1) 1/3 x 1/2 x 3/7 = 3/42 = 1/14

2) 5/4 x 1/3 +1/7 = 5/12 + 1/7 = 35/84 + 12/84 = 47/84

3) 8 x ( 8/9 - 2/3 ) = 8 x 2/9 = 16/9

4) 5/6 x 48/20 x 1/2 = 240/240 = 1

5) ( 2/5 + 3/4 ) + 8 = 23/20 + 8 = 23//20 + 160/20 = 183/20

6) 10 x ( 1/2 - 1/5 ) = 10 x 3/10 = 10/1 x 3/10 = 30/10 = 3

1: \(=\dfrac{1}{3}\cdot\dfrac{3}{7}\cdot\dfrac{1}{2}=\dfrac{1}{7\cdot2}=\dfrac{1}{14}\)

2: =5/12+1/7

=35/84+12/84=47/84

3: =8(8/9-6/9)

=8*2/9=16/9

4: \(=\dfrac{5}{12}\cdot\dfrac{12}{5}=1\)

5: =16/5+6

=16/5+30/5=46/5

6: =10*1/2-10*1/5

=5-2=3

 = ( -2 + 4) + ( -6 +8) + ...+(-18 + 20 ) 

= 2+2+2+2+2

= 10

= [-2 + 4] + [-6+8] + ... +[-18 + 20]

= 2 + 2 + ... + 2 

= 10

 = ( -2 + 4) + ( -6 +8) + ...+(-18 + 20 ) 

=2+2+2+2+2

=10

k mik nhoa

(-2) + 4 + ( -6) + 8 + (-10) + 12 + (-14) + 16 + (-18) + 20

=[(-2) + 12] + [4+(-14)] + [(-6)+16] + [8+(-18)] + [(-10)+20]

=    10        +     (-10)    +    10       +    (-10)    +    10

=(10 +10 +10) + [(-10) + (-10)]

=    30             +      (-20)

=              10

a) 4+2/5=22/5

b) 5/4+2=13/4

c) 3+3/2=9/2

d) 3/4-1/8=5/8

e) 17/15-7/10=13/30

g) 25/12-15/8=5/24

h) 5-4/3=11/3

i)15/4-3=3/4

a)\(\dfrac{4}{1}+\dfrac{2}{5}=\dfrac{20}{5}+\dfrac{2}{5}=\dfrac{22}{5}\)

b)\(\dfrac{5}{4}+\dfrac{2}{1}=\dfrac{5}{4}+\dfrac{8}{4}=\dfrac{13}{4}\)

c)\(\dfrac{3}{1}+\dfrac{3}{2}=\dfrac{6}{2}+\dfrac{3}{2}=\dfrac{9}{2}\)

d)\(\dfrac{3}{4}-\dfrac{1}{8}=\dfrac{6}{8}-\dfrac{1}{8}=\dfrac{5}{8}\)

e)\(\dfrac{17}{15}-\dfrac{7}{10}=\dfrac{34}{30}-\dfrac{21}{30}=\dfrac{13}{30}\)

g)\(\dfrac{25}{12}-\dfrac{15}{8}=\dfrac{50}{24}-\dfrac{45}{24}=\dfrac{5}{24}\)

h)\(\dfrac{5}{1}-\dfrac{4}{3}=\dfrac{15}{3}-\dfrac{4}{3}=\dfrac{11}{3}\)

i)\(\dfrac{15}{4}-\dfrac{3}{1}=\dfrac{15}{4}-\dfrac{12}{4}=\dfrac{3}{4}\)

4/1+2/5= 20/5+2/5= 22/5

5/4+2/1= 5/4+ 8/4= 13/4

3/1+3/2= 6/2+ 3/2= 9/2

6/8- 1/8= 5/8

34/30- 21/30= 13/30

50/24- 45/24= 5/24

5/1- 4/3= 15/3- 4/3= 11/3

15/4- 3/1= 15/4- 12/4= 3/4

\(\left(x+2\right)-2=0\)

\(\Rightarrow x+2-2=0\)

\(\Rightarrow x=0\)

\(\left(x+3\right)+1=7\)

\(\Rightarrow x+3+1=7\)

\(\Rightarrow x+4=7\)

\(\Rightarrow x=3\)

\(\left(3x-4\right)+4=12\)
\(\Rightarrow3x-4+4=12\)

\(\Rightarrow3x=12\)

\(\Rightarrow x=4\)

\(\left(5x+4\right)-1=13\)

\(\Rightarrow5x+4-1=13\)

\(\Rightarrow5x+3=13\)

\(\Rightarrow5x=10\)

\(\Rightarrow x=2\)

\(\left(4x-8\right)-3=5\)

\(\Rightarrow4x-8-3=5\)

\(\Rightarrow4x-11=5\)

\(\Rightarrow4x=16\)

\(\Rightarrow x=4\)

\(8-\left(2x+4\right)=2\)

\(\Rightarrow8-2x-4=2\)

\(\Rightarrow4-2x=2\)

\(\Rightarrow2x=2\)

\(\Rightarrow x=1\)

\(7+\left(5x+2\right)=14\)

\(\Rightarrow7+5x+2=14\)

\(\Rightarrow9+5x=14\)

\(\Rightarrow5x=5\)

\(\Rightarrow x=1\)

\(5-\left(3x-11\right)=1\)

\(\Rightarrow5-3x+11=1\)

\(\Rightarrow16-3x=1\)

\(\Rightarrow3x=15\)

\(\Rightarrow x=5\)

\(\dfrac{-2}{9}\cdot\dfrac{7}{15}+\dfrac{-2}{9}\cdot\dfrac{8}{15}+\dfrac{2}{3^2}\)

\(=-\dfrac{2}{9}\left(\dfrac{7}{15}+\dfrac{8}{15}\right)+\dfrac{2}{9}\)

\(=\dfrac{-2}{9}+\dfrac{2}{9}\)

=0

=>Chọn C

\(=\dfrac{\left(20\cdot16-12\cdot8-48\cdot4\right)^2}{-2^9}=\dfrac{2^{10}}{-2^9}=-2\)