}+\frac{9}{18.21}+.....+\frac{9}{89.92}$

$A=3.\left(\frac{3}{15.18}+\frac{3}{18.21}+....+\frac{3}{89.92}\right)$

$A=3.\left(\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+......+\frac{1}{89}-\frac{1}{92}\right)$

$A=3.\left(\frac{1}{15}-\frac{1}{92}\right)$

$A=3.\frac{77}{1380}=\frac{77}{460}$

260

1)1/6 - - 5/6 = 1/6 + 5/6 = 1

2)6/13 - -14/39 = 6/13 + 14/39= 32/39

3)4/5 - 4/-18 = 4/5 + 4/18= 46/45

4)7/21 - 9/-36 = 7/21 + 9/36 = 7/12

5)-12/18 - -21/35  = -12/18 + 21/35 = -1/15

6)-3/21 - 6/42 = -2/7

7)-18/24 - 15/21 = -41/28

8)1/6 - 2/5 =-7/30

1/15.18 + 1/18.21 + 1/21.24 + ... + 1/87.90

= 1/3.(3/15.18 + 3/18.21 + 3/21.24 + ... + 3/87.90)

= 1/3.(1/15 - 1/18  + 1/18 - 1/21 + 1/21 - 1/24 + ... + 1/97 - 1/90)

= 1/3.(1/15 - 1/90)

= 1/3.1/18

= 1/54

   Đặt tổng trên là A

3A = \(\frac{1\cdot3}{15\cdot18}+\frac{1\cdot3}{18\cdot21}+...+\frac{1\cdot3}{87\cdot90}\)

\(=\frac{1}{15}-\frac{1}{18}+\frac{1}{18}-\frac{1}{21}+...+\frac{1}{87}-\frac{1}{90}\)

\(=\frac{1}{15}-\frac{1}{90}\)

\(=\frac{1}{30}\)

\(A=\frac{1}{30}\div3=\frac{1}{30\cdot3}=\frac{1}{90}\)

                                 \(#Louis\)