\(B=1+\dfrac{4x-2022}{3x+y}\)

\(=1+\dfrac{3x+y+x-y-2022}{3x+y}\)

\(=1+1+\dfrac{x-y-2022}{-1\left(x-y\right)+4x}\)

\(=2+\dfrac{2022-2022}{-1\left(2022\right)+4x}\)

\(=2+\dfrac{0}{-2022+4x}=2+0=2\)

Phép liên kết: phép nối

Cụm từ " May mắn thay " đã liên kết 2 câu

h) \(-\dfrac{5}{6}=\dfrac{7+x}{18}\)

   \(\Rightarrow7+x=\dfrac{\left(-5\right).18}{6}\)

  \(\Rightarrow7+x=\left(-15\right)\)

  \(\Rightarrow x=15-7\)

  \(\Rightarrow x=8\)

d) \(\dfrac{5}{-12}=-\dfrac{10}{24};\dfrac{3}{-8}=-\dfrac{9}{24};2=\dfrac{48}{24}\)

Bài 3: 

a: Ta có: \(A=\left(\sqrt{12}+\sqrt{\left(-2\right)^2}-\sqrt{27}\right)\left(2+\sqrt{3}\right)\)

\(=\left(2-\sqrt{3}\right)\left(2+\sqrt{3}\right)\)

=4-3

=1

b: Ta có: \(B=5\sqrt{3}+2-\sqrt{7-4\sqrt{3}}\)

\(=5\sqrt{3}+2-2+\sqrt{3}\)

\(=6\sqrt{3}\)

2: PTHĐGĐ là:

-2x+3=0.5x-2

\(\Leftrightarrow x\cdot\dfrac{-5}{2}=-5\)

\(\Leftrightarrow x=-5:\dfrac{-5}{2}=-5\cdot\dfrac{2}{-5}=2\)

\(\Leftrightarrow y=-2\cdot2+3=-1\)