X - 55 = 20 x 3
tim x :x-20/11*13-20/13*15-...20/53*55=3/11
X - 55 = 20 x 3
x-55=20.3
x-55=60
x=60+55
x=115
vay x=115
X - 55 = 20 x 3
Tìm x thuộc N biết :
x-20/11*13-20/13*15-20/15*17-...-20/53*55=3/11
tìm x là số N:
x - 20/ 11. 13 - 20/13 . 15 - 20/ 15 . 17 -...-20/53 . 55= 3/ 11
Ta có :
\(x-\frac{20}{11.13}-\frac{20}{13.15}-\frac{20}{15.17}-..-\frac{20}{53.55}=\frac{3}{11}\)
\(x-\left(\frac{20}{11.13}+\frac{20}{13.15}+\frac{20}{15.17}+...+\frac{20}{52.55}\right)=\frac{3}{11}\)
Đặt \(A=\frac{20}{11.13}+\frac{20}{13.15}+\frac{20}{15.17}+...+\frac{20}{53.55}\)
\(A=10\left(\frac{2}{11.13}+\frac{2}{13.15}+\frac{2}{15.17}+...+\frac{2}{53.55}\right)\)
\(A=10\left(\frac{1}{11}-\frac{1}{13}+\frac{1}{13}-\frac{1}{15}+\frac{1}{15}-\frac{1}{17}+...+\frac{1}{53}-\frac{1}{55}\right)\)
\(A=10\left(\frac{1}{11}-\frac{1}{55}\right)\)
\(A=10.\frac{4}{55}=\frac{40}{55}=\frac{8}{11}\)
=> \(x-\frac{8}{11}=\frac{3}{11}\)
\(x=\frac{3}{11}+\frac{8}{11}=\frac{11}{11}=1\)
Ủng hộ mk nha !!! ^_^
x-20/11*13-20/13*15-20/15*17-...-20/53*55= 3/11
x-20/11*13-20/13*15-20/15*17-...-20/53*55=3/11
Tim X
a,X - 20/11 x 13 - 20/13 x 15 - 20/15 x 17 -...-20/53 x 55 = 3/11
b,1/21 + 1/28 +1/36 + ... +2/Xx(x + 1) = 2/9
Ta có : A=20/11×13 + 20/13×15 +20/15×17+...+20/53×55
A = 10 ×( 2/11×13+2/13×15+...12/53×55)
A = 10 ×(1/11-1/13+1/13-1/15+1/15-1/17+...+1/53-1/55)
A = 10 × (1/11-1/55)
A =10 × 4/55
A = 8/11
a, 2.x+3.x=57÷55
B, 5.(7.x - 45) = 23 .52 - 32 . 20
`#3107.101107`
a,
`2x + 3x = 5^7 \div 5^5`
$\Rightarrow (2 + 3)x = 5^{7 - 5}$
$\Rightarrow 5x = 5^2$
$\Rightarrow 5x = 25$
$\Rightarrow x = 25 \div 5$
$\Rightarrow x = 5$
Vậy, `x = 5`
b,
`5(7x - 45) = 2^3 . 5^2 - 3^2 . 20`
`\Rightarrow 5(7x - 45) = 8.25 - 9.20`
`\Rightarrow 5(7x - 45) = 40.5 - 36.5`
`\Rightarrow 5(7x - 45) = 5.(40 - 36)`
`\Rightarrow 5(7x - 45) = 5.4`
`\Rightarrow 7x - 45 = 4`
`\Rightarrow 7x = 49`
`\Rightarrow x = 49 \div 7`
`\Rightarrow x = 7`
Vậy, `x = 7.`
A) (2+3).x=5 mũ 2
5.x=5 mũ 2
5.x=25
x=25:5
x=5
vậy x=5
câu B ko bt làm bn ạ