A = 6 -2/3 + 1 /2 - 5 -5/3 +3/2 -3 + 7/3 - 5/2 

   = (6 - 5 - 3) - ( 2/3 -5/3 + 7/3 ) + ( 1/2 +3/2 - 5/2)

    = -2 + 0 -1/2 = -5/2

ko hiểu

c) Ta có: \(\dfrac{3}{5}+\dfrac{-5}{20}+\dfrac{30}{75}+\dfrac{-7}{4}\)

\(=\dfrac{3}{5}+\dfrac{2}{5}+\dfrac{-1}{4}+\dfrac{-7}{4}\)

\(=1-2=-1\)

Giải:

a)-1/12+4/3=-1/12+16/12=15/12=5/4

b)(-4/14-3/15)-(1/5-20/35-(-1)).7

=-17/35-22/35.7

=-17/35-22/5

=-171/35

c)3/5+-5/20+30/75+-7/4

=3/5+-1/4+2/5+-7/4

=(3/5+2/5)+(-1/4+-7/4)

=1+-2

=-1

d)5/6.-12/14+7/13

=-5/7+7/13

=-16/91

e)2/-9-5/-36-1/4

=-1/12-1/4

=-1/3

f)2/23+-5/12+7/18+21/23+-7/12

=(2/23+21/23)+(-5/12+-7/12)+7/18

=1+-1+7/18

=7/18

ko xem dc de ban oi :/

2

a) 2011 + 5 . [300- ( 18- 8)2]

= 2011 + 5. ( 300 - 102)

= 2011 + 5. 200

= 3011

b) Số số hạng trong tổng trên là:

( 99 - 1) ; 2 = 1 = 50 (số)

99 + 97 = … = 3 + 1

= ( 99 + 1) . 50 : 2

= 2500

c) Số số hạng trong tổngtrên là:

( 100 - 1) : 3 + 1 = 34 ( số)

100 + 97 + 94 + …+ 4 = 1

= ( 100 + 1) . 34 : 2=1717

d) 99 - 97 + 95 - 93 + … + 3 - 1

= 2 + 2 + 2 + … + 2

= 2. 25

= 50

e) 100 - 97 + 94 - …+ 4 - 1

= 3 + 3 + 3 + … + 3 

= 3. 17 

= 51

`#3107.101107`

\(\left[2^3\cdot97+8\cdot75-\left(-47\right)\cdot2^3\right]\div10^2\)

\(=\left(2^3\cdot97+2^3\cdot75+47\cdot2^3\right)\div10^2\)

\(=\left[2^3\cdot\left(97+75-47\right)\right]\div10^2\)

\(=\left(2^3\cdot125\right)\div10^2\)

\(=\left(2^3\cdot5^3\right)\div10^2\)

\(=\left(5\cdot2\right)^3\div10^2\)

\(=10^3\div10^2\)

\(=10\)

\(\left(2^3.97+8.75-47.2^3\right):10^2\\ =\left[\left(97-47+75\right).2^3\right]:100\\ =\left[125.8\right]:100\\ =1000:100=10\)

a: \(61\cdot45+61\cdot23-68\cdot51\)

\(=61\left(45+23\right)-68\cdot51\)

\(=68\cdot61-68\cdot51\)

\(=68\left(61-51\right)=68\cdot10=680\)

b: \(3\cdot5^2-\left(75-4\cdot2^3\right)\)

\(=75-75+4\cdot8\)

\(=4\cdot8=32\)

c: \(36:\left\{2^2\cdot5-\left[30-\left(5-1\right)^2\right]\right\}\)

\(=\dfrac{36}{20-30+4^2}\)

\(=\dfrac{36}{-10+16}=\dfrac{36}{6}=6\)

d: \(\left(12\cdot49-3\cdot2^2\cdot7^2\right):\left(2020\cdot2021\right)\)

\(=\dfrac{\left(12\cdot49-12\cdot49\right)}{2020\cdot2021}=0\)

a) ta có:99 - 97 + 95 - 93 + 91 - 89 + ... + 7 - 5 + 3 - 1 
= (99 - 97) + (95 - 93) + ... + (7 - 5) + (3 - 1)

= 25.2=50

b)(125.37.32).4

=(125.4).(37.32)

=500.1184

=100.5.1184

=100.5920

=592000

c)A=5+8+11+14+...+302

Số số hạng của A là

(302-5):3+1=100(số)

Tổng A= (302+5).100:2=15350

b)(125.37.32):4

=125.37.32:4

=125.37.8

=125.8.37

=1000.37

=37000

Sorry bạn mk nhìn nhầm dấu

a) 50

b)592000

c)15350

Ko ghi đề

C = (3.2)+(3.4)+(3.6)+...+(3.98)+(3.100)

C = 3 . (2+4+6+...+100)

C = 3 . 2550

C = 7650 

Ko theo công thức nha @@

Nhớ k mk nha ^^

1,  17.( 85+15) -120 = 17. 100 -120 =1700 - 120 =1580

2, 

2³ . 17 - 2³ . 14

= 2³(17-14)

=2³. 3= 24