\(\left(x-1\right)^{43}=\left(x-1\right)^{2021}\)

\(\Rightarrow\left(x-1\right)^{43}\left[\left(x-1\right)^{1978}-1\right]=0\)

\(\Rightarrow\left[{}\begin{matrix}x-1=0\\\left(x-1\right)^{1978}=1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=1\\x=2\\x=0\end{matrix}\right.\)

2x-3=x+\(\frac{1}{2}\)

2x-x=3+\(\frac{1}{2}\)

x=\(3\frac{1}{2}\)

2x - 3 = x + 1/2

2x - x = 3 + 1/2 (chuyển x qua vế kia)

x        = 7/2

Vậy x = 7/2

\(5x\left(x-3\right)^2-5\left(x-1\right)^3+15\left(x+2\right)\left(x-2\right)=5\)

\(\Leftrightarrow5x\left(x^2-6x+9\right)-5\left(x^3-3x^2+3x-1\right)+15\left(x^2-4\right)=5\)

\(\Leftrightarrow5x^3-30x^2+45x-5x^3+15x^2-15x+5+15x^2-60=5\)

\(\Leftrightarrow30x=60\)

\(\Leftrightarrow x=2\)

\(a,A=\left\{0;2;4;6;8\right\}\\ b,B=\left\{1;2;3;4;5;6;7;8\right\}\\ c,C=\left\{0;3;6;9;12;15;18\right\}\)

a, A={0;2;4;6;8}

b, B={1;2;3;4;5;6;7;8}

c, C=0;3;6;9;12;15;18}

a, A={0;2;4;6;8}

b, B={1;2;3;4;5;6;7;8}

c, C=0;3;6;9;12;15;18}

\(a,6\left(x-3\right)=0\\ \Leftrightarrow x-3=0\\ \Leftrightarrow x=3\\ ---\\ b,Thiếu.VP\)

x : y =3

x= 3y

ta co   x+y = -4\5

         3y + y = -4\5

          4y = -4\5

           y = -4\5 :4

           y = -1\5

vay     x = -1\5 *3 = -3\5