X* 2.4+X/10=10
x×2.4+x÷10=10
Hai bạn có số quả táo là:
19 + 10 = 29 ( quả )
Đs: 29 quả táo
Ai tích mình thì mình tích lại
29 quả táo (nha)
Ai k mình mình k lại
bai giai
hai ban co so qua tao la :
19+10=29 (qua)
dap so : 29 qua
3/2.4^x+5/3.4^x 2=3/2.4^8+5/3.4^10
tìm x
x×2.4+x÷10=10
x=
\(x\times2,4+x:10=10\)
\(\Rightarrow x\times2,4+x\times0,1=10\)
\(\Rightarrow x\times\left(2,4+0,1\right)=10\)
\(\Rightarrow x\times2,5=10\)
\(\Rightarrow x=10:2,5\)
\(\Rightarrow x=4\)
x * 2,4 + x : 10 = 10
x * 2,4 + x * 0,1 = 10
x * ( 2,4 + 0,1) = 10
x * 2,5 = 10
x = 10 : 2,5
x = 4
tìm x:
x×2.4+x÷10=10
x=
X x 24/10 + X x 1/10 = 10
X x (24/10+1/10) = 10
X x 25/10 = 10
X=10:25/10
X=4
X x 24/10 + X x 1/10 = 10
X x (24/10+1/10) = 10
X x 25/10 = 10
X=10:25/10
X=4
\(\dfrac{1}{2.4}\)+\(\dfrac{1}{4.6}\)+...+\(\dfrac{1}{x.\left(x+2\right)}\)=\(\dfrac{1}{10}\)
Gọi biểu thức trên là A
Ta có:
2A = (\(\dfrac{1}{2.4}\)+\(\dfrac{1}{4.6}\)+...+\(\dfrac{1}{x.\left(x+2\right)}\)).2
2A = \(\dfrac{2}{2.4}\)+\(\dfrac{2}{4.6}\)+...+\(\dfrac{2}{x\left(x+2\right)}\)
2A = \(\dfrac{1}{2}\)-\(\dfrac{1}{4}\)+\(\dfrac{1}{4}\)-\(\dfrac{1}{6}\)+...+\(\dfrac{1}{x}\)-\(\dfrac{1}{x+2}\)
2A = \(\dfrac{1}{2}\)-\(\dfrac{1}{x+2}\)
mà A = \(\dfrac{1}{10}\)(đề bài)
nên 2A = \(\dfrac{2}{10}\) hay \(\dfrac{1}{2}\) - \(\dfrac{1}{x+2}\) = \(\dfrac{2}{10}\)
suy ra \(\dfrac{1}{x+2}\) = \(\dfrac{1}{2}\)-\(\dfrac{2}{10}\)=\(\dfrac{3}{10}\)
tìm x\(\in\)Z biết
1.-10-|5-x|=-12
2.4.|x-5|-54=-34
3.|x-1|+(-5)=2
4.32-8.|2x-9|=24
5.259-51.|4x+3|=(-10)^2.3+10^1
1) (-10)-|5-x|=(-12)
|5-x|=(-10)-(-12)
|5-x|=2
\(\Rightarrow\left[{}\begin{matrix}5-x=2\\5-x=\left(-2\right)\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=7\end{matrix}\right.\)
Vậy:............
1. 13-(x-5)=8 8. (x-5)^6=(x-5)^8
2. 8-(x-10)=23-(-4+12) 9. (3-x).(x-3)=0
3. 134-5(x+4)=34 10. -32-(x-5)=0
4. |5-x|=7
5. 20+8.(x+3)=5^2.4
6. 42x=39.42-37.42
7. |x|=2-(-7)
bài 5 :tìm x, biết
1.(x-2)2-(x-3)(x+3) = 6 2.4(x-3)2-(2x-1)(2x+1) = 10
3.(x-4)2-(x-2)(x+2) = 6 4.9(x+1)2-(3x-2)(3x+2) = 10
1. ... \(\Leftrightarrow\left(x-2\right)^2-\left(x^2-9\right)=6\Leftrightarrow\left(x-2\right)^2-\left(x\right)^2=-3\Leftrightarrow\left(x-2-x\right)\left(x-2+x\right)=-3\)
\(\Leftrightarrow-2\left(2x-2\right)=-3\Leftrightarrow4x-4=3\Leftrightarrow4x=7\Leftrightarrow x=\frac{7}{4}\)
2. ... \(\Leftrightarrow4\left(x-3\right)^2-\left(4x^2-1\right)=10\Leftrightarrow\left[2\left(x-3\right)\right]^2-\left(2x\right)^2=9\)
\(\Leftrightarrow\left(2x-6-2x\right)\left(2x-6+2x\right)=9\Leftrightarrow-6\left(4x-6\right)=9\Leftrightarrow-24x=-27\Leftrightarrow x=\frac{9}{8}\)
3. ... \(\Leftrightarrow\left(x-4\right)^2-\left(x^2-4\right)=6\Leftrightarrow\left(x-4\right)^2-\left(x\right)^2=2\Leftrightarrow\left(x-4-x\right)\left(x-4+x\right)=2\)
\(\Leftrightarrow-4\left(2x-4\right)=2\Leftrightarrow-8x=-14\Leftrightarrow x=\frac{7}{4}\)
4. ... \(\Leftrightarrow9\left(x+1\right)^2-\left(9x^2-4\right)=10\Leftrightarrow\left[3\left(x+1\right)\right]^2-\left(3x\right)^2=6\)
\(\Leftrightarrow\left(3x+3-3x\right)\left(3x+3+3x\right)=6\Leftrightarrow3\left(6x+3\right)=6\Leftrightarrow6x=-1\Leftrightarrow x=-\frac{1}{6}\)
Ta có : (x - 2)2 - (x - 3) (x + 3) = 6
<=> (x2 - 4x + 4) - (x2 - 32) = 6
=> x2 - 4x + 4 - x2 + 9 = 6
=> -4x + 13 = 6
=> -4x = -7
=> x = \(\frac{7}{4}\)
=>
1/Hãy tính giá trị của biểu thức sau:
a)1500-{5^3.2^3-11.[7^2-5.2^3+8(11^2-129)]}
b)3^2.10^3-[13^2-(5^2.4+2^2.15)].10^3
2/tìm x
a){[2.x+14:2^2-3]:2}-1=0
b)10-{[x:3+17):10+3.2^4]:10}=5
dấu chấm là dấu nhân nha
còn đây ^ là dấu mũ.
mình đang cần gấp ,mong các bạn giải giúp mình.Thank you