x+1x2+(x+2x3)+x+(x+3x4)......(x+9x10)
Tìm x:
(x -\(\dfrac{1}{3}\) ) x (\(\dfrac{2}{1x2}\)+ \(\dfrac{2}{2x3}\)+ \(\dfrac{2}{3x4}\) + … + \(\dfrac{2}{9x10}\)) = \(\dfrac{3}{4}\)
\(\Leftrightarrow2\left(x-\dfrac{1}{3}\right)\left(1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+...+\dfrac{1}{9}-\dfrac{1}{10}\right)=\dfrac{3}{4}\)
\(\Leftrightarrow2\left(x-\dfrac{1}{3}\right)\left(1-\dfrac{1}{10}\right)=\dfrac{3}{4}\Leftrightarrow\dfrac{9}{10}\left(x-\dfrac{1}{3}\right)=\dfrac{3}{8}\)
\(\Leftrightarrow x-\dfrac{1}{3}=\dfrac{5}{12}\Leftrightarrow x=\dfrac{5}{12}+\dfrac{1}{3}=\dfrac{9}{12}=\dfrac{3}{4}\)
(1/1x2+1/2x3+1/3x4+........+1/8x9+1/9x10)x100-(5/2:x+(206/100:1/2)
Bài 1. Tính nhanh :
2/1x2 + 2/2x3 + 2/3x4 + ... + 2/18x19 +2/19x20 .
Bài 2. Tìm x trong biểu thức sau :
( 1/1x2 + 1/2x3 + 1/3x4 + ... + 1/8x9 + 1/9x10 ) x 100 - [5/2 : ( x + 206/100 )] :1/2 = 89
CÁC BẠN GIÚP MÌNH NHA !
Bài 1:
Đặt \(A=\frac{2}{1x2}+\frac{2}{2x3}+\frac{2}{3x4}+...+\frac{2}{18x19}+\frac{2}{19x20}\)
\(\frac{A}{2}=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{18x19}+\frac{1}{19x20}\)
\(\frac{A}{2}=\frac{2-1}{1x2}+\frac{3-2}{2x3}+\frac{4-3}{3x4}+...+\frac{19-18}{18x19}+\frac{20-19}{19x20}\)
\(\frac{A}{2}=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{18}-\frac{1}{19}+\frac{1}{19}-\frac{1}{20}=1-\frac{1}{20}=\frac{19}{20}\)
\(A=\frac{2x19}{20}=\frac{19}{10}\)
Bài 2:
Đặt \(B=\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+...+\frac{1}{8x9}+\frac{1}{9x10}\)
Làm tương tự câu 1 có \(B=1-\frac{1}{10}=\frac{9}{10}\)
\(Bx100=\frac{9}{10}x100=90\)
=> \(\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=1\)
=> \(\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]=\frac{1}{2}\)
=> \(x+\frac{206}{100}=\frac{5}{2}:\frac{1}{2}=5\Rightarrow x=5-\frac{206}{100}=\frac{294}{100}=\frac{147}{50}\)
đáp án bài 1 là: 19/10
đáp án bài 2 là 147/50
Tìm x trong biểu thức sau:
\(\left(\frac{1}{1x2}+\frac{1}{2x3}+\frac{1}{3x4}+....+\frac{1}{8x9}+\frac{1}{9x10}\right)x100-\left[\frac{5}{2}:\left(x+\frac{206}{100}\right)\right]:\frac{1}{2}=89\)
x/1x2 +x/2x3 + x/3x4+ .....+x/2017x2018=-1
x= -2018/2017
Bài làm:
Ta có: \(\frac{x}{1.2}+\frac{x}{2.3}+\frac{x}{3.4}+...+\frac{x}{2017.2018}=-1\)
\(\Leftrightarrow x\left(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+...+\frac{1}{2017.2018}\right)=-1\)
\(\Leftrightarrow x\left(1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+...+\frac{1}{2017}-\frac{1}{2018}\right)=-1\)
\(\Leftrightarrow x\left(1-\frac{1}{2018}\right)=-1\)
\(\Leftrightarrow x.\frac{2017}{2018}=-1\)
\(\Rightarrow x=-\frac{2018}{2017}\)
\(\frac{x}{1\cdot2}+\frac{x}{2\cdot3}+\frac{x}{3\cdot4}+...+\frac{x}{2017\cdot2018}=-1\)
=> \(\frac{x}{1}-\frac{x}{2}+\frac{x}{2}-\frac{x}{3}+...+\frac{x}{2017}-\frac{x}{2018}=-1\)
=> \(\frac{x}{1}-\frac{x}{2018}=-1\)
=> \(\frac{2018x-x}{2018}=-1\)
=> \(\frac{2017x}{2018}=-1\)
=> 2017x = -2018
=> x = -2018/2017
1/1x2+1/2x3+1/3x4+.....+1/9x10
1/1 x 2 + 1/2 x 3 + 1/3 x 4 + .... + 1/9 x 10
= 1 - 1/2 + 1/2 - 1/3 +1/3 - 1/4 + ... + 1/9 - 1/10
= 1 - 1/10
= 9/10
\(\dfrac{1}{1\times2}+\dfrac{1}{2\times3}+\dfrac{1}{3\times4}+...+\dfrac{1}{9\times10}\\ =1-\dfrac{1}{2}+\dfrac{1}{2}-\dfrac{1}{3}+\dfrac{1}{3}-\dfrac{1}{4}+...+\dfrac{1}{9}-\dfrac{1}{10}\\ =1-\dfrac{1}{10}\\ =\dfrac{9}{10}\)
1x2+2x3+3x4+...+x(x+1)
giúp mih với
Đề đã đầy đủ chưa bạn? Và bạn đang cần làm gì với biểu thức này?
1/1x2+1/2x3+1/3x4+...+1/9x10
Ta đặt biểu thức là:
A = 1/1 x 2 + 1/2 x 3 + 1/3 x 4 + .... + 1/9 x 10
A = 1 - 1/2 + 1/2 - 1/3 +1/3 - 1/4 + ... + 1/9 - 1/10
A = 1 - 1/10
A = 9/10
\(=1-\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+...+\frac{1}{9}-\frac{1}{10}\)
\(=1-\frac{1}{10}\)
\(=\frac{9}{10}\)
= 1/1 x 2 + 1/2 x 3 + 1/3 x 4 + .... + 1/9 x 10
= 1 - 1/2 + 1/2 - 1/3 +1/3 - 1/4 + ... + 1/9 - 1/10
= 1 - 1/10
= 9/10
tìm X ( 1/1x2 +1/2x3 + .. +1/9x10) x X = 27/10
x là nhân, X là số cần tìm. giúp mình với ạ!
`1/(1 xx2) + 1/(2 xx3) + ...+ 1/(9 xx 10) xx x = 27/10`
`(1- 1/2 + 1/2-1/3+...+ 1/9-1/10) xx x = 27/10`
`(1-1/10) xx x = 27/10`
`9/10 xx x = 27/10`
`x= 27/10 : 9/10`
`x = 27/10 . 10/9`
`x= (27.10)/(10.9)`
`x=27/9 = 3`
Đáp số: x = 3