\(2^{x+1}-2^x=3^2\)

\(\Rightarrow2^x\cdot\left(2-1\right)=9\)

\(\Rightarrow2^x=9\)

\(\Rightarrow x\in\varnothing\)

\(2^{x+1}-2^x=3^2\)

=>2^x*2-2^x=9

=>2^x=9

=>\(x\in\varnothing\)

Sửa đề: +2023^2-2024^2

C=(1-2)(1+2)+(3-4)(3+4)+...+(2023-2024)(2023+2024)

=-(1+2+3+4+...+2023+2024)

=-2024*2025/2=-2049300

31¹¹<32¹¹=2⁵⁵

17¹⁴>16¹⁴=2⁵⁶

=>Vì 2⁵⁵<2⁵⁶ nên 31¹¹<17¹⁴.

giúp mik đi ạ đang gấp

x+1<x+2<x+3<x+4 ( với mọi x)

\(\dfrac{1}{100}\) < \(\dfrac{1}{99}\)<\(\dfrac{1}{3}\) <\(\dfrac{1}{2}\)

=>\(\dfrac{x+1}{100}\)+\(\dfrac{x+2}{99}\) <\(\dfrac{x+3}{3}\)+\(\dfrac{x+4}{2}\) là đúng

\(2x^2y-x^3-xy+1+x^3+2xy^2-2\)

\(=\left(-x^3+x^3\right)+\left(1-2\right)+2x^2y-xy+2xy^2\)

\(=0-1+2x^2y-xy+2xy^2\)

\(=2x^2y-xy+2xy^2-1\)

Đăng lại đi bạn bị lỗi rồi

=11/2(-1/5+3/7-4/5+4/7)

=11/2(1-1)

=0

\(\left(\dfrac{-1}{5}+\dfrac{3}{7}\right):\dfrac{2}{11}+\left(\dfrac{-4}{5}+\dfrac{4}{7}\right):\dfrac{2}{11}\) 

\(=\dfrac{8}{35}:\dfrac{2}{11}+\dfrac{-8}{35}:\dfrac{2}{11}\) 

\(=\dfrac{2}{11}:\left(\dfrac{8}{35}+\dfrac{-8}{35}\right)\) 

\(=\dfrac{2}{11}:0=0\)