\(\frac{2^{4-x}}{16^5}=32^6\)

\(\Rightarrow\frac{2^{4-x}}{\left(2^4\right)^5}=\left(2^5\right)^6\)

\(\Rightarrow\frac{2^{4-x}}{2^{20}}=2^{30}\)

\(\Rightarrow2^{4-x}=2^{30}.2^{20}\)

\(\Rightarrow2^{4-x}=2^{50}\)

\(\Rightarrow4-x=50\)

\(\Rightarrow x=-46\)

64 . 4^x = 168

<=> 43. 4^x = 416

=> 3 + x = 16

<=> x = 13

Vậy x = 13

2^x.16² = 1024

<=> 2^x. 2⁸ = 210

=> x + 8 = 10

<=> x = 2

Vậy x = 2

b: Ta có: \(2^x\cdot16^2=1024\)

\(\Leftrightarrow2^x\cdot2^8=2^{10}\)

\(\Leftrightarrow x+8=10\)

hay x=2

  64.4^x=16³

  2⁶. (2²)^x = (2⁴)³

=> 2⁶. 2^2x = 2¹²

        2^2x   = 2 ¹² : 2⁶

       2^2x   = 2⁶

  =>  2x = 6

         x = 6 :2

         x=3

- Vậy x =3

32^x . 16^x = 1024

=> (2⁵)^x . (2⁴)^x = 2¹⁰

=> 2^5x . 2^4x      = 2¹⁰

=> 2^{5x + 4x}        = 2¹⁰

=> 2^9x              = 2¹⁰

=>  9x              = 10

=>    x              = 10 : 9

=>    x              = 10/9

TL:

\(32^x.16^x=1024\) 

\(\left(2^5\right)^x.\left(2^4\right)^x=1024\) 

\(2^{9x}=2^{10}\) 

\(\Rightarrow9x=10\Leftrightarrow x=\frac{10}{9}\) 

Vậy............

\(32^x.16^x=1024\)

\(\left(2^5\right)^x.\left(2^4\right)^x=1024\)

\(2^{9x}=2^{10}\)

\(=>9x=10\)

\(=>x=\frac{10}{9}\)

a: \(x^6+x^4=0\)

\(\Leftrightarrow x^4\left(x^2+1\right)=0\)

=>x=0

b: \(32^{-x}\cdot16^x=1024\)

\(\Leftrightarrow\left(2^5\right)^{-x}\cdot\left(2^4\right)^x=1024\)

\(\Leftrightarrow2^{-5x+4x}=1024\)

\(\Leftrightarrow2^{-x}=1024\)

=>-x=10

hay x=-10(loại do x là số tự nhiên)

Dễ thế mà ko biết làm

a) x=10

b) x=1

2^x.16² = 1024

=> 2^x.(2⁴)² = 2¹⁰

=> 2^{x + 4.2} = 10

=> x + 8 = 10

=> x = 2

vậy_

64.4^x = 16⁸

=> 4³.4^x = (4²)⁸

=> 4^{3 + x} = 4¹⁶

=> 3 + x = 16

=> x = 13

vậy_

2^x = 16

=> 2^x = 2⁴

=> x = 4

vậy_

a)x=-2

b)x=-102

c)x=123

d)x=10

e)x=-48