ĐK: ...

c) \(\frac{x+5}{x^2-5x}-\frac{x-5}{2x^2+10x}=\frac{x+25}{2x^2-50}\)

\(\Leftrightarrow\frac{2\left(x+5\right)^2}{2x\left(x-5\right)\left(x+5\right)}-\frac{\left(x-5\right)^2}{2x\left(x+5\right)\left(x-5\right)}=\frac{x\left(x+25\right)}{2x\left(x-5\right)\left(x+5\right)}\)

\(\Leftrightarrow2x^2+20x+50-x^2+10x-25=x^2+25x\)

\(\Leftrightarrow5x+25=0\)

\(\Leftrightarrow x=-5\)( ko t/m )

d) tương tự, ngại tính lắm

e) \(\frac{1}{x-1}-\frac{3x^2}{x^3-1}=\frac{2x}{x^2+x+1}\)

\(\Leftrightarrow\frac{x^2+x+1}{x^3-1}-\frac{3x^2}{x^3-1}=\frac{2x\left(x-1\right)}{x^3-1}\)

\(\Leftrightarrow4x^2-3x-1=0\)

\(\Leftrightarrow\left(x-1\right)\left(4x+1\right)=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\left(l\right)\\x=\frac{-1}{4}\left(c\right)\end{matrix}\right.\)

Bạn nào cho mk 1 ik, mk cho bn ý 3 ik luôn. Mk hứa nếu nói dối bạn có thể Báo cáo sai phạm mk.

a) \(\frac{5-x}{4x^2-8x}\) + \(\frac{7}{8x}\) = \(\frac{x-1}{2x\left(x-2\right)}\) +\(\frac{1}{8x-16}\)                               ĐKXĐ : x #0, x#2, x#-2

<=> \(\frac{5-x}{4x\left(x-2\right)}\) + \(\frac{7}{8x}=\frac{x-1}{2x\left(x-2\right)}\) + \(\frac{1}{8\left(x-2\right)}\)

<=> \(\frac{2\left(5-x\right)}{8x\left(x-2\right)}+\frac{7\left(x-2\right)}{8x\left(x-2\right)}=\frac{4\left(x-1\right)}{8x\left(x-2\right)}+\frac{x}{8x\left(x-2\right)}\)

=> 10 - 2x + 7x - 14 = 4x - 4 + x

<=>-2x + 7x - 4x + x  = -4 - 10 + 14

<=>x=-14

a) \({2^x} > 16 \Leftrightarrow {2^x} > {2^4} \Leftrightarrow x > 4\) (do \(2 > 1\)) .

b) \(0,{1^x} \le 0,001 \Leftrightarrow 0,{1^x} \le 0,{1^3} \Leftrightarrow x \ge 3\) (do \(0 < 0,1 < 1\)).

c) \({\left( {\frac{1}{5}} \right)^{x - 2}} \ge {\left( {\frac{1}{{25}}} \right)^x} \Leftrightarrow {\left( {\frac{1}{5}} \right)^{x - 2}} \ge {\left( {{{\left( {\frac{1}{5}} \right)}^2}} \right)^x} \Leftrightarrow {\left( {\frac{1}{5}} \right)^{x - 2}} \ge {\left( {\frac{1}{5}} \right)^{2x}} \Leftrightarrow x - 2 \le 2{\rm{x}}\) (do \(0 < \frac{1}{5} < 1\))

\( \Leftrightarrow x \ge  - 2\).